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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#181257 | #7108. Couleur | ucup-team1069# | RE | 2ms | 9784kb | C++14 | 3.9kb | 2023-09-16 17:09:48 | 2023-09-16 17:09:48 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
const int M = 70e5 + 200;
const int N = 1e5 + 200;
int n, a[N], rt[N];
long long now[N];
struct tree {
int L[M], R[M];
int t[M], sz = 0;
void clear() {
for (int i = 1; i <= sz; ++i) {
L[i] = R[i] = t[i] = 0;
}
sz = 0;
}
inline int make() {
return ++sz;
}
void build(int v, int tl = 1, int tr = n) {
t[v] = 0;
if (tl == tr) return;
L[v] = make();
R[v] = make();
int tm = tl + tr >> 1;
build(L[v], tl, tm);
build(R[v], tm + 1, tr);
}
void upd(int pos, int v, int u, int tl = 1, int tr = n) {
if (tl == tr) {
t[v] = t[u] + 1;
return;
}
int tm = tl + tr >> 1;
L[v] = L[u];
R[v] = R[u];
if (pos <= tm) {
L[v] = make();
upd(pos, L[v], L[u], tl, tm);
}
else {
R[v] = make();
upd(pos, R[v], R[u], tm + 1, tr);
}
t[v] = t[L[v]] + t[R[v]];
}
int get(int l, int r, int lv, int rv, int tl = 1, int tr = n) {
if (l <= tl && tr <= r)
return t[rv] - t[lv];
if (r < tl || tr < l)
return 0;
int tm = tl + tr >> 1;
return get(l, r, L[lv], L[rv], tl, tm) + get(l, r, R[lv], R[rv], tm + 1, tr);
}
} t;
void solve() {
cin >> n;
t.clear();
rt[0] = t.make();
t.build(rt[0]);
for (int i = 1; i <= n; ++i) {
cin >> a[i];
rt[i] = t.make();
t.upd(a[i], rt[i], rt[i - 1]);
}
long long ans = 0;
for (int i = 1; i <= n; ++i) {
ans += t.get(a[i] + 1, n, rt[0], rt[i - 1]);
}
set<pair<int, int>> s;
multiset<long long> vals;
s.insert({1, n});
now[1] = ans;
vals.insert(ans);
vals.insert(0);
int alive[n + 1];
for (int i = 1, p; i <= n; ++i) {
alive[i] = 1;
}
for (int i = 1, p; i <= n; ++i) {
cout << ans << " \n"[i == n];
cin >> p;
p ^= ans;
if(alive[p] == 0) {
cout << "SUKAAAA BLYAAT\n";
exit(0);
}
alive[p] = 0;
if (i == n) break;
auto it = prev(s.upper_bound({p, n + 1}));
auto [l, r] = *it;
s.erase(it);
vals.erase(vals.find(now[l]));
long long x = 0, y = 0, z = 0;
if (p <= (l + r) / 2) {
for (int j = l; j < p; ++j) {
x += t.get(a[j] + 1, n, rt[l - 1], rt[j - 1]);
y += t.get(1, a[j] - 1, rt[p], rt[r]);
}
z += t.get(1, a[p] - 1, rt[p], rt[r]);
z += t.get(a[p] + 1, n, rt[l - 1], rt[p - 1]);
if (p + 1 <= r) {
now[p + 1] = now[l] - x - y - z;
s.insert({p + 1, r});
vals.insert(now[p + 1]);
}
if (p - 1 >= l) {
s.insert({l, p - 1});
now[l] = x;
vals.insert(now[l]);
}
}
else {
for (int j = p + 1; j <= r; ++j) {
x += t.get(a[j] + 1, n, rt[p], rt[j - 1]);
y += t.get(a[j] + 1, n, rt[l - 1], rt[p - 1]);
}
z += t.get(1, a[p] - 1, rt[p], rt[r]);
z += t.get(a[p] + 1, n, rt[l - 1], rt[p - 1]);
if (p + 1 <= r) {
s.insert({p + 1, r});
now[p + 1] = x;
vals.insert(now[p + 1]);
}
if (p - 1 >= l) {
s.insert({l, p - 1});
now[l] = now[l] - x - y - z;
vals.insert(now[l]);
}
}
ans = *vals.rbegin();
}
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int T;
cin >> T;
while (T--) solve();
}
详细
Test #1:
score: 100
Accepted
time: 2ms
memory: 9784kb
input:
3 5 4 3 1 1 1 5 4 5 3 1 10 9 7 1 4 7 8 5 7 4 8 21 8 15 5 9 2 4 5 10 6 15 4 8 8 1 12 1 10 14 7 14 2 9 13 10 3 37 19 23 15 7 2 10 15 2 13 4 5 8 7 10
output:
7 0 0 0 0 20 11 7 2 0 0 0 0 0 0 42 31 21 14 14 4 1 1 1 0 0 0 0 0 0
result:
ok 3 lines
Test #2:
score: -100
Runtime Error
input:
11116 10 10 5 10 3 6 4 8 5 9 8 31 27 24 11 12 3 0 2 3 1 10 8 2 7 2 8 10 1 10 9 10 6 5 2 13 2 1 0 1 3 1 10 7 10 7 6 1 3 10 6 7 9 21 18 10 1 6 5 4 8 9 10 10 2 10 4 8 8 5 7 2 6 7 20 10 9 1 15 0 4 2 9 7 10 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 10 1 2 3 4 5 6 7 8 9 10 6 3 5 2 7 10 9 1 4 8 10 1 10 1 3...
output:
21 18 16 12 10 6 4 1 1 0 12 12 10 10 4 4 4 2 1 0 20 16 9 5 3 3 3 0 0 0 22 14 8 8 5 5 2 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 19 12 7 4 4 2 2 1 0 0 20 18 8 3 1 1 0 0 0 0 45 21 21 10 3 3 3 0 0 0 17 11 8 2 1 1 1 0 0 0 13 4 1 0 0 0 0 0 0 0 29 27 22 15 9 7 4 3 1 0 26 16 9 2 1 1 1 1 1 0 0 0 0 0 0 ...