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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#18028#2265. Short Coding_silhouette_#WA 3ms3856kbC++2.1kb2022-01-15 19:24:582022-05-04 16:42:58

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-05-04 16:42:58]
  • 评测
  • 测评结果:WA
  • 用时:3ms
  • 内存:3856kb
  • [2022-01-15 19:24:58]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
int n,m,ans,Ans[10],A[10],vis[20][20][10][5];
char a[15][15];
void Print(int x){
	if(x==1) puts("LEFT");
	if(x==2) puts("RIGHT");
	if(x==3) puts("FORWARD");
	if(x==4) puts("IF-OPEN 1");
	if(x==5) puts("IF-OPEN 2");
	if(x==6) puts("IF-OPEN 3");
	if(x==7) puts("IF-OPEN 4");
	if(x==8) puts("GOTO 1");
	if(x==9) puts("GOTO 2");
	if(x==10) puts("GOTO 3");
	if(x==11) puts("GOTO 4");
}
bool dfs(int x,int y,int op,int f,int tot){//DLUR
	if(op>tot) return dfs(x,y,op-tot,f,tot);
	if(vis[x][y][op][f]) return false;
	if(a[x][y]=='G') return true;
	vis[x][y][op][f]=1;
	if(A[op]==1) return dfs(x,y,op+1,(f+3)%4,tot);
	if(A[op]==2) return dfs(x,y,op+1,(f+1)%4,tot);
	if(A[op]==3){
		if(f==0) 
		 if(x+1<=n&&a[x+1][y]!='#') return dfs(x+1,y,op+1,f,tot); 
		if(f==1)
		 if(y-1>=1&&a[x][y-1]!='#') return dfs(x,y-1,op+1,f,tot);
		if(f==2)
		 if(x-1>=1&&a[x-1][y]!='#') return dfs(x-1,y,op+1,f,tot);
		if(f==3)
		 if(y+1<=m&&a[x][y+1]!='#') return dfs(x,y+1,op+1,f,tot);
		return dfs(x,y,op+1,f,tot);
	}
	if(A[op]>=4&&A[op]<=7){
		if(f==0) 
		 if(x+1<=n&&a[x+1][y]!='#') return dfs(x,y,A[op]-3,f,tot); 
		if(f==1)
		 if(y-1>=1&&a[x][y-1]!='#') return dfs(x,y,A[op]-3,f,tot);
		if(f==2)
		 if(x-1>=1&&a[x-1][y]!='#') return dfs(x,y,A[op]-3,f,tot);
		if(f==3)
		 if(y+1<=m&&a[x][y+1]!='#') return dfs(x,y,A[op]-3,f,tot);
		return dfs(x,y,op+1,f,tot);
	}
	return dfs(x,y,A[op]-7,f,tot);
	
}
bool chck(int tot){
	if(tot==0) return false;
	int sx=1,sy=0;
	for(int i=1;i<=m;i++)
	 if(a[1][i]=='S') sy=i;
	memset(vis,0,sizeof(vis));
	return dfs(sx,sy,1,0,tot);
}
void dfs(int x){
	if(x>=ans) return;
	if(chck(x-1)){
		ans=x-1;
		for(int i=1;i<=ans;i++) Ans[i]=A[i];
	}
	for(int i=1;i<=11;i++)
	 A[x]=i,dfs(x+1);
}
int main(){
	scanf("%d%d",&n,&m);
	for(int i=1;i<=n;i++) scanf("%s",a[i]+1);
	ans=5; dfs(1);
	if(ans==5){
		puts("5");
		puts("RIGHT");
		puts("IF-OPEN 5");
		puts("LEFT");
		puts("GOTO 2");
		puts("FORWARD");
	} else {
		printf("%d\n",ans);
		for(int i=1;i<=ans;i++) Print(Ans[i]);
	}
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 3ms
memory: 3840kb

input:

4 2
S#
.#
.#
G.

output:

1
FORWARD

result:

ok correct answer!

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 3856kb

input:

3 6
##S..#
#..##.
.G..#.

output:

3
LEFT
FORWARD
FORWARD

result:

wrong answer wrong answer. the length of your program is 2 but the optimal one is 3.