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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#188341#6644. Red Black GridqzzyqWA 2ms3656kbC++142.5kb2023-09-25 19:13:362023-09-25 19:13:36

Judging History

你现在查看的是最新测评结果

  • [2023-09-25 19:13:36]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:3656kb
  • [2023-09-25 19:13:36]
  • 提交

answer

#include<bits/stdc++.h>
#define ll long long
#define ull unsigned long long
#define maxn 1005
#define put() putchar('\n')
#define Tp template<typename Ty>
#define Ts template<typename Ty,typename... Ar>
using namespace std;
void read(int &x){
    int f=1;x=0;char c=getchar();
    while (c<'0'||c>'9') {if (c=='-') f=-1;c=getchar();}
    while (c>='0'&&c<='9') {x=x*10+c-'0';c=getchar();}
    x*=f;
}
namespace Debug{
	Tp void _debug(char* f,Ty t){cerr<<f<<'='<<t<<endl;}
	Ts void _debug(char* f,Ty x,Ar... y){while(*f!=',') cerr<<*f++;cerr<<'='<<x<<",";_debug(f+1,y...);}
	Tp ostream& operator<<(ostream& os,vector<Ty>& V){os<<"[";for(auto& vv:V) os<<vv<<",";os<<"]";return os;}
	#define gdb(...) _debug((char*)#__VA_ARGS__,__VA_ARGS__)
}using namespace Debug;
#define fi first
#define se second
#define mk make_pair
const int mod=1e9+7;
int power(int x,int y=mod-2) {
	int sum=1;
	while (y) {
		if (y&1) sum=sum*x%mod;
		x=x*x%mod;y>>=1;
	}
	return sum;
}
int n,m,a[maxn][maxn];
void print(void) {
	int i,j;
	for (i=1;i<=n;i++,put()) for (j=1;j<=n;j++) putchar(a[i][j]?'R':'B');
}
void solve(void) {
	int i,j;
	read(n);read(m);
	for (i=1;i<=n;i++) for (j=1;j<=n;j++) a[i][j]=0;
	if (m==1||m==2*n*(n-1)-1) return puts("Impossible"),void();
	puts("Possible");
	int tmp1=0,tmp2=0,tmp3=0;
	if (n==3) {
		if (m==3) return a[1][2]=1,print(),void();
		else if (m==5) return a[3][3]=a[1][2]=1,print(),void();
		else if (m==6) return a[1][2]=a[2][1]=1,print(),void();
		else if (m==7) return a[3][1]=a[3][3]=a[1][2]=1,print(),void();
		else if (m==8) return a[1][1]=a[1][3]=a[3][1]=a[3][3]=1,print(),void();
		else if (m==9) return a[1][2]=a[2][1]=a[2][3]=1,print(),void();
		else if (m==10) return a[1][1]=a[1][3]=a[2][2]=a[3][1]=1,print(),void();
	}
	if (n&1) {
//		tmp1=2,tmp2=(n-2)/2*3,tmp3=((n-2)*(n-2)+1)/2;
		for (i=1;i<n&&m>7;i++) 
			for (j=1;j<=n&&m>7;j++) if ((i+j)%2==0) {
				int sum=4;
				if (i==1||i==n) sum--;
				if (j==1||j==n) sum--;
				m-=sum;
				a[i][j]=1;
			}
		for (j=3;j<n&&m>4;j+=2) m-=3,a[n][j]=1;
		if (m==3) a[n][j]=1;
		else if (m==2) a[n][1]=1;
		else if (m==4) a[n][1]=a[n][n]=1;
	}
	else {
		for (i=1;i<n&&m>7;i++) 
			for (j=1;j<=n&&m>7;j++) if ((i+j)%2==0&&i+j>2) {
				int sum=4;
				if (i==1||i==n) sum--;
				if (j==1||j==n) sum--;
				m-=sum;
				a[i][j]=1;
			}
		for (j=2;j<n&&m>4;j+=2) m-=3,a[n][j]=1;
		if (m==3) a[n][j]=1;
		else if (m==2) a[1][1]=1;
		else if (m==4) a[1][1]=a[n][n]=1;
	}
	print();
}
signed main(void){
	int T;
	read(T);
	while (T--) solve();
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3592kb

input:

2
3 6
3 1

output:

Possible
BRB
RBB
BBB
Impossible

result:

ok correct! (2 test cases)

Test #2:

score: -100
Wrong Answer
time: 2ms
memory: 3656kb

input:

4424
1 0
2 4
2 3
2 2
2 1
2 0
3 12
3 11
3 10
3 9
3 8
3 7
3 6
3 5
3 4
3 3
3 2
3 1
3 0
4 24
4 23
4 22
4 21
4 20
4 19
4 18
4 17
4 16
4 15
4 14
4 13
4 12
4 11
4 10
4 9
4 8
4 7
4 6
4 5
4 4
4 3
4 2
4 1
4 0
5 40
5 39
5 38
5 37
5 36
5 35
5 34
5 33
5 32
5 31
5 30
5 29
5 28
5 27
5 26
5 25
5 24
5 23
5 22
5 21
5...

output:

Possible
B
Possible
RB
BR
Impossible
Possible
RB
BB
Impossible
Possible
BB
BB
Possible
RBR
BRB
RBR
Impossible
Possible
RBR
BRB
RBB
Possible
BRB
RBR
BBB
Possible
RBR
BBB
RBR
Possible
BRB
BBB
RBR
Possible
BRB
RBB
BBB
Possible
BRB
BBB
BBR
Possible
BBB
BBB
RBR
Possible
BRB
BBB
BBB
Possible
BBB
BBB
RBB
I...

result:

wrong answer Condition failed: "getNum(vec) == k" (test case 25)