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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#202417 | #7523. Partially Free Meal | ucup-team859 | TL | 0ms | 3660kb | C++17 | 3.8kb | 2023-10-06 01:36:43 | 2023-10-06 01:36:44 |
Judging History
answer
#include <bits/stdc++.h>
#define lsb(x) (x & (-x))
using ull = unsigned long long;
using ll = long long;
using namespace std;
constexpr int INF = (int) 1e9;
struct SegTree {
struct Node {
int l = -1, r = -1;
ll sum = 0;
int count = 0;
};
SegTree() {
makeNode();
}
inline int makeNode(int oldId) {
if (oldId == -1) {
return makeNode();
}
data.push_back(data[oldId]);
return (int)data.size() - 1;
}
inline int makeNode() {
data.emplace_back();
return (int)data.size() - 1;
}
int update(int id, int l, int r, int val) {
int newId = makeNode(id);
if (l == r) {
data[newId].sum += val;
data[newId].count++;
} else {
int mid = (l + r) / 2;
if (val <= mid) {
int idl = update(data[newId].l, l, mid, val);
data[newId].l = idl;
} else {
int idr = update(data[newId].r, mid + 1, r, val);
data[newId].r = idr;
}
data[newId].sum += val;
data[newId].count++;
}
return newId;
}
ll query(int id, int k) {
ll answer = query(id, 1, INF, k);
if (k != 0) {
return 1e18;
}
return answer;
}
private:
ll query(int id, int l, int r, int& k) {
if (id == -1 || k <= 0) return 0LL;
if (data[id].count <= k) {
k -= data[id].count;
return data[id].sum;
} else {
int mid = (l + r) / 2;
ll answer = query(data[id].l, l, mid, k);
answer += query(data[id].r, mid + 1, r, k);
return answer;
}
}
public:
vector<Node> data;
};
struct Dish {
int a, b;
bool operator<(const Dish& dish) const {
if (b == dish.b)
return a > dish.a;
return b < dish.b;
}
};
int main() {
#ifdef HOME
ifstream cin("input.in");
ofstream cout("output.out");
#endif
ios::sync_with_stdio(false);
cin.tie(0), cout.tie(0);
int n;
cin >> n;
vector<Dish> dishes(n);
for (auto& dish : dishes) {
cin >> dish.a >> dish.b;
}
sort(dishes.begin(), dishes.end());
SegTree st;
vector<int> roots(n + 1);
vector<int> norm(n);
vector<int> stk;
auto Get = [&](int p1, int p2) {
int nrm1 = norm[p1], nrm2 = norm[p2];
int root1 = roots[nrm1], root2 = roots[nrm2];
int k = 0;
for (int step = 1 << 17; step; step >>= 1) {
if (k + step <= st.data[root2].count) {
ll s1 = st.query(root1, k + step) + dishes[p1].b;
ll s2 = st.query(root2, k + step) + dishes[p2].b;
if (s1 < s2) {
k += step;
}
}
}
return k;
};
int i = 0;
while (i < n) {
static int nrm = 0;
nrm++;
roots[nrm] = roots[nrm - 1];
int j = i;
while (j < n && dishes[i].b == dishes[j].b) {
roots[nrm] = st.update(roots[nrm], 1, INF, dishes[j].a);
norm[j++] = nrm;
}
i = j;
int pos = i - 1;
while (stk.size() > 1 && Get(stk[stk.size() - 2], stk.back()) >= Get(stk.back(), pos)) {
stk.pop_back();
}
stk.push_back(pos);
}
int k = 1;
for (int i = 0; i < (int)stk.size(); i++) {
int curr = (i == (int)stk.size() - 1 ? n : Get(stk[i], stk[i + 1]));
while (k <= curr) {
cout << st.query(roots[norm[stk[i]]], k) + dishes[stk[i]].b << "\n";
k++;
}
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3660kb
input:
3 2 5 4 3 3 7
output:
7 11 16
result:
ok 3 lines
Test #2:
score: -100
Time Limit Exceeded
input:
200000 466436993 804989151 660995237 756645598 432103296 703610564 6889895 53276988 873617076 822481192 532911431 126844295 623111499 456772252 937464699 762157133 708503076 786039753 78556972 5436013 582960979 398984169 786333369 325119902 930705057 615928139 924915828 506145001 164984329 208212435...