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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#219381#5037. 回文chenxinyang20060 4776ms70080kbC++1414.7kb2023-10-19 13:58:102023-10-19 13:58:11

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  • [2023-10-19 13:58:11]
  • 评测
  • 测评结果:0
  • 用时:4776ms
  • 内存:70080kb
  • [2023-10-19 13:58:10]
  • 提交

answer

#include <bits/stdc++.h>
#define rep(i,j,k) for(int i=(j);i<=(k);i++)
#define per(i,j,k) for(int i=(j);i>=(k);i--)
#define uint unsigned int
#define ll long long
#define ull unsigned long long
#define db double
#define ldb long double
#define pii pair<int,int>
#define pll pair<ll,ll>
#define mkp make_pair
#define eb emplace_back
#define SZ(S) (int)S.size()
#define mod 998244853
//#define mod 1000000007
#define inf 0x3f3f3f3f
#define linf 0x3f3f3f3f3f3f3f3f
using namespace std;

template <class T>
void chkmax(T &x,T y){
	if(x < y) x = y;
}

template <class T>
void chkmin(T &x,T y){
	if(x > y) x = y;
}

inline int popcnt(int x){
	return __builtin_popcount(x);
}

inline int ctz(int x){
	return __builtin_ctz(x);
}

template <int P>
class mod_int
{
    using Z = mod_int;

private:
    static int mo(int x) { return x < 0 ? x + P : x; }

public:
    int x;
    int val() const { return x; }
    mod_int() : x(0) {}
    template <class T>
    mod_int(const T &x_) : x(x_ >= 0 && x_ < P ? static_cast<int>(x_) : mo(static_cast<int>(x_ % P))) {}
    bool operator==(const Z &rhs) const { return x == rhs.x; }
    bool operator!=(const Z &rhs) const { return x != rhs.x; }
    Z operator-() const { return Z(x ? P - x : 0); }
    Z pow(long long k) const
    {
        Z res = 1, t = *this;
        while (k)
        {
            if (k & 1)
                res *= t;
            if (k >>= 1)
                t *= t;
        }
        return res;
    }
    Z &operator++()
    {
        x < P - 1 ? ++x : x = 0;
        return *this;
    }
    Z &operator--()
    {
        x ? --x : x = P - 1;
        return *this;
    }
    Z operator++(int)
    {
        Z ret = x;
        x < P - 1 ? ++x : x = 0;
        return ret;
    }
    Z operator--(int)
    {
        Z ret = x;
        x ? --x : x = P - 1;
        return ret;
    }
    Z inv() const { return pow(P - 2); }
    Z &operator+=(const Z &rhs)
    {
        (x += rhs.x) >= P && (x -= P);
        return *this;
    }
    Z &operator-=(const Z &rhs)
    {
        (x -= rhs.x) < 0 && (x += P);
        return *this;
    }
    Z operator-()
    {
        return -x;
    }
    Z &operator*=(const Z &rhs)
    {
        x = 1ULL * x * rhs.x % P;
        return *this;
    }
    Z &operator/=(const Z &rhs) { return *this *= rhs.inv(); }
#define setO(T, o)                                  \
    friend T operator o(const Z &lhs, const Z &rhs) \
    {                                               \
        Z res = lhs;                                \
        return res o## = rhs;                       \
    }
    setO(Z, +) setO(Z, -) setO(Z, *) setO(Z, /)
#undef setO
    
    friend istream& operator>>(istream& is, mod_int& x)
    {
        long long tmp;
        is >> tmp;
        x = tmp;
        return is;
    }
    friend ostream& operator<<(ostream& os, const mod_int& x)
    {
        os << x.val();
        return os;
    }
};

using Z = mod_int<mod>;
Z power(Z p,ll k){
    Z ans = 1;
    while(k){
        if(k % 2 == 1) ans *= p;
        p *= p;
        k /= 2;
    }
    return ans;
}

ull seed = 'x' + 'a' + 'y' + 't' + 'x' + 'd' + 'y';
ull rnd(){
	seed = seed * 1145141 + 1011451423;
	return seed;
}

int n,Q;
char s[200005];
ull P[2][200005];
Z eP[2][200005];

