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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#229561#5143. Quick Sortwhsyhyyh#WA 27ms7932kbC++141.9kb2023-10-28 16:26:162023-10-28 16:26:17

Judging History

你现在查看的是最新测评结果

  • [2023-10-28 16:26:17]
  • 评测
  • 测评结果:WA
  • 用时:27ms
  • 内存:7932kb
  • [2023-10-28 16:26:16]
  • 提交

answer

#include<bits/stdc++.h>
#define N 500010
#define rep(i,l,r) for(int i=l;i<=r;i++)
using namespace std;
int rd() {
	int res=0,f=1;char ch=getchar();
	while(ch<'0'||ch>'9') {if(ch=='-') f*=-1;ch=getchar();}
	while(ch>='0'&&ch<='9') res=(res<<1)+(res<<3)+(ch^48),ch=getchar();	
	return res*f;
}
int Tim,n,a[N];
struct Seg {
	int mn[N<<2],mx[N<<2];
	void update(int p) {
		mn[p]=min(mn[p<<1],mn[p<<1|1]);
		mx[p]=max(mx[p<<1],mx[p<<1|1]);
	}
	void build(int p,int l,int r) {
		if(l==r) {mn[p]=mx[p]=a[l];return ;}
		int mid=l+r>>1;
		build(p<<1,l,mid),build(p<<1|1,mid+1,r);
		update(p);
	}
	void modify(int p,int l,int r,int x) {
		if(l==r) {mn[p]=mx[p]=a[x];return ;}
		int mid=l+r>>1;
		if(x<=mid) modify(p<<1,l,mid,x);
		else modify(p<<1|1,mid+1,r,x);
		update(p);
	}
	int findl(int p,int l,int r,int L,int R,int v) {
		if(mx[p]<v) return -1;
		if(l==r) return l;
		int mid=l+r>>1;
		if(R<=mid) return findl(p<<1,l,mid,L,R,v);
		if(L>mid) return findl(p<<1|1,mid+1,r,L,R,v);
		int tmp=findl(p<<1,l,mid,L,R,v);
		if(tmp!=-1) return tmp;
		return findl(p<<1|1,mid+1,r,L,R,v);
	}
	int findr(int p,int l,int r,int L,int R,int v) {
		if(mn[p]>v) return -1;
		if(l==r) return l;
		int mid=l+r>>1;
		if(R<=mid) return findr(p<<1,l,mid,L,R,v);
		if(L>mid) return findr(p<<1|1,mid+1,r,L,R,v);
		int tmp=findr(p<<1|1,mid+1,r,L,R,v);
		if(tmp!=-1) return tmp;
		return findr(p<<1,l,mid,L,R,v);
	}
}T;
int ans;
void solve(int l,int r) {
	if(l==r) return ;
	int p=l+r>>1;
	int L=l,R=r,A,B;
	while(L!=p||R!=p) {
		A=L!=p?T.findl(1,1,n,L,p,a[p]):p;
		B=R!=p?T.findr(1,1,n,p,R,a[p]):p;
		L=A,R=B;
		if(L==R) break;
		if(p==L) p=R;
		else if(p==R) p=L;
		swap(a[L],a[R]),T.modify(1,1,n,L),T.modify(1,1,n,R),ans++;
	}
	solve(l,p);
	if(p<r) solve(p+1,r);
}
int main() {
	Tim=rd();
	while(Tim--) {
		n=rd();
		rep(i,1,n) a[i]=rd();
		T.build(1,1,n);
		ans=0,solve(1,n);
		printf("%d\n",ans);
	}
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 7932kb

input:

3
3
3 2 1
5
2 4 5 3 1
10
7 2 4 6 1 9 10 8 5 3

output:

1
4
7

result:

ok 3 number(s): "1 4 7"

Test #2:

score: 0
Accepted
time: 17ms
memory: 7916kb

input:

100000
4
3 4 2 1
5
5 4 1 3 2
4
3 1 4 2
4
4 2 1 3
4
1 3 2 4
4
4 2 3 1
4
3 2 1 4
5
1 2 3 4 5
5
5 2 3 1 4
5
1 3 5 4 2
5
4 3 2 1 5
5
3 4 2 1 5
5
5 4 3 2 1
4
3 4 2 1
5
4 2 5 1 3
5
4 1 5 2 3
4
3 4 1 2
4
2 1 3 4
5
4 3 2 5 1
4
4 2 1 3
5
3 1 5 2 4
4
4 1 2 3
5
1 5 2 4 3
5
4 1 3 5 2
5
4 2 3 5 1
5
1 2 3 4 5
5
4...

output:

3
4
3
2
1
1
1
0
2
2
2
3
2
3
2
3
2
1
3
2
4
3
2
3
2
0
4
2
4
1
3
2
3
2
2
1
3
1
1
2
4
3
2
3
1
1
1
3
3
3
4
4
2
3
3
2
3
3
3
2
1
1
2
3
1
3
1
1
3
4
2
2
4
1
1
3
2
2
2
2
1
3
4
4
3
4
2
2
1
3
2
3
2
3
3
2
1
4
2
3
4
1
2
2
3
2
2
3
2
2
2
2
4
1
2
3
2
2
2
2
3
2
3
4
3
2
3
4
2
4
1
3
2
3
4
3
3
4
1
2
4
3
2
4
2
3
3
1
2
2
...

result:

ok 100000 numbers

Test #3:

score: -100
Wrong Answer
time: 27ms
memory: 7852kb

input:

50000
10
3 1 2 10 6 8 5 4 7 9
10
8 3 9 2 10 4 5 1 7 6
9
6 8 4 9 5 7 1 3 2
9
6 7 9 3 8 5 2 1 4
10
7 10 1 2 6 5 3 9 4 8
10
1 10 4 3 2 9 7 8 5 6
9
1 5 3 4 9 6 7 2 8
10
4 7 2 8 3 6 9 5 10 1
9
6 4 9 1 8 5 2 3 7
10
5 1 7 8 10 3 9 6 2 4
9
4 8 6 3 9 7 5 2 1
9
9 1 7 6 2 3 8 5 4
10
5 7 2 1 4 3 6 8 9 10
10
9 7...

output:

8
8
8
8
9
5
3
8
8
9
7
8
7
9
8
11
6
8
8
7
7
11
7
6
11
8
3
6
8
6
6
7
10
4
8
6
6
8
5
6
7
6
7
5
5
8
9
5
9
10
6
7
8
9
4
9
6
7
8
8
9
7
5
7
6
6
10
9
8
6
4
8
6
10
4
9
9
6
9
6
7
7
7
9
6
6
9
8
7
9
9
5
6
8
8
8
8
8
6
4
8
8
5
8
8
8
9
8
8
7
8
7
6
10
9
5
7
7
6
5
5
6
8
9
5
6
7
8
6
7
9
6
7
9
7
7
6
8
9
9
7
7
9
7
8
6
...

result:

wrong answer 11th numbers differ - expected: '9', found: '7'