QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#240768 | #7108. Couleur | pandapythoner# | AC ✓ | 1804ms | 35968kb | C++23 | 3.4kb | 2023-11-05 18:36:45 | 2023-11-05 18:36:45 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define flt double
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define sz(s) (int)(s).size()
vector<int> l, r, t;
int new_node(int sm, int l1, int r1) {
int rs = sz(t);
t.emplace_back(sm);
l.emplace_back(l1);
r.emplace_back(r1);
return rs;
}
int add(int v, int tl, int tr, int pos) {
if (tl > pos || tr <= pos) return v;
int nv = new_node(t[v] + 1, l[v], r[v]);
if (tl + 1 == tr) return nv;
int tm = (tr - tl) / 2 + tl;
if (l[nv] == -1) l[nv] = new_node(0, -1, -1);
if (r[nv] == -1) r[nv] = new_node(0, -1, -1);
l[nv] = add(l[nv], tl, tm, pos);
r[nv] = add(r[nv], tm, tr, pos);
return nv;
}
ll get(int v, int tl, int tr, int ql, int qr) {
if (v == -1 || tl >= qr || tr <= ql) return 0;
if (tl >= ql && tr <= qr) return t[v];
int tm = (tr - tl) / 2 + tl;
return get(l[v], tl, tm, ql, qr) + get(r[v], tm, tr, ql, qr);
}
struct seg {
int l, r;
ll rs;
bool operator<(const seg& o) const {
return r < o.r;
}
seg(int l, int r, ll rs) : l(l), r(r), rs(rs) {}
};
void solve() {
t.clear(), l.clear(), r.clear();
int n;
cin >> n;
vector<int> a(n);
vector<ll> p(n);
for (int& el : a) {
cin >> el;
--el;
}
for (ll& el : p) cin >> el;
vector<int> root(n + 1);
root[0] = new_node(0, -1, -1);
vector<vector<int>> b(n);
for (int i = 0; i < n; ++i) {
b[a[i]].emplace_back(i);
}
ll sm0 = 0;
for (int i = 0; i < n; ++i) {
root[i + 1] = root[i];
for (auto j : b[i]) {
root[i + 1] = add(root[i + 1], 0, n, j);
sm0 += get(root[i], 0, n, j + 1, n);
}
}
set<seg> s;
s.emplace(0, n, sm0);
multiset<ll> cur_rs{sm0};
ll lst = sm0;
for (int i = 0; i < n; ++i) {
lst = *cur_rs.rbegin();
cout << lst << " \n"[i == n - 1];
int pos = (int)(p[i] ^ lst);
--pos;
auto it = s.upper_bound(seg{-1, pos, -1});
auto [ql, qr, rs] = *it;
s.erase(it);
cur_rs.erase(cur_rs.find(rs));
ll lres = 0, rres = 0;
if (pos - ql <= qr - pos - 1) {
rres = rs;
for (int j = ql; j <= pos; ++j) {
if (j < pos) {
lres += get(root[a[j]], 0, n, j + 1, pos);
}
rres -= get(root[a[j]], 0, n, j + 1, qr);
}
} else {
lres = rs;
for (int j = qr - 1; j >= pos; --j) {
if (j > pos) {
rres += (j - pos - 1) - get(root[a[j] + 1], 0, n, pos + 1, j);
}
lres -= (j - ql) - get(root[a[j] + 1], 0, n, ql, j);
}
}
if (ql < pos) {
s.emplace(ql, pos, lres);
cur_rs.insert(lres);
}
if (pos + 1 < qr) {
s.emplace(pos + 1, qr, rres);
cur_rs.insert(rres);
}
}
}
int32_t main() {
if (1) {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
#ifdef LOCAL
freopen("../input.txt", "r", stdin);
freopen("../output.txt", "w", stdout);
#endif
t.reserve(1e6);
l.reserve(1e6);
r.reserve(1e6);
int tt;
cin >> tt;
while (tt--) solve();
return 0;
}
这程序好像有点Bug,我给组数据试试?
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3616kb
input:
3 5 4 3 1 1 1 5 4 5 3 1 10 9 7 1 4 7 8 5 7 4 8 21 8 15 5 9 2 4 5 10 6 15 4 8 8 1 12 1 10 14 7 14 2 9 13 10 3 37 19 23 15 7 2 10 15 2 13 4 5 8 7 10
output:
7 0 0 0 0 20 11 7 2 0 0 0 0 0 0 42 31 21 14 14 4 1 1 1 0 0 0 0 0 0
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 1804ms
memory: 35968kb
input:
11116 10 10 5 10 3 6 4 8 5 9 8 31 27 24 11 12 3 0 2 3 1 10 8 2 7 2 8 10 1 10 9 10 6 5 2 13 2 1 0 1 3 1 10 7 10 7 6 1 3 10 6 7 9 21 18 10 1 6 5 4 8 9 10 10 2 10 4 8 8 5 7 2 6 7 20 10 9 1 15 0 4 2 9 7 10 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 10 1 2 3 4 5 6 7 8 9 10 6 3 5 2 7 10 9 1 4 8 10 1 10 1 3...
output:
21 18 16 12 10 6 4 1 1 0 12 12 10 10 4 4 4 2 1 0 20 16 9 5 3 3 3 0 0 0 22 14 8 8 5 5 2 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 19 12 7 4 4 2 2 1 0 0 20 18 8 3 1 1 0 0 0 0 45 21 21 10 3 3 3 0 0 0 17 11 8 2 1 1 1 0 0 0 13 4 1 0 0 0 0 0 0 0 29 27 22 15 9 7 4 3 1 0 26 16 9 2 1 1 1 1 1 0 0 0 0 0 0 ...
result:
ok 11116 lines
Extra Test:
score: 0
Extra Test Passed