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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#194250#7512. Almost Prefix Concatenationucup-team1191#WA 1894ms34656kbC++204.0kb2023-09-30 19:46:162023-09-30 19:46:16

Judging History

你现在查看的是最新测评结果

  • [2023-09-30 19:46:16]
  • 评测
  • 测评结果:WA
  • 用时:1894ms
  • 内存:34656kb
  • [2023-09-30 19:46:16]
  • 提交

answer

/*
    author:  Maksim1744
    created: 30.09.2023 14:37:06
*/

#include "bits/stdc++.h"

using namespace std;

using ll = long long;
using ld = long double;

#define mp   make_pair
#define pb   push_back
#define eb   emplace_back

#define sum(a)     ( accumulate ((a).begin(), (a).end(), 0ll))
#define mine(a)    (*min_element((a).begin(), (a).end()))
#define maxe(a)    (*max_element((a).begin(), (a).end()))
#define mini(a)    ( min_element((a).begin(), (a).end()) - (a).begin())
#define maxi(a)    ( max_element((a).begin(), (a).end()) - (a).begin())
#define lowb(a, x) ( lower_bound((a).begin(), (a).end(), (x)) - (a).begin())
#define uppb(a, x) ( upper_bound((a).begin(), (a).end(), (x)) - (a).begin())

template<typename T>             vector<T>& operator--            (vector<T> &v){for (auto& i : v) --i;            return  v;}
template<typename T>             vector<T>& operator++            (vector<T> &v){for (auto& i : v) ++i;            return  v;}
template<typename T>             istream& operator>>(istream& is,  vector<T> &v){for (auto& i : v) is >> i;        return is;}
template<typename T>             ostream& operator<<(ostream& os,  vector<T>  v){for (auto& i : v) os << i << ' '; return os;}
template<typename T, typename U> pair<T,U>& operator--           (pair<T, U> &p){--p.first; --p.second;            return  p;}
template<typename T, typename U> pair<T,U>& operator++           (pair<T, U> &p){++p.first; ++p.second;            return  p;}
template<typename T, typename U> istream& operator>>(istream& is, pair<T, U> &p){is >> p.first >> p.second;        return is;}
template<typename T, typename U> ostream& operator<<(ostream& os, pair<T, U>  p){os << p.first << ' ' << p.second; return os;}
template<typename T, typename U> pair<T,U> operator-(pair<T,U> a, pair<T,U> b){return mp(a.first-b.first, a.second-b.second);}
template<typename T, typename U> pair<T,U> operator+(pair<T,U> a, pair<T,U> b){return mp(a.first+b.first, a.second+b.second);}
template<typename T, typename U> void umin(T& a, U b){if (a > b) a = b;}
template<typename T, typename U> void umax(T& a, U b){if (a < b) a = b;}

#ifdef HOME
#define SHOW_COLORS
#include "/mnt/c/Libs/tools/print.cpp"
#else
#define show(...) void(0)
#define debugf(fun)   fun
#define debugv(var)   var
#define mclock    void(0)
#define shows     void(0)
#define debug  if (false)
#define OSTREAM(...)    ;
#define OSTREAM0(...)   ;
#endif

// mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
mt19937_64 rng(423876428);
ll rnd (ll l, ll r) { return (ll)(rng() % (r - l + 1)) + l; }
ll rnd (ll r)       { return rng() % r; }
ll rnd ()           { return rng(); }
ld rndf()           { return (ld)rng() / (ld)ULLONG_MAX; }
ld rndf(ld l, ld r) { return rndf() * (r - l) + l; }

// template<typename T>
// using pq = priority_queue<T, vector<T>, greater<T>>;

int main() {
    ios_base::sync_with_stdio(false); cin.tie(NULL);

    int n = 1e6, q = 1e6;
    // cin >> n >> q;

    vector<int> a(n);
    vector<int> b(n);
    const int inf = 1e9;
    for (int i = 0; i < n; ++i) {
        a[i] = rnd(1, inf);
        b[i] = rnd(1, inf);
    }
    // cin >> a >> b;
    vector<int> ord(n);
    iota(ord.begin(), ord.end(), 0);
    sort(ord.begin(), ord.end(), [&](int i, int j) {
        return a[i] > a[j];
    });

    priority_queue<pair<int, int>> qu;
    for (int i = 0; i < n; ++i) {
        qu.emplace(b[i], i);
    }

    auto calc = [&](int shift) {
        while (qu.top().second < shift)
            qu.pop();
        int bmax = qu.top().first;
        int ans = 0;
        for (int i : ord) {
            if (bmax + a[i] <= ans) break;
            ans = max(ans, a[i] + b[i + shift]);
        }
        return ans;
    };
    for (int sh = 0; sh <= q; ++sh) {
        int r = calc(sh);
        cout << r << '\n';
        if (sh != q) {
            // int v;
            // cin >> v;
            // b.pb(v ^ r);
            b.pb(rnd(1, inf));
            qu.emplace(b.back(), b.size()-1);
        }
    }

    return 0;
}

詳細信息

Test #1:

score: 0
Wrong Answer
time: 1894ms
memory: 34656kb

input:

ababaab
aba

output:

1998700234
1998212927
1998376387
1998887278
1998470459
1998287180
1998559670
1999127838
1998097203
1999082481
1998914885
1997041708
1999530430
1998248609
1998308505
1998529428
1998906640
1999815741
1999226541
1998373047
1998633405
1999427995
1998562893
1998957667
1999523669
1998888104
1999784917
199...

result:

wrong answer 1st numbers differ - expected: '473', found: '1998700234'