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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#250332#7627. Phonyucup-team1516WA 1ms3440kbC++177.4kb2023-11-13 04:02:502023-11-13 04:02:50

Judging History

你现在查看的是最新测评结果

  • [2023-11-13 04:02:50]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3440kb
  • [2023-11-13 04:02:50]
  • 提交

answer

#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
using namespace std;
typedef long long int ll;
typedef unsigned long long int ull;

mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
ll myRand(ll B) {
    return (ull)rng() % B;
}
inline double time() {
    return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;
}

// 0-indexed
template<typename T>
struct BIT{
    int n;
    vector<T> bit,ary;
    BIT(int n = 0) : n(n),bit(n+1),ary(n) {}
    T operator[](int k) {
        return ary[k];
    }
    // [0, i)
    T sum(int i) {
        T res = 0;
        for (; i > 0; i -= (i&-i)) {
            res += bit[i];
        }
        return res;
    }
    // [l, r)
    T sum(int l, int r) {
        return sum(r) - sum(l);
    }
    void add(int i, T a) {
        ary[i] += a;
        i++;
        for (; i <= n; i += (i&-i)) {
            bit[i] += a;
        }
    }
    int lower_bound(T k) { // k <= sum(res)
        if (k <= 0) return 0;
        int res = 0, i = 1;
        while ((i << 1) <= n) i <<= 1;
        for (; i ; i >>= 1) {
            if (res+i <= n and bit[res+i] < k) {
                k -= bit[res += i];
            }
        }
        return res;
    }

    // The 2nd UC Stage 9: Qinhuangdao - I
    // 円環状で見たときに bit[i]+bit[i-1]+...+bit[j] を求める
    // i=j のときは 0 を返すようにしました
    T sum_cyc(int i, int j) {
        if (i == j) return 0;
        else if (j < i) return sum(j, i+1);
        else return sum(0, i+1) + sum(j+1, n);
    }
    // The 2nd UC Stage 9: Qinhuangdao - I
    // 円環状で見たときに bit[i]+bit[i-1]+...+bit[j] >= k となる最近の j と左辺の総和を求める
    // 雑にlog2つ
    pair<int, T> lower_bound_cyc(int j, T k) {
        T prefix = sum(j+1);
        if (prefix < k) {
            k -= prefix;
            int l = 0, r = n;
            while (r-l > 1) {
                int mid = (l+r)/2;
                T s = sum(mid, n);
                if (s >= k) {
                    l = mid;
                }
                else {
                    r = mid;
                }
            }
            return {l, prefix+sum(l,n)};
        }
        else {
            int l = 0, r = j+1;
            while (r-l > 1) {
                int mid = (l+r)/2;
                T s = sum(mid, j+1);
                if (s >= k) {
                    l = mid;
                }
                else {
                    r = mid;
                }
            }
            return {l, sum(l, j+1)};
        }
    }
};

int main(){
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    int n,q; cin >> n >> q;
    ll K; cin >> K;
    vector<ll> a(n);
    for (int i = 0; i < n; ++i) {
        cin >> a[i];
    }
    sort(a.rbegin(), a.rend());
    vector<ll> z(n);
    for (int i = 0; i < n; ++i) {
        z[i] = a[i]%K;
    }
    sort(z.begin(), z.end());
    z.erase(unique(z.begin(), z.end()), z.end());
    int m = z.size();

    int sz = 0;
    BIT<int> bit(m);
    auto add = [&](int i) -> void {
        sz += 1;
        bit.add(i, 1);
    };

    vector<int> md(n);
    for (int i = 0; i < n; ++i) {
        md[i] = lower_bound(z.begin(), z.end(), a[i]%K) - z.begin();
        if (a[0]-a[i] < K) {
            add(md[i]);
        }
    }

    int pos = md[0];
    int cnt = 0;
    ll mx = a[0];
    __int128 nx = 0;

    auto bitsum = [&](int s, int t) -> int {
        if (t <= s) {
            return bit.sum(t, s+1);
        }
        else {
            return sz-bit.sum(s+1, t);
        }
    };

    auto calNext = [&]() -> void {
        if (sz >= n) {
            return;
        }
        else {
            ll dif = z[pos]-z[md[sz]];
            if (dif < 0) dif += K;
            nx = bitsum(pos, md[sz])-cnt;
            nx = bit.sum_cyc(pos, md[sz]) - cnt;

