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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#284151#2884. 切切糕qyzyq#WA 0ms3988kbC++14802b2023-12-16 11:05:162023-12-16 11:05:17

Judging History

你现在查看的是最新测评结果

  • [2023-12-16 11:05:17]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3988kb
  • [2023-12-16 11:05:16]
  • 提交

answer

#include<bits/stdc++.h>
#define db double
using namespace std;

const int N=2510;
const db eps=1e-12;

int n,m,a[N],suf[N];
db f[N][N];

int main()
{
	scanf("%d%d",&n,&m);
	for(int i=1; i<=n; i++)
		scanf("%d",&a[i]);

	sort(a+1,a+1+n);

	f[0][0]=0;
	for(int i=1; i<=n; i++)
	{
		int cur=n-i+1;
		f[i][0]=(db)a[cur]+f[i-1][0];
		f[i][i]=(db)a[cur]/2.000000+f[i-1][i-1];
		for(int j=1; j<=min(i-1,m); j++)
		{
			if((db)a[i]-(f[i-1][j-1]-f[i-1][j])>=-eps)
				f[i][j]=(f[i-1][j-1]+f[i-1][j]+(db)a[cur])/2.000000;
			else
				f[i][j]=min(f[i-1][j-1],f[i-1][j]+(db)a[cur]);
		}

	}
	// cout<<f[2][2]<<endl;
	db ans=1e9;
	for(int i=0; i<=m; i++)
		/*printf("%.3lf ",f[n][i]),*/ans=min(ans,f[n][i]);
	printf("%.6lf\n",f[n][m]);

	return 0;
}

/*
4 3
4 3 2 1
*/

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3900kb

input:

1 1
10

output:

5.000000

result:

ok found '5.0000000', expected '5.0000000', error '0.0000000'

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 3988kb

input:

10 8
1 2 3 1 2 2 1 3 3 2

output:

10.011719

result:

wrong answer 1st numbers differ - expected: '10.0351562', found: '10.0117190', error = '0.0023355'