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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#268379#7744. ElevatorXeQuadF#RE 1ms3612kbC++141.9kb2023-11-28 16:53:452023-11-28 16:53:46

Judging History

你现在查看的是最新测评结果

  • [2023-11-28 16:53:46]
  • 评测
  • 测评结果:RE
  • 用时:1ms
  • 内存:3612kb
  • [2023-11-28 16:53:45]
  • 提交

answer

#include<bits/stdc++.h>
#define N 100005
#define LL long long
using namespace std;
#define Ms(a,b) memset(a,b,sizeof a)
#define db(x) cerr<<#x<<"="<<x<<endl;
#define db2(x,y) cerr<<#x<<"="<<x<<" "<<#y<<"="<<y<<endl;
#define db3(x,y,z) cerr<<#x<<"="<<x<<" "<<#y<<"="<<y<<" "<<#z<<"="<<z<<endl;
LL rd(){
    LL res=0,c,f=0;
    while(!isdigit(c=getchar()))f=c=='-';
    do res=(res<<1)+(res<<3)+(c^48);
    while(isdigit(c=getchar()));
    return f?-res:res;
}
int T,n;
LL k;
struct node{
    int c,w,f;
}a[N];
struct cmp{
    bool operator ()(const node &a,const node &b){
        return a.f>b.f;
    }
};
int main(){
    T=rd();
    while(T--){
        n=rd(),k=rd();
        for(int i=1;i<=n;i++){
            a[i].c=rd();
            a[i].w=rd();
            a[i].f=rd();
        }
        sort(a+1,a+1+n,cmp());
        queue<int>q;
        for(int i=1;i<=n;i++)if(a[i].w==1&&(a[i].c&1))q.push(i);
        //for(int i=1;i<=n;i++)db3(a[i].c,a[i].w,a[i].f);
        LL res=0;
        int cur=2;
        for(int i=1;i<=n;i++){
            res+=1ll*a[i].c*a[i].w/k*a[i].f;
            a[i].c%=k/a[i].w;
            if((a[i].c&1)&&a[i].w==1){
                q.pop();
                if(!q.empty()){
                    int x=q.front();q.pop();
                    a[x].c--;
                }
                a[i].c++;
            }
            if(a[i].c){
                LL now = a[i].c*a[i].w;
                cur=max(cur,i+1);
                while(cur<=n&&now<k){
                    while(cur<=n&&a[cur].c==0)++cur;
                    LL add = min(k-now, 1ll*a[cur].c*a[cur].w);
                    now+=add;
                    a[cur].c-=add/a[cur].w;
                }
                res+=a[i].f;
            }
            //db2(i,res);
            //for(int j=1;j<=n;j++)
                //db3(a[j].c,a[j].w,a[j].f);
        }
        printf("%lld\n",res);
    }
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 3612kb

input:

2
4 6
1 1 8
7 2 5
1 1 7
3 2 6
8 1200000
100000 1 100000
100000 1 12345
100000 2 100000
100000 2 12345
100000 1 100000
100000 1 12345
100000 2 100000
100000 2 12345

output:

24
100000

result:

ok 2 lines

Test #2:

score: -100
Runtime Error

input:

5501
8 104
5 2 3
6 2 4
5 2 3
6 2 9
8 2 4
2 1 3
7 2 4
8 2 8
1 290
3 1 1
12 12
6 1 2
1 2 2
1 1 2
1 2 4
6 1 1
1 2 5
6 1 4
4 1 4
6 2 4
6 2 5
4 2 5
4 1 4
5 334
1 1 4
1 2 3
4 2 1
5 1 1
2 1 2
13 218
5 2 3
5 1 4
1 2 1
1 2 5
3 2 2
1 1 3
4 2 2
1 2 5
2 2 1
2 1 5
3 2 1
5 2 1
1 1 4
10 260
7 2 1
5 1 1
5 2 4
6 1 6...

output:


result: