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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#227318#6801. BlackjackjzhWA 6ms11748kbC++231.2kb2023-10-27 12:11:002023-10-27 12:11:01

Judging History

你现在查看的是最新测评结果

  • [2023-10-27 12:11:01]
  • 评测
  • 测评结果:WA
  • 用时:6ms
  • 内存:11748kb
  • [2023-10-27 12:11:00]
  • 提交

answer

#pragma GCC optimize(3,"Ofast","inline")
#pragma GCC target("avx2","sse2","fma")
#include<bits/stdc++.h>

using namespace std;

using db = __float128;

const int maxn = 505;
db dp[maxn][maxn], ndp[maxn][maxn];
int vec[maxn];

void solve() {
	int n, a, b; cin >> n >> a >> b;
	for(int i = 1 ; i <= n ; i ++) cin >> vec[i];

	dp[0][0] = 1;

	for(int i = 1 ; i <= n ; i ++) {
		memset(ndp, 0, sizeof(ndp));
		for(int x = 0 ; x < i ; x ++) {
			for(int y = 0 ; y <= b ; y ++) {
				ndp[x][y] += dp[x][y];
			}
			for(int y = 0 ; y <= b-vec[i] ; y ++) {
				ndp[x+1][y + vec[i]] += dp[x][y] * (x+1) / (n-x);
			}
		}
		memcpy(dp, ndp, sizeof(ndp));
	}

	db ans = 0;
	for(int i = 1 ; i <= n ; i ++) {
		memcpy(ndp, dp, sizeof(dp));
		for(int x = 0 ; x < n ; x ++) {
			for(int y = 0 ; y <= b-vec[i] ; y ++) {
				ndp[x+1][y+vec[i]] -= ndp[x][y] * (x+1) / (n-x);
			}
		}
		for(int x = 0 ; x <= n-1 ; x ++) {
			for(int y = max(0, a-vec[i]) ; y <= min(a, b-vec[i]) ; y ++) {
				ans += ndp[x][y] / (n-x);
			}
		}
	}
	cout << fixed << setprecision(50) << (long double)ans << endl;
}

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	solve();

	return 0;
}

詳細信息

Test #1:

score: 0
Wrong Answer
time: 6ms
memory: 11748kb

input:

5 2 4
1 1 1 5 5

output:

0.40000000000000000000542101086242752217003726400435

result:

wrong answer 1st numbers differ - expected: '0.1000000', found: '0.4000000', error = '0.3000000'