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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#211722 | #2065. Cyclic Distance | Zeardoe | TL | 4ms | 31924kb | C++20 | 3.4kb | 2023-10-12 20:36:42 | 2023-10-12 20:36:42 |
Judging History
answer
/*
[templates]:
duipai
spjdp
compre
addhis
floor_sum
treedfs
matrix
network_flow
polynomial
lca
bitset
valuesgt
fenwick
erbitree
*/
//#pragma GCC optimize("Ofast")
//#pragma GCC target("avx")
#include<bits/stdc++.h>
using namespace std;
#define int long long
//use ll instead of int.
#define f(i, a, b) for(int i = (a); i <= (b); i++)
#define cl(i, n) i.clear(),i.resize(n);
#define endl '\n'
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int inf = 1e18;
//#define cerr if(false)cerr
//#define freopen if(false)freopen
mt19937 rng(time(0));
int rnd(int l, int r) {return rng() % (r-l+1) + l; }
#define watch(x) cerr << (#x) << ' '<<'i'<<'s'<<' ' << x << endl
void pofe(int number, int bitnum) {
string s; f(i, 0, bitnum) {s += char(number & 1) + '0'; number >>= 1; }
reverse(s.begin(), s.end()); cerr << s << endl;
return;
}
template <typename TYP> void cmax(TYP &x, TYP y) {if(x < y) x = y;}
template <typename TYP> void cmin(TYP &x, TYP y) {if(x > y) x = y;}
//调不出来给我对拍!
//use std::array.
vector<pii> t[200020]; int n, k;
struct HEAP {
priority_queue<int, vector<int>, greater<int>> q;
int tag;
void qing() {
while(!q.empty()) q.pop();
tag = 0;
}
void jin(int shu) {
q.push(shu - tag);
}
int ding() {
return q.top() + tag;
}
void chu() {
q.pop();
}
void jia(int shu) {
tag += shu;
}
void bing(HEAP op) {
if(q.size() < op.q.size()) {
swap(q, op.q);
swap(tag, op.tag);
}
while(!op.q.empty()) {
q.push(op.ding() - tag);
op.chu();
}
}
}s[200020], p[200020], x[200020];
void dfs(int now, int fa) {
for(pii iw : t[now]) {
int i = iw.first, w = iw.second;
if(i == fa) continue;
dfs(i, now);
s[i].jia(w); x[i].jia(-w);
s[now].bing(s[i]);
p[now].bing(p[i]);
x[now].bing(x[i]);
}
s[now].jin(0);
while((int)s[now].q.size() > k / 2) {p[now].jin(s[now].ding()); s[now].chu(); }
while((int)p[now].q.size() > k % 2) {x[now].jin(p[now].ding()); p[now].chu(); }
// cerr << "now = " << now << ", " << s[now].q.size() << " " << p[now].q.size() << " " << x[now].q.size() << endl;
}
signed main() {
ios::sync_with_stdio(0);
cin.tie(NULL);
cout.tie(NULL);
//freopen();
//freopen();
//time_t start = clock();
//think twice,code once.
//think once,debug forever.
int T; cin >> T;
while(T--) {
cin >> n >> k;
f(i, 1, n - 1) {
int u, v, w; cin >> u >> v >> w;
t[u].push_back({v, w}); t[v].push_back({u, w});
}
f(i, 1, n) {
s[i].qing();
p[i].qing();
x[i].qing();
}
dfs(1, 0);
s[1].bing(p[1]); s[1].bing(x[1]);
int cur = 0; vector<int> res;
while(!s[1].q.empty()) {
res.push_back(s[1].ding());
s[1].chu();
}
reverse(res.begin(), res.end());
f(i, 0, k - 1) {
cur += res[i];
}
cout << 2 * cur << endl;
}
//time_t finish = clock();
//cout << "time used:" << (finish-start) * 1.0 / CLOCKS_PER_SEC <<"s"<< endl;
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 4ms
memory: 31924kb
input:
1 5 3 1 2 4 1 3 1 1 4 8 4 5 9
output:
44
result:
ok single line: '44'
Test #2:
score: -100
Time Limit Exceeded
input:
57206 3 2 1 2 574927 2 3 406566 2 2 1 2 308806 4 3 1 2 312588 2 3 500141 2 4 53602 3 3 1 2 797183 2 3 944061 5 3 1 2 624010 2 3 488613 3 4 734514 4 5 497493 5 4 1 2 540278 2 3 488655 2 4 228989 2 5 653896 2 2 1 2 569117 4 2 1 2 821764 2 3 499471 1 4 549060 2 2 1 2 991159 2 2 1 2 482941 5 4 1 2 30462...