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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#235293#6644. Red Black Gridjzh#RE 0ms3620kbC++203.4kb2023-11-02 17:00:132023-11-02 17:00:13

Judging History

你现在查看的是最新测评结果

  • [2023-11-02 17:00:13]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:3620kb
  • [2023-11-02 17:00:13]
  • 提交

answer

#include<bits/stdc++.h>

using namespace std;
typedef long long ll;
typedef pair<int, int> pii;

int cal(int mask) {
    int cnt = 0;
    for (int i = 0; i < 9; i++) {
        for (int j = 0; j < 9; j++) {
            if (abs(i % 3 - j % 3) + abs(i / 3 - j / 3) == 1) {
                cnt += (((mask >> i) & 1) ^ (1 & (mask >> j))) != 0;
            }
        }
    }
    return cnt / 2;
}

void show(int ret) {
    for (int i = 0; i < 3; i++) {
        for (int j = 0; j < 3; j++) {
            int id = 3 * i + j;
            cout << (((ret >> id) & 1) ? 'R' : 'B');
        }
        cout << "\n";
    }
}

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    int t;
    cin >> t;

    unordered_map<int, int> ans;
    for (int msk = 0; msk < (1 << 9); msk++) {
        ans[cal(msk)] = msk;
    }

    while (t--) {
        ll n, k;
        cin >> n >> k;
        if (k == 1 || 2LL * n * (n - 1) - k == 1) {
            cout << "Impossible\n";
            continue;
        }
        if (n == 2) {
            if (k == 4) {
                cout << "Possible\n";
                cout << "RB\n";
                cout << "BR\n";
            } else if (k == 2) {
                cout << "Possible\n";
                cout << "RB\n";
                cout << "RR\n";
            }
            continue;
        }
        if (n == 3) {
            auto ret = ans[k];
            cout << "Possible\n";
            show(ret);
            continue;
        }
        vector<vector<int>> block(n, vector<int>(n));
        vector<pair<ll, pii>> op;
        vector<pair<ll, pii>> op3;
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                if ((i + j) % 2 == 0) {
                    block[i][j] = 1;
                    int cnt = 4;
                    if (i == 0 || i == n - 1)cnt--;
                    if (j == 0 || j == n - 1)cnt--;
                    op.push_back({cnt, {i, j}});
                }
            }
        }
        for (int i = 0; i < op.size(); i++) {
            if (op[i].first == 2) {
                swap(op[0], op[1]);
            }
        }
        for (int i = 0; i < op.size(); i++) {
            if (op[i].first == 3) {
                swap(op[1], op[i]);
            }
        }
        for (int i = 0; i < op.size(); i++) {
            if (op[i].first == 4) {
                swap(op[2], op[i]);
            }
        }

        ll num = 2LL * n * (n - 1) - k;
        ll fir = 9;
        vector<int> from(num + 20, -1);
        from[2] = 0, from[3] = 1, from[4] = 2;
        from[5] = 1, from[7] = 1, from[9] = 1;
        from[6] = 2;
        for (int i = 3; i < op.size(); i++) {
            auto [cnt, pos] = op[i];
            for (int j = fir + cnt; j >= fir - 1; j--) {
                if (from[j - cnt] == -1 || j == fir)continue;
                from[j] = i;
            }
            fir += cnt;
        }
        while (num > 0) {
            auto [cnt, pos] = op[from[num]];
            num -= cnt;
            block[pos.first][pos.second] = 0;
        }
        assert(num == 0);
        cout << "Possible\n";
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                cout << (block[i][j] ? 'R' : 'B');
            }
            cout << "\n";
        }

    }
    return 0;
}


詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3620kb

input:

2
3 6
3 1

output:

Possible
RBR
BRR
RRR
Impossible

result:

ok correct! (2 test cases)

Test #2:

score: -100
Runtime Error

input:

4424
1 0
2 4
2 3
2 2
2 1
2 0
3 12
3 11
3 10
3 9
3 8
3 7
3 6
3 5
3 4
3 3
3 2
3 1
3 0
4 24
4 23
4 22
4 21
4 20
4 19
4 18
4 17
4 16
4 15
4 14
4 13
4 12
4 11
4 10
4 9
4 8
4 7
4 6
4 5
4 4
4 3
4 2
4 1
4 0
5 40
5 39
5 38
5 37
5 36
5 35
5 34
5 33
5 32
5 31
5 30
5 29
5 28
5 27
5 26
5 25
5 24
5 23
5 22
5 21
5...

output:


result: