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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#250332 | #7627. Phony | ucup-team1516 | WA | 1ms | 3440kb | C++17 | 7.4kb | 2023-11-13 04:02:50 | 2023-11-13 04:02:50 |
Judging History
answer
#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
using namespace std;
typedef long long int ll;
typedef unsigned long long int ull;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
ll myRand(ll B) {
return (ull)rng() % B;
}
inline double time() {
return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;
}
// 0-indexed
template<typename T>
struct BIT{
int n;
vector<T> bit,ary;
BIT(int n = 0) : n(n),bit(n+1),ary(n) {}
T operator[](int k) {
return ary[k];
}
// [0, i)
T sum(int i) {
T res = 0;
for (; i > 0; i -= (i&-i)) {
res += bit[i];
}
return res;
}
// [l, r)
T sum(int l, int r) {
return sum(r) - sum(l);
}
void add(int i, T a) {
ary[i] += a;
i++;
for (; i <= n; i += (i&-i)) {
bit[i] += a;
}
}
int lower_bound(T k) { // k <= sum(res)
if (k <= 0) return 0;
int res = 0, i = 1;
while ((i << 1) <= n) i <<= 1;
for (; i ; i >>= 1) {
if (res+i <= n and bit[res+i] < k) {
k -= bit[res += i];
}
}
return res;
}
// The 2nd UC Stage 9: Qinhuangdao - I
// 円環状で見たときに bit[i]+bit[i-1]+...+bit[j] を求める
// i=j のときは 0 を返すようにしました
T sum_cyc(int i, int j) {
if (i == j) return 0;
else if (j < i) return sum(j, i+1);
else return sum(0, i+1) + sum(j+1, n);
}
// The 2nd UC Stage 9: Qinhuangdao - I
// 円環状で見たときに bit[i]+bit[i-1]+...+bit[j] >= k となる最近の j と左辺の総和を求める
// 雑にlog2つ
pair<int, T> lower_bound_cyc(int j, T k) {
T prefix = sum(j+1);
if (prefix < k) {
k -= prefix;
int l = 0, r = n;
while (r-l > 1) {
int mid = (l+r)/2;
T s = sum(mid, n);
if (s >= k) {
l = mid;
}
else {
r = mid;
}
}
return {l, prefix+sum(l,n)};
}
else {
int l = 0, r = j+1;
while (r-l > 1) {
int mid = (l+r)/2;
T s = sum(mid, j+1);
if (s >= k) {
l = mid;
}
else {
r = mid;
}
}
return {l, sum(l, j+1)};
}
}
};
int main(){
cin.tie(nullptr);
ios::sync_with_stdio(false);
int n,q; cin >> n >> q;
ll K; cin >> K;
vector<ll> a(n);
for (int i = 0; i < n; ++i) {
cin >> a[i];
}
sort(a.rbegin(), a.rend());
vector<ll> z(n);
for (int i = 0; i < n; ++i) {
z[i] = a[i]%K;
}
sort(z.begin(), z.end());
z.erase(unique(z.begin(), z.end()), z.end());
int m = z.size();
int sz = 0;
BIT<int> bit(m);
auto add = [&](int i) -> void {
sz += 1;
bit.add(i, 1);
};
vector<int> md(n);
for (int i = 0; i < n; ++i) {
md[i] = lower_bound(z.begin(), z.end(), a[i]%K) - z.begin();
if (a[0]-a[i] < K) {
add(md[i]);
}
}
int pos = md[0];
int cnt = 0;
ll mx = a[0];
__int128 nx = 0;
auto bitsum = [&](int s, int t) -> int {
if (t <= s) {
return bit.sum(t, s+1);
}
else {
return sz-bit.sum(s+1, t);
}
};
auto calNext = [&]() -> void {
if (sz >= n) {
return;
}
else {
ll dif = z[pos]-z[md[sz]];
if (dif < 0) dif += K;
nx = bitsum(pos, md[sz])-cnt;
