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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#202332#6644. Red Black Gridarseny_y#RE 1ms5516kbC++232.7kb2023-10-05 22:32:222023-10-05 22:32:22

Judging History

你现在查看的是最新测评结果

  • [2023-10-05 22:32:22]
  • 评测
  • 测评结果:RE
  • 用时:1ms
  • 内存:5516kb
  • [2023-10-05 22:32:22]
  • 提交

answer

//I wrote this code 4 u today
#include <bits/stdc++.h>

template<class t> using vc = std::vector<t>;

#define nd node*
#define pnd pair<nd, nd>

//using namespace std;
typedef long long ll;

template<const ll MOD>
struct mod_mul : std::multiplies<const ll> {
    ll operator()(const ll a, const ll b) {
        return (a * b) % MOD;
    }
};


template<typename T>
inline void sort(T &a) {
    sort(a.begin(), a.end());
}

template<typename T>
inline void unique(T &a) {
    a.resize(unique(a.begin(), a.end()) - a.begin());
}

template<typename T>
inline void reverse(T &a) {
    reverse(a.begin(), a.end());
}

const ll INF = 9023372036854775808ll;
const ll MOD = 1000000007ll;

std::pair<int, int> q[4] = {{0,  1},
                            {1,  0},
                            {0,  -1},
                            {-1, 0}};

int a[3005][3005];
int max = 0;

int n, k;
vc<std::array<int, 3>> x;
bool da[3005 * 3005 * 2];

int cnt = 0;
bool gen(int i = 0) {
    if (cnt == k) {
        for (int i = 0; i < n; ++i) for (int j = 0; j < n; ++j) a[i][j] = 0;
        for (int i = 0; i < x.size(); ++i) if (da[i]) a[x[i][1]][x[i][2]] = 1;
        for (int i = 0; i < n; ++i) {
            std::string s;
            for (int j = 0; j < n; ++j) s.push_back(a[i][j] ? 'R' : 'B');
            std::cout << s << '\n';
        }
        return true;
    }
    if (i == x.size()) {
        return true;
    }
    da[i] = 1;
    cnt += x[i][0];
    if (gen(i + 1)) return true;
    da[i] = 0;
    cnt -= x[i][0];
    if (gen(i + 1)) return true;
    return false;
}

int main() {
    std::cin.tie(nullptr)->ios_base::sync_with_stdio(false);
    int t;
    std::cin >> t;
    while (t--) {
        max = 0;
        std::cin >> n >> k;
        int hex = 0;
        for (int i = 0; i < n; ++i) {
            for (int j = 0; j < n; ++j) {
                hex += i != n - 1;
                hex += j != n - 1;
            }
        }
        if (k > hex || k == hex - 1 || k == 1) {
            std::cout << "Impossible\n";
//            gen(0, 0);
        } else {
            std::cout << "Possible\n";
            x.clear();
            for (int i = 0; i < n; ++i) {
                for (int j = 0; j < n; ++j) {
                    if ((i + j + 1) % 2) {
                        if (i % (n - 1) == 0 && j % (n - 1) == 0) x.push_back({2, i, j});
                        else if (i % (n - 1) == 0 || j % (n - 1) == 0) x.push_back({3, i, j});
                        else x.push_back({4, i, j});
                    }
                }
            }
            std::sort(x.begin(), x.end());
            assert(gen());
        }
    }
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 5516kb

input:

2
3 6
3 1

output:

Possible
RBR
BBB
RBB
Impossible

result:

ok correct! (2 test cases)

Test #2:

score: -100
Runtime Error

input:

4424
1 0
2 4
2 3
2 2
2 1
2 0
3 12
3 11
3 10
3 9
3 8
3 7
3 6
3 5
3 4
3 3
3 2
3 1
3 0
4 24
4 23
4 22
4 21
4 20
4 19
4 18
4 17
4 16
4 15
4 14
4 13
4 12
4 11
4 10
4 9
4 8
4 7
4 6
4 5
4 4
4 3
4 2
4 1
4 0
5 40
5 39
5 38
5 37
5 36
5 35
5 34
5 33
5 32
5 31
5 30
5 29
5 28
5 27
5 26
5 25
5 24
5 23
5 22
5 21
5...

output:


result: