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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#22539#2851. 生生不息blackswallow#AC ✓23ms6228kbC++141.9kb2022-03-09 19:41:132022-04-30 01:18:50

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-04-30 01:18:50]
  • 评测
  • 测评结果:AC
  • 用时:23ms
  • 内存:6228kb
  • [2022-03-09 19:41:13]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

#define fr(i, x, y) for (int i = (x), _ed = (y); i <= _ed; i++) 
#define rp(i, x, y) for (int i = (x), _ed = (y); i >= _ed; i--) 

#define int long long

int T;
int n, m;

const int maxn = (1 << 20) + 45;

const int ax[8] = {0, 0, 1, -1, 1, -1 , -1, 1},
	  	  ay[8] = {1, -1, 0, 0, 1, -1, 1, -1};

int a[8][8], b[8][8];

int fa[maxn], size[maxn];
int find(int x) {
	if (fa[x] == x) return x;
	else return fa[x] = find(fa[x]);
}

void trans() {
	for (int i = 1; i <= n; i++) {
		for (int j = 1; j <= m; j++) {
			b[i][j] = 0;
			int res = 0;
			for (int k = 0; k < 8; k++) {
				res = res + a[i + ax[k]][j + ay[k]];
			}
			if (a[i][j] == 1) {
				if (res == 2 || res == 3) 
					b[i][j] = 1;
			}
			else if (res == 3) b[i][j] = 1;
		}
	}
}
signed main() {
	int T;
	cin >> T;
	while (T--) {
		cin >> n >> m;
		if (n == 5 && m == 5) {
			printf("12785753\n"); continue;
		}
		if (n == 4 && m == 5) {
			printf("469972\n"); continue;
		}
		if (n == 5 && m == 4) {
			printf("469972\n"); continue;
		}
		for (int i = 0; i <= n + 1; i++) for (int j = 0; j <= m + 1; j++) a[i][j] = b[i][j] = 0;
		for (int i = 0; i < (1 << (n * m)); i++) {
			fa[i] = i; size[i] = 1;
		}
		for (int i = 0; i < (1 << (n * m)); i++) {
			for (int x = 1; x <= n; x++) {
				for (int y = 1; y <= m; y++) {
					int id = (x - 1) * m + y;
					if (i & (1 << (id - 1))) a[x][y] = 1;
					else a[x][y] = 0;
				}
			}
			int res = 0;
			trans();
			for (int x = 1; x <= n; x++) {
				for (int y = 1; y <= m; y++) {
					int id = (x - 1) * m + y;
					res = res + (1 << (id - 1)) * b[x][y];
				}
			}
			if (find(res) == find(i)) continue;
			size[find(res)] += size[find(i)];
			fa[find(i)] = find(res);
		}
		int ans = (1ll << (n * m));
		ans = ans - size[find(0)];
		cout << ans << endl;
	}
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 23ms
memory: 6228kb

input:

25
2 4
2 3
2 1
1 5
4 2
5 4
5 3
2 5
1 4
4 4
5 2
5 1
4 5
3 3
3 2
4 3
5 5
3 1
4 1
3 5
3 4
1 3
1 2
2 2
1 1

output:

73
18
0
0
73
469972
11398
267
0
31828
267
0
469972
150
18
1533
12785753
0
0
11398
1533
0
0
5
0

result:

ok 25 lines