QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#233270#6620. Linear Fractional Transformationextreme1228#WA 203ms3992kbC++202.4kb2023-10-31 15:54:192023-10-31 15:54:20

Judging History

你现在查看的是最新测评结果

  • [2023-10-31 15:54:20]
  • 评测
  • 测评结果:WA
  • 用时:203ms
  • 内存:3992kb
  • [2023-10-31 15:54:19]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;

typedef long long ll;

struct com{
    double x,y;  
    friend com operator +(const com&a,const com&b){
        com c;
        c.x = a.x + b.x;
        c.y = a.y + b.y;
        return c;
    }
    friend com operator -(const com&a,const com&b){
        com c;
        c.x = a.x - b.x;
        c.y = a.y - b.y;
        return c;
    }
    friend com operator *(const com&a,const com&b){
        com c;
        c.x = a.x*b.x - a.y*b.y;
        c.y = a.y*b.x + a.x*b.y;
        return c;
    }
    friend com operator /(const com&a,const com&b){
        com c;
        c.x = (a.x*b.x + a.y*b.y)/(b.x*b.x + b.y*b.y);
        c.y = (-a.x*b.y+a.y*b.x)/(b.x*b.x + b.y*b.y);
        return c;
    }
    
    friend bool operator ==(const com&a,const com&b){
        return fabs(a.x-b.x)<1e-7 && fabs(a.y-b.y)<1e-7; 
    }
    
};



void solve()
{
    com z1,z2,z3,w1,w2,w3,z0,w0;
    cin>>z1.x>>z1.y>>w1.x>>w1.y;
    cin>>z2.x>>z2.y>>w2.x>>w2.y;
    cin>>z3.x>>z3.y>>w3.x>>w3.y;
    cin>>z0.x>>z0.y;
    
    com a,b,c,d;

    //d=0 c!=0  ->  c=1  // (az+b)/z 此时不能有z为0

    a = (w1*z1 - w2*z2)/(z1-z2);
    b = w1*z1 - a*z1;

        
    if((a*z3 + b)/z3== w3){
        w0 = (a*z0+b)/z0;
        cout<<w0.x<< " "<<w0.y<<"\n";
        return;
    }
    

    //d!=0 -> d=1
    d.x=1;d.y=0;
    
    //c=0
    a = (w1-w2)/(z1-z2);
    b = w1-a*z1;
    if((a*z3 + b) == w3){
        w0 = a*z0+b;
        
        cout<<w0.x<< " "<<w0.y<<"\n";
        return;
    }

    //c!=0

    //a=0
    c = (w2 - w1)/(w1*z1 -w2*z2);
    b = w1*(c*z1+d);

    if( b/(c*z3+d) == w3){
        w0 = b/(c*z0 + d);
        cout<<w0.x<< " "<<w0.y<<"\n";
        return;
    }    
    

    //a!=0

    a =((w3 - w1)*(w1*z1 - w2*z2) - (w2 - w1)*(w1*z1 - w3*z3) ) / ((z1 -z2)*(w1*z1 - w3*z3) - (z1 - z3)*(w1*z1 - w2*z2));
    c = (a*(z1-z2) + w2 - w1)/(w1*z1 - w2*z2);
    b = w1*(c*z1+d)- a*z1;

    w0 = (a*z0 + b)/(c*z0 + d);
    cout<<w0.x<<" "<<w0.y<<"\n";

}




int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    int t = 1;
    cin>>t;

    cout<<fixed<<setprecision(15);

    while(t--){
        solve();
    }
    return 0;
}


/*

2
-1 0 0 -1
0 1 -1 0
1 0 0 1
0 -1
-1 0 -1 0
0 1 0 -1
1 0 1 0
0 -1




*/

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3992kb

input:

2
-1 0 0 -1
0 1 -1 0
1 0 0 1
0 -1
-1 0 -1 0
0 1 0 -1
1 0 1 0
0 -1

output:

1.000000000000000 0.000000000000000
0.000000000000000 1.000000000000000

result:

ok 4 numbers

Test #2:

score: -100
Wrong Answer
time: 203ms
memory: 3944kb

input:

100000
0 0 -1 1
1 1 1 0
1 0 1 -1
-1 0
-1 -1 -1 1
1 -1 1 -1
-1 0 1 0
-1 -1
-1 -1 0 -1
-1 1 -1 -1
0 -1 0 0
1 1
1 0 0 -1
0 0 0 0
-1 -1 1 0
1 1
-1 -1 0 -1
0 1 1 -1
1 0 -1 -1
1 -1
0 1 1 -1
1 0 1 0
0 -1 0 1
-1 -1
1 1 -1 1
0 0 -1 -1
0 1 0 1
1 0
1 1 1 -1
0 1 -1 -1
1 0 -1 0
1 -1
1 0 -1 1
-1 -1 1 0
0 -1 0 1
0...

output:

1.000000000000000 1.666666666666667
-1.000000000000000 1.000000000000000
-1.500000000000000 -0.500000000000000
0.333333333333333 -0.666666666666667
-0.384615384615385 -0.923076923076923
-1.000000000000000 0.000000000000000
-1.500000000000000 0.500000000000000
-0.853658536585366 -0.317073170731707
-1...

result:

wrong output format Expected double, but "-nan" found