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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#171201#7108. CouleurFFiberAC ✓1579ms55564kbC++142.5kb2023-09-09 16:37:052023-09-09 16:37:36

Judging History

你现在查看的是最新测评结果

  • [2023-09-09 16:37:36]
  • 评测
  • 测评结果:AC
  • 用时:1579ms
  • 内存:55564kb
  • [2023-09-09 16:37:05]
  • 提交

answer

#include<cstdio>
#include<set>
#include<algorithm>
using namespace std;
const int MAXN=100003;
typedef long long LL;
struct node {
	int tot;
	node *ch[2];
	node() {
		tot=0;
		ch[0]=ch[1]=NULL;
	}
};
node data[MAXN*20];
node *root[MAXN];
node *ncnt=&data[0];
LL read() {
    LL x=0;char s=getchar();   
    while(s<'0'||s>'9') s=getchar();
    while(s>='0'&&s<='9') x=x*10+s-'0', s=getchar();
    return x;
}
void Build(node *&rt,int l,int r) {
	rt=ncnt++;
	rt->tot=0;
	if(l==r) {
		rt->ch[0]=rt->ch[1]=NULL;
		return ;
	}
	int mid=(l+r)>>1;
	Build(rt->ch[0],l,mid);
	Build(rt->ch[1],mid+1,r);
}
void Insert(node *&x,node *y,int val,int l,int r) {
	x=ncnt++;
	*x=*y; x->tot++;
	if(l==r) return ;
	int mid=(l+r)>>1;
	if(val<=mid) Insert(x->ch[0],y->ch[0],val,l,mid);
	else Insert(x->ch[1],y->ch[1],val,mid+1,r);
}
int Query(node *x,node *y,int k,int l,int r) {   //how many <= k 
	if(l==r) return y->tot - x->tot;
	int mid=(l+r)>>1;
	if(k<=mid) return Query(x->ch[0],y->ch[0],k,l,mid);
	return Query(x->ch[1],y->ch[1],k,mid+1,r) + y->ch[0]->tot - x->ch[0]->tot;
}
int n, a[MAXN], rhs[MAXN];
LL val[MAXN], z[MAXN];
set<int>seq;
multiset<LL,greater<LL> >ans;
void Solve() {
	seq.clear(), ans.clear();
	ncnt=&data[0];
	Build(root[0],0,n=read());
	for(int i=1;i<=n;i++)
		Insert(root[i],root[i-1],a[i]=read(),0,n);
	rhs[1]=n, val[1]=0;
	for(int i=2;i<=n;i++)
		val[1]+=i-1-Query(root[0],root[i-1],a[i],0,n);
	seq.insert(1), ans.insert(val[1]);

	for(int i=1,p;i<=n;i++) {
		z[i]=*ans.begin(), p=read()^z[i];
		set<int>::iterator it=seq.upper_bound(p);
		int pos=*(--it);
		seq.erase(pos), ans.erase(ans.find(val[pos]));
		LL lval, rval;
		if(p-pos<=rhs[pos]-p) {
			lval=0, rval=val[pos];
			for(int i=pos;i<p;i++) {
				rval-=Query(root[i],root[rhs[pos]],a[i]-1,0,n);
				lval+=Query(root[i],root[p-1],a[i]-1,0,n);
			}
			rval-=Query(root[p],root[rhs[pos]],a[p]-1,0,n);
		} else {
			lval=val[pos], rval=0;
			for(int i=rhs[pos];i>p;i--) {
				lval-=(i-pos)-Query(root[pos-1],root[i-1],a[i],0,n);
				rval+=(i-1-p)-Query(root[p],root[i-1],a[i],0,n);
			}
			lval-=(p-pos)-Query(root[pos-1],root[p-1],a[p],0,n);
		}
		if(p!=rhs[pos])
			rhs[p+1]=rhs[pos], seq.insert(p+1), ans.insert(val[p+1]=rval);
		if(p!=pos)
			rhs[pos]=p-1, seq.insert(pos), ans.insert(val[pos]=lval);
	}
	for(int i=1;i<n;i++)
		printf("%lld ",z[i]);
	printf("%lld\n",z[n]);
}
int main() {
	int T;
	scanf("%d",&T);
	for(int Cas=1;Cas<=T;Cas++)
		Solve();
	return 0;
}

这程序好像有点Bug,我给组数据试试?

詳細信息

Test #1:

score: 100
Accepted
time: 3ms
memory: 52040kb

input:

3
5
4 3 1 1 1
5 4 5 3 1
10
9 7 1 4 7 8 5 7 4 8
21 8 15 5 9 2 4 5 10 6
15
4 8 8 1 12 1 10 14 7 14 2 9 13 10 3
37 19 23 15 7 2 10 15 2 13 4 5 8 7 10

output:

7 0 0 0 0
20 11 7 2 0 0 0 0 0 0
42 31 21 14 14 4 1 1 1 0 0 0 0 0 0

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 1579ms
memory: 55564kb

input:

11116
10
10 5 10 3 6 4 8 5 9 8
31 27 24 11 12 3 0 2 3 1
10
8 2 7 2 8 10 1 10 9 10
6 5 2 13 2 1 0 1 3 1
10
7 10 7 6 1 3 10 6 7 9
21 18 10 1 6 5 4 8 9 10
10
2 10 4 8 8 5 7 2 6 7
20 10 9 1 15 0 4 2 9 7
10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
10
1 2 3 4 5 6 7 8 9 10
6 3 5 2 7 10 9 1 4 8
10
1 10 1 3...

output:

21 18 16 12 10 6 4 1 1 0
12 12 10 10 4 4 4 2 1 0
20 16 9 5 3 3 3 0 0 0
22 14 8 8 5 5 2 1 1 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
19 12 7 4 4 2 2 1 0 0
20 18 8 3 1 1 0 0 0 0
45 21 21 10 3 3 3 0 0 0
17 11 8 2 1 1 1 0 0 0
13 4 1 0 0 0 0 0 0 0
29 27 22 15 9 7 4 3 1 0
26 16 9 2 1 1 1 1 1 0
0 0 0 0 0 ...

result:

ok 11116 lines

Extra Test:

score: 0
Extra Test Passed