#define base 127
#define ibase 9150747060186627967llu

const int B = 447;
inline int from(int x){return (x + B - 1) / B;}
inline int L(int x){return x * B - B + 1;}
inline int R(int x){return x * B;}
ull val[2][300005],tag[2][550];
Z eval[2][300005],etag[2][550];
void init(){
	rep(i,1,n) val[0][i] = val[0][i - 1] + P[0][i] * s[i];
	rep(i,1,n) val[1][i] = val[1][i - 1] + P[0][i] * s[n + 1 - i];

	rep(i,1,n) eval[0][i] = eval[0][i - 1] + eP[0][i] * s[i];
	rep(i,1,n) eval[1][i] = eval[1][i - 1] + eP[0][i] * s[n + 1 - i];
}

void upd(int op,int pos,ull C){
	int fp = from(pos);
	rep(k,pos,R(fp)) val[op][k] += C;
	rep(k,fp + 1,from(n)) tag[op][k] += C;
}

ull qry(int op,int pos){
	return val[op][pos] + tag[op][from(pos)];
}

//
void eupd(int op,int pos,Z C){
	int fp = from(pos);
	rep(k,pos,R(fp)) eval[op][k] += C;
	rep(k,fp + 1,from(n)) etag[op][k] += C;	
}

Z eqry(int op,int pos){
	return eval[op][pos] + etag[op][from(pos)];	
}
//

void mdf(int pos,int C){
	upd(0,pos,P[0][pos] * C);
	upd(1,n - pos + 1,P[0][n - pos + 1] * C);

	eupd(0,pos,eP[0][pos] * C);
	eupd(1,n - pos + 1,eP[0][n - pos + 1] * C);
}

int rev;//rev 表示查询的都是反信息
int curL,curR;
ull _getval(int l,int r){
	return (qry(0,r) - qry(0,l - 1)) * P[1][l];
}

ull _getvalrev(int l,int r){
	l = n - l + 1;r = n - r + 1;
	swap(l,r);
	return (qry(1,r) - qry(1,l - 1)) * P[1][l];
}

//
Z _egetval(int l,int r){
	return (eqry(0,r) - eqry(0,l - 1)) * eP[1][l];	
}

Z _egetvalrev(int l,int r){
	l = n - l + 1;r = n - r + 1;
	swap(l,r);
	return (eqry(1,r) - eqry(1,l - 1)) * eP[1][l];	
}
//

int check(int l,int r){
	if(l < curL || r > curR) return 0;
	if(rev){
		l = n - l + 1;r = n - r + 1;
		swap(l,r);
	}
	return (_getval(l,r) == _getvalrev(l,r)) && (_egetval(l,r) == _egetvalrev(l,r));
}

ull getval(int l,int r){
	if(l < curL || r > curR) return rnd();

	if(rev) return _getvalrev(n - r + 1,n - l + 1);
	return _getval(l,r);
}

ull getvalrev(int l,int r){
	if(l < curL || r > curR) return rnd();

	if(rev) return _getval(n - r + 1,n - l + 1);
	return _getvalrev(l,r);
}

ull getval2(int l,int d){
	return getval(l,l + d - 1);
}

ull getvalrev2(int r,int d){
	return getvalrev(r - d + 1,r);
}

Z egetval(int l,int r){
	if(l < curL || r > curR) return rnd();

	if(rev) return _egetvalrev(n - r + 1,n - l + 1);
	return _egetval(l,r);
}

Z egetvalrev(int l,int r){
	if(l < curL || r > curR) return rnd();

	if(rev) return _egetval(n - r + 1,n - l + 1);
	return _egetvalrev(l,r);
}

Z egetval2(int l,int d){
	return egetval(l,l + d - 1);
}

Z egetvalrev2(int r,int d){
	return egetvalrev(r - d + 1,r);
}

int check2(int l,int r){//拓展到右端点 curR
	return check(l + r - curR,curR);
}

struct info{
	int l,r,d;
};

struct node{
	vector <info> pre,suf;//维护所有起始终止点
	int l,r;
}tree[530005];
#define ls (rt * 2)
#define rs (rt * 2 + 1)

int __frp;
int m;
info tmp[205];
void maintain(vector <info> &S){
	m = 0;
	if(__frp){
		cerr << "before maintain\n";
		for(info I:S) cerr << I.l << " " << I.r << " " << I.d << endl;
	}


	for(info I:S){
		if(I.l == I.r) I.d = 0;
		if(!m){
			tmp[++m] = I;
			continue;
		}
		if(!tmp[m].d || tmp[m].d == tmp[m].l - I.r){
			tmp[m].d = tmp[m].l - I.r;
			tmp[m].l = I.r;
			if(I.d) I.r -= I.d;
			else continue;
			if(I.l == I.r) I.d = 0;
		}else{
			tmp[++m] = I;
			continue;
		}
//		cerr << "tm\n";
//		cerr << I.l << " " << I.r << " " << I.d << endl;
		if(tmp[m].l - I.r == tmp[m].d){
			tmp[m].l = I.l;
			continue;
		}else{
			tmp[++m] = I;
		}
	}
	S.clear();
	rep(i,1,m) S.eb(tmp[i]);

	if(__frp){
		cerr << "result:\n";
		rep(i,1,m) cerr << tmp[i].l << " " << tmp[i].r << " " << tmp[i].d << endl;		
	}

}

vector <info> answer;
void mrg(node &p,node &q){
	assert(p.r + 1 == q.l);
	if(__frp){
		cerr << '[' << p.l << "," << p.r << "] [" << q.l << "," << q.r << "]\n";
		cerr << "psuf\n";
		for(info I:p.suf) cerr << I.l << " " << I.r << " " << I.d << endl;
		cerr << "qpre\n";
		for(info I:q.pre) cerr << I.l << " " << I.r << " " << I.d << endl;
		cerr << "qsuf\n";
		for(info I:q.suf) cerr << I.l << " " << I.r << " " << I.d << endl;		
	}


	answer = q.suf;
	info cur = answer.back();
	if(cur.l == q.l){
		if(cur.l == cur.r){
			answer.pop_back();
		}else{
			cur.l += cur.d;
			answer.pop_back();
			answer.eb(cur);
		}
	}

	curL = p.l;curR = q.r;
	int pl,pr,k,pos;
	reverse(q.pre.begin(),q.pre.end());
	for(info I:q.pre){
		if(I.l == I.r){
			pl = q.l - (q.r - I.l);
			pr = q.r;
//			if(__frp) cerr << "check range" << pl << " " << pr << endl;
			if(check(pl,pr)) answer.push_back({pl,pl,0});
			continue;
		}
		k = (I.r - I.l) / I.d;
		pl = I.r + 1;pr = q.r;
		if(pr - pl + 1 <= I.d && getval(I.l + 1,I.l + 1 + pr - pl) == getval(pl,pr) && egetval(I.l + 1,I.l + 1 + pr - pl) == egetval(pl,pr)){//[pl,pr] 是 [I.l + 1,I.l + I.d] 的前缀
			pos = 0;
//			if(__frp) cerr << p.r << " " << I.l + 1 << endl;
			per(_k,__lg(k),0) if(pos + (1 << _k) <= k && getvalrev2(p.r,(pos + (1 << _k)) * I.d) == getval2(I.l + 1,(pos + (1 << _k)) * I.d) && egetvalrev2(p.r,(pos + (1 << _k)) * I.d) == egetval2(I.l + 1,(pos + (1 << _k)) * I.d)) pos += 1 << _k;
//			if(__frp) cerr << getvalrev2(8,6) << " " << getval2(10,6) << endl << "!!" << pos << endl;
//			if(__frp) cerr << "prefix! " << pos << endl;
			if(pl > pr || (getvalrev2(p.r - pos * I.d,pr - pl + 1) == getval(pl,pr) && egetvalrev2(p.r - pos * I.d,pr - pl + 1) == egetval(pl,pr))) pos++;
			pos--;
			pos = k - pos;
//			if(__frp) cerr << pos << endl;
			if(pos <= k) answer.push_back({q.l + I.l - q.r + pos * I.d,q.l + I.l - q.r + k * I.d,I.d});
		}else{
			pos = 0;
			per(_k,__lg(k),0) if(pos + (1 << _k) <= k && getvalrev2(p.r,(pos + (1 << _k)) * I.d) == getval2(I.l + 1,(pos + (1 << _k)) * I.d) && egetvalrev2(p.r,(pos + (1 << _k)) * I.d) == egetval2(I.l + 1,(pos + (1 << _k)) * I.d)) pos += 1 << _k;
			if(check2(q.l,I.l + I.d * (k - pos))){
				pl = q.l + I.l + I.d * (k - pos) - q.r;
				answer.push_back({pl,pl,0});
			}
		}
	}
	reverse(q.pre.begin(),q.pre.end());
	if(check2(p.r,q.l)){
		pl = p.r + q.l - q.r;
		answer.push_back({pl,pl,0});
	}
	if(__frp){
		cerr << "partical result:\n";
		for(info I:answer) cerr << I.l << " " << I.r << " " << I.d << endl;		
	}
	for(info I:p.suf){
		if(I.l == I.r){
			pl = I.l + p.r - q.r;
			pr = q.r;
//			cerr << "check " << pl << " " << pr << endl;
			if(check(pl,pr)) answer.push_back({pl,pl,0});
			continue;
		}
		k = (I.r - I.l) / I.d;
		pos = 0;
		per(_k,__lg(k),0) if(pos + (1 << _k) <= k && getvalrev2(I.r - 1,(pos + (1 << _k)) * I.d) == getval2(q.l,(pos + (1 << _k)) * I.d) && egetvalrev2(I.r - 1,(pos + (1 << _k)) * I.d) == egetval2(q.l,(pos + (1 << _k)) * I.d)) pos += 1 << _k;
		pl = q.l + pos * I.d;
		pr = q.r;
		if(pr - pl + 1 <= I.d && getvalrev2(I.r - 1,pr - pl + 1) == getval(pl,pr) && egetvalrev2(I.r - 1,pr - pl + 1) == egetval(pl,pr)){
			if(__frp) cerr << "!!" << pos << endl;
			if(k - pos > 0) answer.push_back({I.r - (k - pos - 1) * I.d + p.r - q.r,I.r + p.r - q.r,I.d});
		}

