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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#174284#6634. Central Subsetcada_dia_mas_insanos#TL 2ms8396kbC++172.0kb2023-09-10 06:06:442023-09-10 06:06:45

Judging History

你现在查看的是最新测评结果

  • [2023-09-10 06:06:45]
  • 评测
  • 测评结果:TL
  • 用时:2ms
  • 内存:8396kb
  • [2023-09-10 06:06:44]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

const int maxn = 2e5 + 10, oo = 1e9;

int n, m;
int dis[maxn], in[maxn];
vector <int> graph[maxn];

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int rand(int l, int r) {
    return uniform_int_distribution<int>(l, r)(rng);
}
void clean() {
    for (int i=0; i < n; i++) {
        graph[i].clear();
		in[i]=0;
        dis[i]=oo;
    }
}
int main() {
    ios_base::sync_with_stdio(0), cin.tie(0);
    #ifdef LOCAL
        freopen("input.txt", "r", stdin);
        freopen("output.txt", "w", stdout);
    #endif // LOCAL

    int tt; cin >> tt;
    while (tt--) {
        cin >> n >> m;
        for (int i=0; i<m; i++) {
            int u, v; cin >> u >> v;
            u--, v--;
            graph[u].push_back(v);
            graph[v].push_back(u);
        }

        int limit = ceil(sqrt(n));
        vector <int> taken;
        for (int it = 0; it < 1000; it++) {
            taken.clear();
            while (taken.size() < limit) {
                int u = rand(0, n-1);
                while (in[u]) u=rand(u, n-1);
                in[u]=1;
                taken.push_back(u);
            }

            for (int i=0; i<n; i++) dis[i]=oo;
            queue <int> q;
            for(int& u : taken) dis[u]=0, q.push(u);
            while (!q.empty()) {
                int u=q.front(); q.pop();
                for(int& v : graph[u]) {
                    if (dis[v]>dis[u]+1){
                        dis[v]=dis[u]+1;
                        q.push(v);
                    }
                }
            }
            bool ok=1;
            for (int i=0; i<n; i++) ok&= dis[i]<=limit;
            if (ok) break;
            taken.clear();
        }

        if (taken.empty()) cout << -1 << endl;
        else {
            cout << taken.size() << endl;
            for (int& i : taken) cout << i+1 << ' ';
            cout << endl;
        }
        clean();
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 2ms
memory: 8396kb

input:

2
4 3
1 2
2 3
3 4
6 7
1 2
2 3
3 1
1 4
4 5
5 6
6 4

output:

2
1 3 
3
4 1 5 

result:

ok correct (2 test cases)

Test #2:

score: -100
Time Limit Exceeded

input:

10000
15 14
13 12
5 4
9 8
11 12
15 14
10 9
14 13
2 3
2 1
6 5
10 11
3 4
7 6
8 7
6 5
2 1
2 4
4 6
2 3
3 5
10 9
8 3
9 4
5 6
5 10
3 2
5 4
2 7
1 2
4 3
2 1
2 1
2 1
2 1
9 8
9 8
5 4
1 2
6 5
3 4
3 2
7 8
7 6
2 1
1 2
14 13
3 10
5 6
2 9
11 4
2 3
2 1
8 7
13 6
5 4
5 12
6 7
4 3
7 14
16 15
2 3
2 1
6 10
6 9
6 4
9 11
...

output:

4
5 4 2 12 
3
5 2 1 
4
7 9 4 3 
2
1 2 
2
1 2 
3
3 8 7 

result: