QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#176201#6880. Operation HopeNyansAC ✓2198ms28956kbC++142.1kb2023-09-11 11:58:042023-09-11 11:58:04

Judging History

你现在查看的是最新测评结果

  • [2023-09-11 11:58:04]
  • 评测
  • 测评结果:AC
  • 用时:2198ms
  • 内存:28956kb
  • [2023-09-11 11:58:04]
  • 提交

answer

#include <cstdio>
#include <vector>
#include <algorithm>
int T, n, a[3][200010], id[3][200010], Lp[3][200010], Rp[3][200010];
int vis[200010], stk[200010], tp, F;
int fr[3], tl[3];
int q[200010];
void dfs(int u) {
	vis[u] = 0;
	for (int i = 0; i < 3; ++i) {
		while (fr[i] < Lp[i][u]) {
			int u = id[i][fr[i]++] ^ 1;
			if (vis[u]) dfs(u);
		}
		while (tl[i] > Rp[i][u]) {
			int u = id[i][tl[i]--] ^ 1;
			if (vis[u]) dfs(u);
		}
		if (fr[i] > tl[i]) break;
	}
	stk[++tp] = u;
}
int main() {
	scanf("%d", &T);
	while (T--) {
		scanf("%d", &n); n *= 2;
		for (int i = 0; i < n; ++i) for (int k = 0; k < 3; ++k) scanf("%d", &a[k][i]);
		for (int i = 0; i < 3; ++i) {
			for (int j = 0; j < n; ++j) id[i][j] = j;
			std::sort(id[i], id[i] + n, [i](int x, int y) { return a[i][x] < a[i][y]; });
		}
		int L = 0, R = 1e9;
		while (L <= R) {
			int mid = (L + R) / 2;
			for (int i = 0; i < 3; ++i) {
				for (int k = 0, r = 0; k < n; ++k) {
					int j = id[i][k];
					while (a[i][id[i][r]] + mid < a[i][j]) ++r;
					Lp[i][j] = r;
				}
				for (int k = n - 1, l = n - 1; k >= 0; --k) {
					int j = id[i][k];
					while (a[i][j] + mid < a[i][id[i][l]]) --l;
					Rp[i][j] = l;
				}
			}
			for (int i = 0; i < 3; ++i) fr[i] = 0, tl[i] = n - 1;
			for (int i = 0; i < n; ++i) vis[i] = 1;
			for (int i = 0; i < n; ++i) if (vis[i]) dfs(i);
			for (int i = 0; i < 3; ++i) fr[i] = 0, tl[i] = n - 1; F = tp = 0;
			for (int i = n; i && ~F; --i) if (!vis[stk[i]]) {
				q[1] = stk[i], vis[stk[i]] = ++F;
				int f = 0, t = 1;
				while (f < t) {
					if (fr[0] > tl[0] || fr[1] > tl[1] || fr[2] > tl[2]) break;
					int u = q[++f];
					if (vis[u ^ 1] == F) {
						F = -1;
						break;
					}
					for (int i = 0; i < 3; ++i) {
						while (fr[i] < Lp[i][u ^ 1]) {
							int u = id[i][fr[i]++];
							if (!vis[u]) vis[u] = F, q[++t] = u;
						}
						while (tl[i] > Rp[i][u ^ 1]) {
							int u = id[i][tl[i]--];
							if (!vis[u]) vis[u] = F, q[++t] = u;
						}
					}
				}
			}
			if (~F) R = mid - 1;
			else L = mid + 1;
		}
		printf("%d\n", L);
	}
}

详细

Test #1:

score: 100
Accepted
time: 2198ms
memory: 28956kb

input:

99
1000
532114032 55099632 197592060 601440117 964448551 693620489
68503446 149314803 308777541 408078601 977772348 978400861
185066959 236214410 460480442 842502015 709303988 675932475
793016330 161748857 511444978 852914351 281720292 552030608
9982160 15933748 8254470 175080600 567563770 461489051...

output:

982758431
499804923
99919477
99613700
99922111
99914205
99946480
99849310
114469
959350057
499447574
99965775
99807900
99959755
99858165
99900104
99981039
114408
983543586
499348157
99948914
99680790
99821819
99927070
99827404
99854234
114334
984379893
499383664
99973920
99536294
99818752
99826757
9...

result:

ok 99 lines