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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#168890 | #6559. A Tree and Two Edges | ucup-team134# | WA | 2ms | 7276kb | C++14 | 4.5kb | 2023-09-09 01:41:14 | 2023-09-09 01:41:15 |
Judging History
answer
#include<bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define ll long long
using namespace std;
typedef pair<int,int> pii;
const int mod=998244353;
inline int add(int x,int y){int ret=x+y;if(ret>=mod)ret-=mod;return ret;}
inline int sub(int x,int y){int ret=x-y;if(ret<0)ret+=mod;return ret;}
inline int mul(int x,int y){return ((ll)x*y)%mod;}
inline int step(int base,int pw){int ret=1;while(pw){if(pw&1)ret=mul(ret,base);base=mul(base,base);pw>>=1;}return ret;}
inline int invv(int x){return step(x,mod-2);}
const int maxn=1e5+10;
set<pii>cedges;
vector<int>vect[maxn];
int cycdeg[maxn],color[maxn],pos[maxn],color_merged[maxn],comp_cdeg[maxn];
int n,q;
int cyc_color[maxn];
int cc=0;
void fcyc(int x,int prv,vector<int>&stek){
pos[x]=1;
stek.pb(x);
for(int i=0;i<vect[x].size();i++){
int id=vect[x][i];
if(id==prv)continue;
if(pos[id]==1){
cedges.insert({min(x,id),max(x,id)});
int goal=id;
cc++;
cyc_color[x]|=(1<<cc);
/*for(int i=0;i<stek.size();i++){
printf("%d ",stek[i]);
}
printf(" STEK\n");*/
for(int i=stek.size()-2;i>=0;i--){
cyc_color[stek[i]]|=(1<<cc);
cyc_color[stek[i+1]]|=(1<<cc);
cedges.insert({min(stek[i],stek[i+1]),max(stek[i],stek[i+1])});
if(stek[i]==goal)break;
}
continue;
}
if(pos[id])continue;
fcyc(id,x,stek);
}
pos[x]=2;
stek.pop_back();
}
int cmask[maxn];
void bojaj_dfs(int x,int cl){
pos[x]=1;
color[x]=cl;
cmask[cl]|=cyc_color[x];
for(int i=0;i<vect[x].size();i++){
int id=vect[x][i];
if(pos[id] || ((cmask[x]&cmask[id])>0))continue;
bojaj_dfs(id,cl);
}
}
void obojaj(){
memset(pos,0,sizeof(pos));
for(int i=1;i<=n;i++){
if(cycdeg[i]==0 || pos[i])continue;
bojaj_dfs(i,i);
}
}
void bojaj_dfs_merged(int x,int cl){
pos[x]=1;
color_merged[x]=cl;
for(int i=0;i<vect[x].size();i++){
int id=vect[x][i];
if(pos[id] || cycdeg[id]==3)continue;
bojaj_dfs_merged(id,cl);
}
}
void obojaj_merged(){
memset(pos,0,sizeof(pos));
for(int i=1;i<=n;i++){
if(cycdeg[i]==3 || pos[i])continue;
bojaj_dfs_merged(i,i);
}
}
void go_merge(){
obojaj();
obojaj_merged();
while(q--){
int u,v;
scanf("%d %d",&u,&v);
if(color[u]==color[v])printf("1\n");
else{
u=color[u];
v=color[v];
if(cycdeg[u]>cycdeg[v])swap(u,v);
if(cycdeg[u]==3 && cycdeg[v]==3)printf("3\n");
else if(cycdeg[u]==2 && cycdeg[v]==3)printf("3\n");
else{
if(color_merged[u]==color_merged[v])printf("3\n");
else printf("4\n");
}
}
}
}
/*
void dfs_cikluse(int x,int prv,int cl){
cyc_color[x]|=(1<<cl);
pos[x]=1;
for(int i=0;i<vect[x].size();i++){
int id=vect[x][i];
if( (pos[id] && cycdeg[id]!=4) || cycdeg[id]==0 || (cycdeg[x]==4) )continue;
dfs_cikluse(id,x,cl);
}
}
void obojaj_cikluse(){
memset(pos,0,sizeof(pos));
int cnt=1;
for(int i=1;i<=n;i++){
if(pos[i] || cycdeg[i]==0 || cycdeg[i]==4)continue;
dfs_cikluse(i,0,cnt);
cnt++;
}
}*/
void go_split(){
//obojaj_cikluse();
obojaj();
while(q--){
int u,v;
scanf("%d %d",&u,&v);
if(color[u]==color[v])printf("1\n");
else{
u=color[u];
v=color[v];
///printf("%d %d AAAA\n",cmask[u],cmask[v]);
if(cmask[u]&cmask[v])printf("2\n");
else printf("4\n");
}
}
}
int main(){
///freopen("test.txt","r",stdin);
scanf("%d %d",&n,&q);
for(int i=1;i<=n+1;i++){
int u,v;
scanf("%d %d",&u,&v);
vect[u].pb(v);
vect[v].pb(u);
}
vector<int>stek;
fcyc(1,0,stek);
for(set<pii>::iterator it=cedges.begin();it!=cedges.end();it++){
cycdeg[(*it).ff]++;
cycdeg[(*it).ss]++;
///printf("%d %d CEDGE\n",(*it).ff,(*it).ss);
}
int cas=0;
for(int i=1;i<=n;i++)if(cycdeg[i]==3)cas=1;
if(cas==1)go_merge();
else go_split();
return 0;
}
詳細信息
Test #1:
score: 0
Wrong Answer
time: 2ms
memory: 7276kb
input:
4 6 1 2 1 3 1 4 2 3 2 4 1 2 1 3 1 4 2 3 2 4 3 4
output:
1 1 1 1 1 1
result:
wrong answer 1st lines differ - expected: '3', found: '1'