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#190649#2830. Data Structureqzez#RE 3ms14040kbC++144.0kb2023-09-29 11:09:192023-09-29 11:09:19

Judging History

你现在查看的是最新测评结果

  • [2023-09-29 11:09:19]
  • 评测
  • 测评结果:RE
  • 用时:3ms
  • 内存:14040kb
  • [2023-09-29 11:09:19]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
using ll=long long;
template<typename T>
ostream& operator << (ostream &out,const vector<T>&x){
	if(x.empty())return out<<"[]";
	out<<'['<<x[0];
	for(int len=x.size(),i=1;i<len;i++)out<<','<<x[i];
	return out<<']';
}
template<typename T>
ostream& operator << (ostream &out,const pair<T,T>&x){
	return out<<x.first;
}
template<typename T>
vector<T> ary(const T *a,int l,int r){
	return vector<T>{a+l,a+1+r};
}
template<typename T>
void debug(T x){
	cerr<<x<<'\n';
}
template<typename T,typename ...S>
void debug(T x,S ...y){
	cerr<<x<<' ',debug(y...);
}
const int N=2e5+10;
int n,m,in[N],out[N];
vector<int>ept,ok;
vector<int>only[N];
vector<pair<int,int> >to[N];
void addedge(int u,int v,int i){
	out[u]++,in[v]++;
	to[u].push_back({v,i});
	to[v].push_back({u,-i});
}
#define v e.first
#define w e.second
int vis[N];
bool judge(int u,int fa=0){
	vis[u]=1;
	if(out[u]==2)return 1;
	for(auto e:to[u])if(v^fa){
		if(judge(v,u))return 1;
	}
	return 0;
}
void cover(int u){
	if(vis[u])return;
	vis[u]=1;
	for(auto e:to[u])cover(v);
}
int k,id[N],p[N];
void find(int u,int las=0){
	if(vis[u])return;
	vis[u]=1,id[++k]=u,p[k]=las;
	for(auto e:to[u])find(v,w);
}
vector<pair<int,int> >ans;
void opt(int x,int y){
	ans.push_back({abs(x),abs(y)});
}
bool solve1(int s){
	k=0,find(s);
	// for(int i=1;i<=k;i++)debug(id[i],only[id[i]]);
	// return 1;
	p[1]=only[id[1]][0],only[id[1]].pop_back();
	p[k+1]=only[id[k]][0],only[id[k]].pop_back();
	// debug(ary(id,1,k),ary(p,1,k+1));
	vector<int>t{1};
	for(int i=1;i<=k;i++)if(out[i]==2)t.push_back(i);
	for(int len=t.size(),i=1;i<len;i++){
		int l=t[i-1],r=t[i],id=-1;
		for(int i=l+1;i<r;i++)if(in[i]==2)id=i;
		if(ept.empty())return 0;
		int x=ept.back();
		ept.pop_back();
		opt(p[r],x);
		if(~id){
			for(int i=l;i<id;i++)opt(p[i+1],p[i]);
			for(int i=r-1;i>id;i--)opt(p[i],p[i+1]);
			int x=p[id],y=p[id+1];
			opt(x,y),ept.push_back(x);
		}else{
			for(int i=r-1;i>=l;i--)opt(p[i],p[i+1]);
			ept.push_back(p[l]);
		}
		p[r]=abs(x);
	}
	int l=t.back(),r=k+1,id=-1;
	for(int i=l+1;i<r;i++)if(in[i]==2)id=i;
	if(~id){
		for(int i=l;i<id;i++)opt(p[i+1],p[i]);
		for(int i=r-1;i>id;i--)opt(p[i],p[i+1]);
		int x=p[id],y=p[id+1];
		opt(x,y),ept.push_back(x);
	}else{
		if(p[k]>0){
			for(int i=l;i<r;i++)opt(p[i+1],p[i]);
			ept.push_back(p[r]);
		}else{
			for(int i=r;i>l;i--)opt(p[i-1],p[i]);
			ept.push_back(p[l]);
		}
	}
	return 1;
}
bool solve2(int s){
	// debug("ok1");
	int x=-1,y=-1;
	for(auto e:to[s])if(w>0)x=v,y=w;
	to[s].erase(find(to[s].begin(),to[s].end(),make_pair(x,y)));
	to[x].erase(find(to[x].begin(),to[x].end(),make_pair(s,-y)));
	out[s]--,in[x]--;
	// debug(s,x,to[s],to[x]);
	if(ept.empty())return 0;
	int z=ept.back();
	ept.pop_back();
	opt(y,z);
	only[s].push_back(z);
	only[x].push_back(y);
	return solve1(s);
}
#undef v
#undef w
bool get(){
	for(int i=1,x,u,v;i<=m;i++){
		scanf("%d",&x);
		if(!x)ept.push_back(i);
		else if(x==1)scanf("%d",&u),only[u].push_back(i);
		else if(scanf("%d%d",&u,&v),u!=v)addedge(v,u,i);
		else ok.push_back(u);
	}
	// for(int i=1;i<=n;i++)debug("to",i,to[i]);
	fill(vis+1,vis+1+n,0);
	for(int x:ok)vis[x]=1;
	vector<int>t[3];
	for(int i=1;i<=n;i++){
		if(!vis[i]&&to[i].size()==1){
			if(judge(i))t[1].push_back(i);
			else t[0].push_back(i);
		}
	}
	for(int i=1;i<=n;i++){
		if(!vis[i]&&out[i]==2)t[2].push_back(i),cover(i);
	}
	// debug(ary(t,0,2));
	for(int i=1;i<=n;i++){
		if(!vis[i])t[2].push_back(i),cover(i);
	}
	fill(vis+1,vis+1+n,0);
	for(int i:t[0]){
		if(!solve1(i))return 0;
	}
	for(int i:t[1]){
		if(!solve1(i))return 0;
	}
	for(int i:t[2]){
		if(!solve2(i))return 0;
	}
	printf("%d\n",(int)ans.size());
	for(auto x:ans)printf("%d %d\n",x.first,x.second);
	return 1;
}
void clr(){
	ept.clear(),ans.clear(),ok.clear();
	for(int i=1;i<=n;i++){
		only[i].clear();
		in[i]=out[i]=0;
	}
}
int main(){
	for(;~scanf("%d%d",&n,&m);clr())if(!get())puts("-1");
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 3ms
memory: 14040kb

input:

2 3
2 1 2
2 1 2
0
1 1
2 1 1
3 4
2 1 3
2 2 3
1 1
1 2

output:

3
2 3
1 3
2 1
0
-1

result:

ok 3 cases passed. max #moves/#balls = 1.500000000

Test #2:

score: -100
Runtime Error

input:

1 2
1 1
1 1
1 3
1 1
0
1 1
1 4
1 1
1 1
0
0
1 1
2 1 1
1 2
2 1 1
0
1 3
0
0
2 1 1

output:


result: