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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#267340#3272. 简单数据结构KHIN#20 0ms0kbC++173.0kb2023-11-27 10:06:362024-07-04 03:08:52

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你现在查看的是最新测评结果

  • [2024-07-04 03:08:52]
  • 评测
  • 测评结果:20
  • 用时:0ms
  • 内存:0kb
  • [2023-11-27 10:06:36]
  • 提交

answer

# include <bits/stdc++.h>

using namespace std;

constexpr long N(200'000);
constexpr long Q(200'000);

typedef pair<long, long> pair;

struct event {
  long op, v, l, r;
};

long n, q;
long a[N + 1];
long s[N + 1];
event e[Q + 1];

vector<long> id1;
long stk[Q], *top(stk);
vector<long> ins[N + 1];
set<long> set;
long cnt[Q + 1];
long prv[Q + 1];
long vl1[Q + 1];
long vl2[Q + 1];
long sum[Q + 1];

vector<::pair> upd[N + 1];
long ans[Q + 1];

inline long clc(long const i, long const x)
{ return e[prv[x]].v + i * (cnt[x] - cnt[prv[x]]); }

inline bool cmp(long const i, long const j, long const k) {
  long const vij(e[j].v - e[i].v), vjk(e[k].v - e[j].v);
  long const cij(cnt[j] - cnt[i]), cjk(cnt[k] - cnt[j]);
  assert(vij > 0), assert(vjk > 0);
  assert(cij > 0), assert(cjk > 0);
  return __int128_t(vij) * cjk >= __int128_t(vjk) * cij;
}

int main() {
  cin >> n >> q;
  for (long i(1); i <= n; ++i) cin >> a[i];
  partial_sum(a + 1, a + n + 1, s + 1);
  for (long i(1); i <= q; ++i) {
    switch (cin >> e[i].op, e[i].op) {
      case 1: cin >> e[i].v; break;
      case 2: break;
      case 3: cin >> e[i].l >> e[i].r; break;
    }
    if (e[i].op == 1) id1.push_back(i);
    cnt[i] = cnt[i - 1] + (e[i].op == 2);
    if (e[i].op == 3) {
      long const l(e[i].l - 1);
      long const r(e[i].r - 0);
      upd[l].emplace_back(i, +1);
      upd[r].emplace_back(i, -1);
      ans[i] += s[r] - s[l];
      ans[i] += (l + r + 1) * (r - l) / 2 * cnt[i];
    }
  }
  if (!id1.empty()) {
    for (long const i : id1) {
      if (top != stk && cnt[i] == cnt[top[-1]] && e[i].v > e[top[-1]].v)
        continue;
      while (top != stk && cnt[top[-1]] == cnt[i]) --top;
      while (top != stk && e[i].v <= e[top[-1]].v) --top;
      while (top - stk > 1 && cmp(top[-2], top[-1], i)) --top;
      if (top == stk) ins[1].push_back(i);
      else {
        long const dv(e[i].v - e[top[-1]].v);
        long const dc(cnt[i] - cnt[top[-1]]);
        ins[dv / dc + 1].push_back(i);
      }
      *top++ = i;
    }
    ::set.insert(0), ::set.insert(q + 1);
    for (long i(id1.front()); i <= q; ++i)
      prv[i] = id1.front();
    for (long i(1); i <= n; ++i) {
      for (long const j : ins[i]) {
        auto const k(::set.insert(j).first);
        auto const dv(e[j].v - e[*prev(k)].v);
        auto const dc(cnt[j] - cnt[*prev(k)]);
        for (long l(j); l != *next(k); ++l)
          prv[l] = j, vl1[l] += dv, vl2[l] += dc;
      }
      long l(-1), r(id1.size());
      while (r - l > 1) {
        long const m((l + r) / 2);
        (a[i] + i * cnt[id1.at(m)] < clc(i, id1.at(m)) ? l : r) = m;
      }
      long const p(r == long(id1.size()) ? q + 1 : id1.at(r));
      for (long j(p); j <= q; ++j) {
        // sum[j] += a[i] + i * cnt[prv[j]] - e[prv[j]].v;
        sum[j] += a[i] - vl1[j] + i * vl2[j];
      }
      for (auto const& j : upd[i]) ans[j.first] += j.second * sum[j.first];
    }
  }
  for (long i(1); i <= q; ++i)
    if (e[i].op == 3)
      cout << ans[i] << '\n';
}

详细

Subtask #1:

score: 0
Runtime Error

Test #1:

score: 0
Runtime Error

input:

5000 5000
29940 259997 53132 912489 608312 594283 432259 344137 889466 383028 320097 337418 571199 372832 563110 542407 133378 998389 238387 120880 477310 634888 191990 133585 935315 558139 141724 893331 190118 991968 843042 384930 935256 891482 123419 91431 955722 376987 197566 106433 234494 645967...

output:


result:


Subtask #2:

score: 20
Accepted

Subtask #3:

score: 0
Runtime Error

Test #1:

score: 0
Runtime Error

input:

5000 5000
29940 259997 53132 912489 608312 594283 432259 344137 889466 383028 320097 337418 571199 372832 563110 542407 133378 998389 238387 120880 477310 634888 191990 133585 935315 558139 141724 893331 190118 991968 843042 384930 935256 891482 123419 91431 955722 376987 197566 106433 234494 645967...

output:


result:


Subtask #4:

score: 0
Skipped

Dependency #1:

0%