		if(check2(I.r - (k - pos) * I.d,p.r)){
			pl = I.r - (k - pos) * I.d + p.r - q.r;
			answer.push_back({pl,pl,0});
		}
	}
/*	if(__frp){
		cerr << "result:\n";
		for(info I:answer) cerr << I.l << " " << I.r << " " << I.d << endl;		
	}*/
	maintain(answer);
	if(__frp){
		cerr << "result:\n";
		for(info I:answer) cerr << I.l << " " << I.r << " " << I.d << endl;		
	}
}

void rever(vector <info> &p){
	for(info &I:p){
		I.l = n + 1 - I.l;
		I.r = n + 1 - I.r;
		swap(I.l,I.r);
	}
}

node operator +(node &p,node &q){
	node ans;
	rev = 0;
	ans.l = curL = p.l;ans.r = curR = q.r;
//	if(p.l == 2 && q.r == 15) __frp = 1;
//	else __frp = 0;
	if(__frp) cerr << "merge suffix:\n";
	mrg(p,q);
	ans.suf = answer;
	
//	__frp = 0;
/*	if(p.l == 1 && q.r == 4){
		__frp = 1;
		cerr << "merge prefix:\n";
	}*/
//	__frp = 0;
	if(__frp) cerr << "merge prefix:\n";
	node tp = p,tq = q;
	rever(tp.pre);rever(tp.suf);
	rever(tq.pre);rever(tq.suf);
	swap(tp.pre,tq.suf);
	swap(tp.suf,tq.pre);
	tp.l = n + 1 - tp.l;tp.r = n + 1 - tp.r;
	tq.l = n + 1 - tq.l;tq.r = n + 1 - tq.r;
	swap(tp.l,tq.r);swap(tp.r,tq.l);
	rev = 1;
	mrg(tp,tq);

	rever(answer);
	ans.pre = answer;
	return ans;
}

void print(node &p){
	cerr << "range [" << p.l << "," << p.r << "] info\n";
	cerr << "pre palin\n";
	for(info I:p.pre) cerr << I.l << " " << I.r << " " << I.d << endl;
	cerr << "suf palin\n";
	for(info I:p.suf) cerr << I.l << " " << I.r << " " << I.d << endl; 
}

void vertify(int rt,int l,int r){
	rev = 0;
	curL = l;curR = r;
	for(info I:tree[rt].pre){
		if(!I.d) I.d = 114514;
		int pos = I.l;
		while(pos <= I.r){
			assert(l <= pos && pos <= r);
			if(!check(l,pos)) printf("fail vertify!! [%d,%d] %d %d\n",l,r,l,pos);
			assert(check(l,pos));
			pos += I.d;
		}
	}
	for(info I:tree[rt].suf){
		if(!I.d) I.d = 114514;
		int pos = I.r;
		while(pos >= I.l){
			assert(l <= pos && pos <= r);
			if(!check(pos,r)) printf("fail vertify!! [%d,%d]\n",l,r);
			assert(check(pos,r));
			pos -= I.d;
		}
	}
}

void build(int rt,int l,int r){
	if(l == r){
		tree[rt].l = tree[rt].r = l;
		tree[rt].pre.push_back({l,l,0});
		tree[rt].suf.push_back({l,l,0});
//		print(tree[rt]);
		return;
	}
	int mid = (l + r) >> 1;
	build(ls,l,mid);build(rs,mid+1,r);
	tree[rt] = tree[ls] + tree[rs];
//	vertify(rt,l,r);
//	print(tree[rt]);
}

void modify(int rt,int l,int r,int pos){
	if(l == r){
		tree[rt].l = tree[rt].r;
		tree[rt].pre.clear();tree[rt].suf.clear();
		tree[rt].pre.push_back({l,l,0});
		tree[rt].suf.push_back({l,l,0});
		return;
	}
	int mid = (l + r) >> 1;
	if(pos <= mid) modify(ls,l,mid,pos);
	else modify(rs,mid+1,r,pos);
	tree[rt] = tree[ls] + tree[rs];
}

node result;
void query(int rt,int l,int r,int L,int R){
	if(l == L && r == R){
		if(!result.l) result = tree[rt];
		else result = result + tree[rt];
		return;
	}
	int mid = (l + r) >> 1;
	if(R <= mid){
		query(ls,l,mid,L,R);
	}else if(L > mid){
		query(rs,mid+1,r,L,R);
	}else{
		query(ls,l,mid,L,mid);
		query(rs,mid+1,r,mid+1,R);
	}
}

int solve(int l,int r){
//	__frp = 1;
	result.l = result.r = 0;
	query(1,1,n,l,r);
//	__frp = 0;
	int _result = 0;
	for(info I:result.suf){
		if(I.d) _result += (I.r - I.l) / I.d + 1;
		else _result++;
	}

	curL = l;curR = r;
	rev = 0;
	for(info I:result.suf){
		if(!I.d) I.d = 114514;
		int pos = I.l;
		while(pos <= I.r){
			assert(check(pos,r));
			printf("%d\n",pos);
			pos += I.d;
		}
	}
	return _result;
}

int main(){
//	freopen("test.in","r",stdin);
//	freopen("test.out","w",stdout);
	scanf("%s",s + 1);
	n = strlen(s + 1);
	P[0][0] = P[1][0] = 1;
	eP[0][0] = eP[1][0] = 1;
	rep(i,1,n){
		P[0][i] = P[0][i - 1] * base;
		P[1][i] = P[1][i - 1] * ibase;

		eP[0][i] = eP[0][i - 1] * base;
		eP[1][i] = eP[1][i - 1] / base;
	}
	init();
	build(1,1,n);
//	printf("qwq\n");

	int lastans = 0,op,l,r;
	char ch;
	scanf("%d",&Q);
	rep(i,1,Q){
		scanf("%d",&op);
		if(op == 1){
			scanf("%d",&l);
			l ^= lastans;
			assert(1 <= l && l <= n);
			do{
				scanf("%c",&ch);
			}while(ch < 'a' || ch > 'z');
			mdf(l,ch - s[l]);
			s[l] = ch;
			modify(1,1,n,l);
		}else{
			scanf("%d%d",&l,&r);
			l ^= lastans;r ^= lastans;
			assert(1 <= l && l <= r && r <= n);
			lastans = solve(l,r);
			printf("%d\n",lastans);
		}
	}
	return 0;
}

