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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#252141#7706. Rikka with LinkerSolitaryDream#TL 1ms3428kbC++17946b2023-11-15 15:57:062023-11-15 15:57:07

Judging History

你现在查看的是最新测评结果

  • [2023-11-15 15:57:07]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:3428kb
  • [2023-11-15 15:57:06]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
#define FOR(i,s,t) for(int i=(s),_t=(t); i<=_t; ++i)
const int N=19;
int f[1<<N|5];
int g[N];
void solve() {
    int n,m;
    cin >> n >> m;
    FOR(i,0,n-1) g[i]=0;
    FOR(i,1,m) {
        int x,y;
        cin >> x >> y;
        --x,--y;
        g[x]|=1<<y;
    }
    f[0]=0;
    FOR(i,1,(1<<n)-1) {
        f[i]=1e9;
        FOR(j,0,n-1) if((1<<j)&i) {
            int c=1;
            FOR(k,0,n-1) if(k!=j && ((1<<k)&i) && (g[k]&i)==g[k] && (g[k]&(i^(1<<j)))!=g[k]) {
                ++c;
            }
            // if(i==7) cerr << j << ' ' << ' ' << f[i^(1<<j)] << ' ' << c << endl;
            f[i]=min(f[i],f[i^(1<<j)]+c);
        }
        // cerr << i << " = " << f[i] << endl;
    }
    cout << f[(1<<n)-1] << '\n';
}
int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    int T;
    cin >> T;
    while(T--) solve();
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3428kb

input:

3
3 2
1 2
2 3
3 3
1 2
2 3
3 1
5 7
1 2
2 3
3 5
5 4
4 2
2 5
3 1

output:

3
4
6

result:

ok 3 number(s): "3 4 6"

Test #2:

score: -100
Time Limit Exceeded

input:

1000
18 93
1 6
1 13
2 1
2 8
3 6
4 8
5 4
5 6
5 9
5 10
5 11
5 12
5 13
5 18
6 2
6 4
6 16
7 1
7 2
7 3
7 9
7 10
7 13
7 15
8 6
8 9
9 5
9 8
9 10
9 13
9 14
10 1
10 3
10 4
10 5
10 6
10 8
10 11
10 13
11 1
11 2
11 3
11 4
11 6
11 7
11 9
11 12
11 14
11 15
12 1
12 2
12 4
12 6
12 10
12 13
12 14
12 16
12 17
12 18
1...

output:


result: