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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#185097 | #6737. Neighbourhood | bulijiojiodibuliduo | TL | 0ms | 30700kb | C++ | 2.6kb | 2023-09-21 17:05:46 | 2023-09-21 17:05:46 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define rep(i,a,n) for (int i=a;i<n;i++)
#define per(i,a,n) for (int i=n-1;i>=a;i--)
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define fi first
#define se second
#define SZ(x) ((int)(x).size())
typedef vector<int> VI;
typedef basic_string<int> BI;
typedef long long ll;
typedef pair<int,int> PII;
typedef double db;
mt19937 mrand(random_device{}());
const ll mod=998244353;
int rnd(int x) { return mrand() % x;}
ll powmod(ll a,ll b) {ll res=1;a%=mod; assert(b>=0); for(;b;b>>=1){if(b&1)res=res*a%mod;a=a*a%mod;}return res;}
ll gcd(ll a,ll b) { return b?gcd(b,a%b):a;}
// head
const int N=201000;
vector<array<int,2>> e[N];
int wt[N];
int q[N],f[N],vis[N],sz[N],ms[N];
int find(int u) {
int t=1;q[0]=u;f[u]=-1;
rep(i,0,t) {
u=q[i];
rep(j,0,e[u].size()) {
int v=e[u][j][0];
if (!vis[v]&&v!=f[u]) f[q[t++]=v]=u;
}
ms[q[i]]=0;
sz[q[i]]=1;
}
for (int i=t-1;i>=0;i--) {
ms[q[i]]=max(ms[q[i]],t-sz[q[i]]);
if (ms[q[i]]*2<=t) return q[i];
sz[f[q[i]]]+=sz[q[i]];
ms[f[q[i]]]=max(ms[f[q[i]]],sz[q[i]]);
}
return 0;
}
struct dst {
vector<ll> a;
int bsz;
void init(vector<ll> dp) {
a=dp;
}
void add(int l,int r,ll x) {
rep(i,l,r+1) a[i]+=x;
}
int query(int l,int r,ll d) {
int ans=0;
rep(i,l,r+1) ans+=a[i]<=d;
return ans;
}
ll queryp(int x) {
return a[x];
}
}ds[N];
int n,Q;
vector<array<int,3>> ps[N];
vector<array<int,5>> cs[N];
void solve(int x) {
x=find(x);
vis[x]=1;
int tot=0;
static int l[N],r[N],br[N];
VI pv;
vector<ll> dp;
function<void(int,int,int,ll)> dfs=[&](int u,int f,int b,ll dep) {
l[u]=tot++;
dp.pb(dep);
pv.pb(u);
br[u]=b;
for (auto [v,id]:e[u]) if (v!=f&&!vis[v]) {
dfs(v,u,b==-1?v:b,dep+wt[id]);
ps[id].pb({x,l[v],r[v]});
}
r[u]=tot-1;
};
dfs(x,-1,-1,0);
ds[x].init(dp);
for (auto u:pv) {
cs[u].pb({x,0,tot-1,l[u],1});
if (br[u]!=-1) cs[u].pb({x,l[br[u]],r[br[u]],l[u],-1});
}
for (auto [v,id]:e[x]) if (!vis[v]) {
solve(v);
}
}
int main() {
scanf("%d%d",&n,&Q);
rep(i,1,n) {
int u,v,w;
scanf("%d%d%d",&u,&v,&w);
e[u].pb({v,i});
e[v].pb({u,i});
wt[i]=w;
}
solve(1);
rep(i,0,Q) {
int op;
scanf("%d",&op);
if (op==1) {
int id,c;
scanf("%d%d",&id,&c);
c-=wt[id]; wt[id]+=c;
for (auto [x,l,r]:ps[id]) {
ds[x].add(l,r,c);
}
} else {
int x; ll d;
scanf("%d%lld",&x,&d);
int ans=0;
for (auto [u,l,r,pos,sgn]:cs[x]) {
ll v=ds[u].queryp(pos);
ans+=sgn*ds[u].query(l,r,d-v);
}
printf("%d\n",ans);
}
}
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 30700kb
input:
3 7 1 2 3 2 3 1 2 2 1 2 1 3 2 3 4 1 1 1 2 2 1 2 1 0 2 3 1
output:
2 2 3 3 1 2
result:
ok 6 numbers
Test #2:
score: -100
Time Limit Exceeded
input:
200000 200000 1 2 146181238 2 3 45037818 3 4 176924060 4 5 969365276 5 6 683948619 6 7 356268194 7 8 871634797 8 9 630254480 9 10 283061123 10 11 204904965 11 12 838381393 12 13 516373812 13 14 253862710 14 15 223572474 15 16 114452997 16 17 145251056 17 18 905638436 18 19 375445402 19 20 549829545 ...
output:
219 62303 1358 5532 65345 682 11856 120285 4980 5689 2998 2314 18102 8014 20512 2827 113022 74534 159775 14517 17961 21855 8138 265 3336 3251 7023 35187 4932 151611 14338 101 899 117 64441 888 10380 1833 29381 1014 4806 10770 23734 236 37258 2280 14550 2196 38205 80950 80839 4517 74570 13972 95914 7...