详细

Subtask #1:

score: 0
Wrong Answer

Test #1:

score: 0
Wrong Answer
time: 30ms
memory: 43328kb

input:

aabbbabbbaaaaaaabbabbbaaaabaaaabbaabbaabbaaababbbabbbbabbbbaaaabbbabbbbbaaabbbabbaaaaabbbbbaaababbabbaaaaabaabbbbaaababaaabbaabbabbbabbbbaaaaabbbbbbbabbbaabbbabbabbbababbabbbbaaaaabbaababbbbaabbaaaaaabaaabbbaaababbbbaabaaaaababababbbbbbaaaabbbbaaababaaabbaabbbbbaaaabbaaaabaaaaaababbababaaaabaaababaa...

output:

4778
4779
2
1672
1673
1674
3
4396
4397
4398
4399
4400
5
4359
4361
4355
3
3462
3463
3464
3
4180
4181
4177
3
4914
4918
2
4561
4563
4565
3
3822
3823
3824
3825
4
3742
3745
2
3608
3609
3610
3611
4
3461
3465
2
4214
4215
4216
4217
4
4782
4786
2
4681
4683
4671
3
3204
3205
3206
3
4768
4769
4770
3
4420
4424
2...

result:

wrong answer 1st words differ - expected: '2', found: '4778'

Subtask #2:

score: 0
Wrong Answer

Test #15:

score: 0
Wrong Answer
time: 4776ms
memory: 70080kb

input:

aabababbabbbbbbabbababaaaabababbabbbbbbabbababaaaabababbabbbbbbabbababaaaabababbabbbbbbabbababaabbbaaabbaabbbbaabbaaabbbaabababbabbbbbbabbababaaaabababbabbbbbbabbababaaaabababbabbbbbbabbababaaaabababbabbbbbbabbababaabbaaabaaaaaabaaabbaabababbabbbbbbabbababaaaabababbabbbbbbabbababaaaabababbabbbbbbabb...

output:

48380
48381
48382
48369
48376
32169
32619
33069
33519
33969
34419
34869
35319
35769
36219
36669
37119
37569
38019
38469
38919
39369
39819
40269
40719
41169
41619
42069
42519
42969
43419
43869
44319
44769
45219
45669
46119
46569
47019
47469
47919
41
116047
116049
116008
116032
115702
115936
99052
995...

result:

wrong answer 1st words differ - expected: '41', found: '48380'

Subtask #3:

score: 0
Wrong Answer

Test #21:

score: 0
Wrong Answer
time: 1729ms
memory: 69352kb

input:

abbaaaabbabaaaaaabaabbaabbababbaaabbabbbabaabaabaaaaabaabbbbabbabbabbbababbbababababbbbabaabbaaababbbbbababbbbaabbbaaabaababababaabbbbbbaababaabbaaabaabbaaababbabbabbbbaaaaabaaabbbabbbbbbabbbabbabaabbbbbbbaaaabbaaaababbbaaaaaaababaabbbbaaabaaabbaabbbbbbababbaabbaaabbabbbbbabaababbaabaaaabbbbabababba...

output:

199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
199999
2
199997
19999...

result:

wrong answer 1st words differ - expected: '2', found: '199997'

Subtask #4:

score: 0
Wrong Answer

Test #27:

score: 0
Wrong Answer
time: 964ms
memory: 69276kb

input:

babbaaabbbbbbbabbbababaabbbbbababababbaabaabbbbbbabbbbbbbbbbababbbbabbaabbbaabaabbabbbaabbabbbabbababaababbbabbbbaabbabbabbaaaabbbaaabbbbaabbaaaaaaabbbabbbaaabaababaaabaaaabaaaababaaaaababaaaabaabbaaaabbbabbaabaabbbabbbbbaaabaababbbaaaaabbbbaaabbbbaabbabbbbabbbabbaaaaabaabaaaabbbabbbbbaabbbbabbbbaab...

output:

199999
200000
199988
199996
4
199999
200000
199988
199996
4
199999
200000
199988
199996
4
199999
200000
199988
199996
4
199999
200000
199988
199996
4
199999
200000
199988
199996
4
199999
200000
199988
199996
4
199999
200000
199988
199996
4
199999
200000
199988
199996
4
199999
200000
199988
199996
4
...

result:

wrong answer 1st words differ - expected: '4', found: '199999'

Subtask #5:

score: 0
Skipped

Dependency #1:

0%

Subtask #6:

score: 0
Skipped

Dependency #1:

0%