nx = bit.sum_cyc(pos, md[sz]) - cnt;
ll uo = mx-dif;
nx += (__int128)(uo-a[sz]-K)/K*(__int128)sz;
}
};
calNext();
auto debug = [&]() -> void {
// cout << "debug" << endl;
// for (int i = 0; i < query.size(); ++i) {
// cout << query[i].first << " " << query[i].second << endl;
// }
// cout << "A" << endl;
// for (int i = 0; i < 18; ++i) {
// cout << a[i] << " ";
// }
// cout << endl;
for (int i = 0; i < m; ++i) {
cout << bit[i] << " ";
}
cout << endl;
cout << "pos = " << pos << endl;
cout << "cnt = " << cnt << endl;
cout << "mx = " << mx << endl;
cout << "nx = " << (ll)nx << endl;
};
while (q--) {
char c; cin >> c;
ll in; cin >> in;
if (c == 'A') {
int x = in;
ll res;
if (sz < x) {
res = a[x-1];
}
else {
// 最大値との差分を返すように
auto findKth = [&](int i, int k, int cnt) -> ll {
if (bit[i]-cnt >= k) return 0;
if (sz-cnt < k) return K;
k += cnt;
auto p = bit.lower_bound_cyc(i, k);
ll dif = z[i]-z[p.first];
if (dif < 0) dif += K;
return dif;
};
ll dif = findKth(pos, x, cnt);
res = mx-dif;
}
cout << res << "\n";
}
else {
auto update = [&]() -> void {
if (pos) {
mx -= z[pos]-z[pos-1];
pos -= 1;
cnt = 0;
}
else {
mx -= z[0]-z[m-1]+K;
pos = m-1;
cnt = 0;
}
};
ll t = in;
while (sz < n and t >= nx) {
t -= nx;
mx = a[sz]+K;
pos = md[sz];
ll cp = a[sz];
while (sz < n and a[sz] == cp) {
add(md[sz]);
}
update();
calNext();
}
ll u = t/sz;
mx -= u*K;
t -= u*sz;
nx -= t;
if (bit[pos]-cnt >= t) {
cnt += t;
}
else {
t -= (bit[pos]-cnt);
update();
// debug();
if (bit.sum(pos+1) <= t) {
t -= bit.sum(pos+1);
mx -= z[pos]-z.back()+K;
pos = m-1;
cnt = 0;
}
// (r,pos]は全消し可能
int l = -1, r = pos;
while (r-l > 1) {
int mid = (l+r)/2;
if (bit.sum(mid+1,pos+1) <= t) {
r = mid;
}
else {
l = mid;
}
}
t -= bit.sum(r+1,pos+1);
mx -= z[pos]-z[r];
pos = r;
cnt = 0;
assert(bit[pos] >= t);
cnt = t;
}
// debug();
}
}
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3424kb
input:
3 5 5 7 3 9 A 3 C 1 A 2 C 2 A 3
output:
3 4 -1
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 1ms
memory: 3440kb
input:
5 8 8 294 928 293 392 719 A 4 C 200 A 5 C 10 A 2 C 120 A 1 A 3
output:
294 200 191 0 -2
result:
ok 5 lines
Test #3:
score: -100
Wrong Answer
time: 1ms
memory: 3436kb
input:
100 100 233 5101 8001 6561 6329 6305 7745 4321 811 49 1121 3953 8054 8415 9876 6701 4097 6817 6081 495 5521 2389 2042 4721 8119 7441 7840 8001 5756 5561 129 1 5981 4801 7201 8465 7251 6945 5201 5626 3361 5741 3650 7901 2513 8637 3841 5621 9377 101 3661 5105 4241 5137 7501 5561 3581 4901 561 8721 811...
output:
6881 9161 4721 8200 2945 7647 7531 5291 5001 2042 4721 4721 6881 4097 7187 7218 7035 7018 811 6742 2561 6675 6103 6135 3581 5291 1485 5949 5388 2042 5303 5167 5203 4721 5080 4029 4097 4586 4809 4578 4698 2042 4530 4449 4591 4412 3581 4335 115 2042 4273 2042 4273 1485 4318 -17559
result:
wrong answer 20th lines differ - expected: '6752', found: '6742'