            ll uo = mx-dif;
            nx += (__int128)(uo-a[sz]-K)/K*(__int128)sz;
        }
    };

    calNext();

    auto debug = [&]() -> void {
//        cout << "debug" << endl;
//        for (int i = 0; i < query.size(); ++i) {
//            cout << query[i].first << " " << query[i].second << endl;
//        }
//        cout << "A" << endl;
//        for (int i = 0; i < 18; ++i) {
//            cout << a[i] << " ";
//        }
//        cout << endl;
        for (int i = 0; i < m; ++i) {
            cout << bit[i] << " ";
        }
        cout << endl;
        cout << "pos = " << pos << endl;
        cout << "cnt = " << cnt << endl;
        cout << "mx  = " << mx << endl;
        cout << "nx  = " << (ll)nx << endl;
    };

    while (q--) {
        char c; cin >> c;
        ll in; cin >> in;
        if (c == 'A') {
            int x = in;
            ll res;
            if (sz < x) {
                res = a[x-1];
            }
            else {
                // 最大値との差分を返すように
                auto findKth = [&](int i, int k, int cnt) -> ll {
                    if (bit[i]-cnt >= k) return 0;
                    if (sz-cnt < k) return K;

                    k += cnt;
                    auto p = bit.lower_bound_cyc(i, k);
                    ll dif = z[i]-z[p.first];
                    if (dif < 0) dif += K;
                    return dif;
                };
                ll dif = findKth(pos, x, cnt);
                res = mx-dif;
            }
            cout << res << "\n";
        }
        else {
            auto update = [&]() -> void {
                if (pos) {
                    mx -= z[pos]-z[pos-1];
                    pos -= 1;
                    cnt = 0;
                }
                else {
                    mx -= z[0]-z[m-1]+K;
                    pos = m-1;
                    cnt = 0;
                }
            };

            ll t = in;
            while (sz < n and t >= nx) {
                t -= nx;
                mx = a[sz]+K;
                pos = md[sz];
                ll cp = a[sz];
                while (sz < n and a[sz] == cp) {
                    add(md[sz]);
                }
                update();
                calNext();
            }

            ll u = t/sz;
            mx -= u*K;
            t -= u*sz;
            nx -= t;

            if (bit[pos]-cnt >= t) {
                cnt += t;
            }
            else {
                t -= (bit[pos]-cnt);
                update();
//                debug();

                if (bit.sum(pos+1) <= t) {
                    t -= bit.sum(pos+1);
                    mx -= z[pos]-z.back()+K;
                    pos = m-1;
                    cnt = 0;
                }

                // (r,pos]は全消し可能
                int l = -1, r = pos;
                while (r-l > 1) {
                    int mid = (l+r)/2;
                    if (bit.sum(mid+1,pos+1) <= t) {
                        r = mid;
                    }
                    else {
                        l = mid;
                    }
                }
                t -= bit.sum(r+1,pos+1);
                mx -= z[pos]-z[r];
                pos = r;
                cnt = 0;
                assert(bit[pos] >= t);
                cnt = t;
            }

//            debug();
        }
    }
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3424kb

input:

3 5 5
7 3 9
A 3
C 1
A 2
C 2
A 3

output:

3
4
-1

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 1ms
memory: 3440kb

input:

5 8 8
294 928 293 392 719
A 4
C 200
A 5
C 10
A 2
C 120
A 1
A 3

output:

294
200
191
0
-2

result:

ok 5 lines

Test #3:

score: -100
Wrong Answer
time: 1ms
memory: 3436kb

input:

100 100 233
5101 8001 6561 6329 6305 7745 4321 811 49 1121 3953 8054 8415 9876 6701 4097 6817 6081 495 5521 2389 2042 4721 8119 7441 7840 8001 5756 5561 129 1 5981 4801 7201 8465 7251 6945 5201 5626 3361 5741 3650 7901 2513 8637 3841 5621 9377 101 3661 5105 4241 5137 7501 5561 3581 4901 561 8721 811...

output:

6881
9161
4721
8200
2945
7647
7531
5291
5001
2042
4721
4721
6881
4097
7187
7218
7035
7018
811
6742
2561
6675
6103
6135
3581
5291
1485
5949
5388
2042
5303
5167
5203
4721
5080
4029
4097
4586
4809
4578
4698
2042
4530
4449
4591
4412
3581
4335
115
2042
4273
2042
4273
1485
4318
-17559

result:

wrong answer 20th lines differ - expected: '6752', found: '6742'