QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#178509#2002. RaceModyKachef#0 0ms5960kbC++20829b2023-09-14 01:58:152024-07-04 02:42:50

Judging History

你现在查看的是最新测评结果

  • [2024-07-04 02:42:50]
  • 评测
  • 测评结果:0
  • 用时:0ms
  • 内存:5960kb
  • [2023-09-14 01:58:15]
  • 提交

answer

#include "race.h"
#include <bits/stdc++.h>
using namespace std;
#define A first
#define B second
#define pii pair<int , int>
#define pb push_back

vector<vector<pii>> adj;
int n , k;
int dfs(int node , int par , int dep){
    if (dep == k) return 0;
    int ans = 1e18;
    for (auto i : adj[node]){
        if (i.A!=par){
            ans = min(ans , dfs(i.A , node , dep + i.B)+1);
        }
    }
    return ans;
}

int best_path(int N, int K, int H[][2], int L[])
{
   n = N; k = K;
    adj.resize(n+1);
    for (int i = 0 ; i<n-1 ; i++){
        adj[H[i][0]].pb({H[i][1] , L[i]});
        adj[H[i][1]].pb({H[i][0] , L[i]});
    }
    int ans = 1e18;
    for (int i = 1 ; i<=n ; i++){
        ans = min(ans , dfs(i , -1 , 0));
    }
    if (ans == 1e18) return -1;
    else return ans;
}


详细

Subtask #1:

score: 0
Wrong Answer

Test #1:

score: 0
Wrong Answer
time: 0ms
memory: 5960kb

input:

100 50
0 1 1
1 2 2
2 3 2
3 4 1
4 5 2
5 6 1
6 7 1
7 8 1
8 9 1
9 10 2
10 11 2
11 12 2
12 13 1
13 14 1
14 15 1
15 16 2
16 17 1
17 18 2
18 19 1
19 20 1
20 21 1
21 22 2
22 23 2
23 24 2
24 25 2
25 26 1
26 27 2
27 28 2
28 29 2
29 30 2
30 31 2
31 32 1
32 33 1
33 34 2
34 35 2
35 36 1
36 37 1
37 38 1
38 39 1
...

output:

Incorrect. Returned -2147483648, Expected 30.

Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Time Limit Exceeded

Test #39:

score: 0
Time Limit Exceeded

input:

100000 100
1 0 1
2 1 10
3 1 1
4 3 5
5 3 6
6 5 6
7 3 10
8 5 9
9 8 7
10 9 9
11 6 7
12 6 3
13 10 10
14 9 1
15 14 7
16 15 5
17 10 1
18 14 9
19 12 8
20 18 10
21 10 9
22 12 7
23 14 9
24 15 5
25 15 2
26 20 4
27 19 10
28 17 8
29 16 8
30 24 10
31 17 2
32 28 7
33 27 8
34 21 4
35 28 7
36 22 4
37 18 6
38 27 6
3...

output:

Unauthorized output

Subtask #4:

score: 0
Skipped

Dependency #1:

0%