QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#24716#1877. Matryoshka Dollszzy0922WA 21ms16140kbC++2.7kb2022-04-02 15:36:152022-04-30 06:31:11

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-04-30 06:31:11]
  • 评测
  • 测评结果:WA
  • 用时:21ms
  • 内存:16140kb
  • [2022-04-02 15:36:15]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

#define getchar() (p1 == p2 && (p2 = (p1 = buf) + fread(buf, 1, 1<<21, stdin), p1 == p2) ? EOF : *p1++)
char buf[1 << 21],*p1 = buf,*p2 = buf;
inline int read()
{
    char c = getchar();
    int x = 0;
    bool f = 0;
    for(;!isdigit(c); c = getchar()) f ^= !(c ^ 45);
    for(;isdigit(c); c = getchar()) x = (x << 1) + (x << 3) + (c ^ 48);
    if (f) x = -x; 
    return x;
}

int n, m, a[500005], b[500005], pos[500005];
long long anslist[500005];
int len;
struct query{
    int l, r, idx;
    bool operator<(query a) {
        if (l / len == a.l / len) return r > a.r;
        else return l / len < a.l / len; 
    }
}q[500005];

struct node {
    int val, next, prev;
}lis[500005];
#define head lis[0]
#define tail lis[n + 1]
long long ans, tmp, now;

void del(int p, long long& x) {
    if (lis[p].prev == 0) x -= abs(p - lis[p].next);
    else if (lis[p].next == n + 1) x -= abs(p - lis[p].prev);
    else if (lis[p].prev == 0 && lis[p].next == n + 1) x = 0;
    else x = x - abs(p - lis[p].prev) - abs(p - lis[p].next) + abs(lis[p].next - lis[p].prev);
    lis[lis[p].prev].next = lis[p].next;
    lis[lis[p].next].prev = lis[p].prev;
}

void rcv(int p) {
    lis[lis[p].prev].next = p;
    lis[lis[p].next].prev = p;
}

int main() {
    scanf("%d%d", &n, &m);
    len = n;
    for (int i = 1; i <= n; i++)
        scanf("%d", &a[i]);
    for (int i = 1; i <= n; i++)
        lis[i].val = a[i];
    for (int i = 1; i <= n; i++)
        pos[a[i]] = i;
    memcpy(b, a, sizeof a);
    sort(b + 1, b + n + 1);
    for (int i = 1; i < n; i++) {
        ans += abs(pos[b[i]] - pos[b[i + 1]]);
    }
    head.next = pos[b[1]];
    lis[pos[b[1]]].prev = 0;
    for (int i = 1; i < n; i++) {
        lis[pos[b[i]]].next = pos[b[i + 1]];
        lis[pos[b[i + 1]]].prev = pos[b[i]];
    }
    tail.prev = pos[b[n]];
    lis[pos[b[n]]].next = n + 1;
    for (int i = 1; i <= m; i++)
        scanf("%d%d", &q[i].l, &q[i].r);
    for (int i = 1; i <= m; i++)
        q[i].idx = i;
    sort (q + 1, q + m + 1);
    now = ans;
    //cout << ans;
    for (int i = 1, l = 1, r = n; i <= m; i++) {
        // if (q[i].l / len != q[i - 1].l /len) {
        //     while (l < (q[i].l - 1) / len * len + 1) del(l++, now);
        //     r = n;
        //     tmp = ans = now;
        // }
        l = 1, r = n;
        ans = now;
        while (r > q[i].r) del(r--, ans);
        tmp = ans;
        while (l < q[i].l) del(l++, ans/*tmp*/);
        anslist[q[i].idx] = ans/*tmp*/;
        while (l > (q[i].l - 1) / len * len + 1) rcv(l--);
    }
    for (int i = 1; i <= m; i++) printf("%lld\n", anslist[i]);
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 16080kb

input:

5 5
1 5 2 4 3
1 5
1 4
1 3
1 2
1 1

output:

7
5
3
1
0

result:

ok 5 number(s): "7 5 3 1 0"

Test #2:

score: 0
Accepted
time: 2ms
memory: 16140kb

input:

1 1
1
1 1

output:

0

result:

ok 1 number(s): "0"

Test #3:

score: 0
Accepted
time: 21ms
memory: 15192kb

input:

100000 1
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 96 98 100 102 104 106 108 110 112 114 116 118 120 122 124 126 128 130 132 134 136 138 140 142 144 146 148 150 152 154 156 158 160 162 164 166 168 170 172 ...

output:

4999950000

result:

ok 1 number(s): "4999950000"

Test #4:

score: 0
Accepted
time: 3ms
memory: 16080kb

input:

20 1
12 8 13 10 18 14 1 19 5 16 15 9 17 20 6 2 11 4 3 7
9 18

output:

36

result:

ok 1 number(s): "36"

Test #5:

score: -100
Wrong Answer
time: 2ms
memory: 13884kb

input:

20 10
5 16 11 7 19 8 12 13 17 18 6 1 14 3 4 2 15 20 10 9
7 11
7 13
7 17
11 15
1 7
4 6
1 5
6 14
3 5
9 9

output:

7
16
34
9
37
3
25
22
3
0

result:

wrong answer 5th numbers differ - expected: '20', found: '37'