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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#279402#5148. Tree DistanceMars_DingdangTL 3ms38392kbC++143.0kb2023-12-08 17:41:532023-12-08 17:41:53

Judging History

你现在查看的是最新测评结果

  • [2023-12-08 17:41:53]
  • 评测
  • 测评结果:TL
  • 用时:3ms
  • 内存:38392kb
  • [2023-12-08 17:41:53]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
#define rep(ii,aa,bb) for(re int ii = aa; ii <= bb; ii++)
#define Rep(ii,aa,bb) for(re int ii = aa; ii >= bb; ii--)
typedef long long ll;
typedef unsigned long long ull;
typedef double db;
typedef pair<int, ll> PII;
const int maxn = 2e5 + 5;
const ll inf = 1ll << 60;
namespace IO_ReadWrite {
	#define re register
	#define gg (p1 == p2 && (p2 = (p1 = _buf) + fread(_buf, 1, 1<<21, stdin), p1 == p2) ? EOF :*p1++)
	char _buf[1<<21], *p1 = _buf, *p2 = _buf;
	template <typename T>
	inline void read(T &x){
		x = 0; re T f=1; re char c = gg;
		while(c > 57 || c < 48){if(c == '-') f = -1;c = gg;}
		while(c >= 48 &&c <= 57){x = (x<<1) + (x<<3) + (c^48);c = gg;}
		x *= f;return;
	}
	inline void ReadChar(char &c){
		c = gg;
		while(!isalpha(c)) c = gg;
	}
	template <typename T>
	inline void write(T x){
		if(x < 0) putchar('-'), x = -x;
		if(x > 9) write(x/10);
		putchar('0' + x % 10);
	}
	template <typename T>
	inline void writeln(T x){write(x); putchar('\n');}
}
using namespace IO_ReadWrite;
int n, sz[maxn], rt, S, f[maxn], dis[maxn];
vector <PII> e[maxn], ds, d[maxn];
bool vis[maxn];
inline void findrt(int u, int fa) {
	sz[u] = 1, f[u] = 0;
	for(auto [v, w] : e[u]) {
		if(v == fa || vis[v]) continue;
		findrt(v, u);
		sz[u] += sz[v];
		f[u] = max(f[u], sz[v]);
	}
	f[u] = max(f[u], S - sz[u]);
	if(f[u] < f[rt]) rt = u;
}
inline void get_dis(int u, int fa) {
	ds.push_back({u, dis[u]});
	for(auto [v, w] : e[u]) {
		if(v == fa || vis[v]) continue;
		dis[v] = dis[u] + w;
		get_dis(v, u);
	}
}
int stk[maxn], top;
inline void calc(int u) {
	dis[u] = 0;
	ds.clear();
	get_dis(u, 0);
	sort(ds.begin(), ds.end());
	top = 0;
	for(auto [v, w] : ds) {
		while(top && w < dis[stk[top]]) top --;
		if(top) d[v].push_back({stk[top], w + dis[stk[top]]});
		stk[++ top] = v;
	}
	top = 0;
	reverse(ds.begin(), ds.end());
	for(auto [v, w] : ds) {
		while(top && w < dis[stk[top]]) top --;
		if(top) d[stk[top]].push_back({v, w + dis[stk[top]]});
		stk[++ top] = v;
	}
}
inline void solve(int u) {
	vis[u] = 1;
	calc(u);
	for(auto [v, w] : e[u]) {
		if(vis[v]) continue;
		S = sz[v], f[rt = 0] = n + 1;
		findrt(v, u);
		solve(rt);
	}
}
vector <PII> qry[1000005];
int q;
ll bit[maxn], ans[maxn];
inline int lowbit(int x) {return x & (-x);}
inline void upd(int x, ll v) {
	for(; x; x -= lowbit(x))
		bit[x] = min(bit[x], v);
}
inline ll qMin(int x) {
	ll res = inf;
	for(; x <= n; x += lowbit(x)) {
		res = min(res, bit[x]);
	}
	return res;
}
int main () {
	read(n);
	fill(bit, bit + n + 2, inf);
	rep(i, 1, n - 1) {
		int u, v, w;
		read(u); read(v); read(w);
		e[u].push_back({v, w});
		e[v].push_back({u, w});
	}
	S = n;
	f[rt = 0] = n + 1;
	findrt(1, 0);
	solve(rt);
	read(q);
	rep(i, 1, q) {
		int l, r;
		read(l); read(r);
		qry[r].push_back({l, i});
	}
	rep(r, 1, n) {
		for(auto [u, w] : d[r]) upd(u, w);
		for(auto [l, id] : qry[r]) {
			if(l == r) ans[id] = -1;
			else ans[id] = qMin(l);
		}
	}
	rep(i, 1, q) writeln(ans[i]);
	
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 3ms
memory: 38392kb

input:

5
1 2 5
1 3 3
1 4 4
3 5 2
5
1 1
1 4
2 4
3 4
2 5

output:

-1
3
7
7
2

result:

ok 5 number(s): "-1 3 7 7 2"

Test #2:

score: -100
Time Limit Exceeded

input:

199999
31581 23211 322548833
176307 196803 690953895
34430 82902 340232856
36716 77480 466375266
7512 88480 197594480
95680 61864 679567992
19572 14126 599247796
188006 110716 817477802
160165 184035 722372640
23173 188594 490365246
54801 56250 304741654
10103 45884 643490340
127469 154479 214399361...

output:


result: