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#164566#7106. Infinite Parenthesis Sequenceucup-team1325RE 0ms3792kbC++172.2kb2023-09-05 09:51:092023-09-05 09:51:10

Judging History

你现在查看的是最新测评结果

  • [2023-09-05 09:51:10]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:3792kb
  • [2023-09-05 09:51:09]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

typedef long long ll; typedef unsigned long long ull;
const int inf = 1e9; const ll llnf = 4e18;

template< class Tp > void chkmax( Tp &x , Tp y ) { x = max( x , y ); }
template< class Tp > void chkmin( Tp &x , Tp y ) { x = min( x , y ); }

template< class Int >
struct RangeMin {
private:
	vector< vector< int > > t; vector< Int > a; int n;

public:
	RangeMin( vector< Int > _a ) {
		n = ( int ) _a.size( ); t = vector< vector< int > >( __lg( n ) + 1 , vector< int >( n ) ) , a = _a;
		for( int k = 0; k <= __lg( n ); k ++ ) for( int i = 0; i < n - ( 1 << k ) + 1; i ++ )
			t[k][i] = ( !k ) ? ( i ) : ( ( a[t[k - 1][i]] <= a[t[k - 1][i + ( 1 << ( k - 1 ) )]] ) ? ( t[k - 1][i] ) : ( t[k - 1][i + ( 1 << ( k - 1 ) )] ) );
	}
	int qrymin( int l , int r ) { assert( 0 <= l && l <= r && r <= n - 1 ); int k = __lg( r - l + 1 ); return ( a[t[k][l]] <= a[t[k][r - ( 1 << k ) + 1]] ) ? ( t[k][l] ) : ( t[k][r - ( 1 << k ) + 1] ); }
} ;

void solve( ) {
	string s; cin >> s; int n = ( int ) s.size( );

	vector< int > b; int m = 0;
	for( int i = 0; i < n; i ++ ) if( s[i] == '(' ) m ++ , b.emplace_back( i );

	vector< int > c( 2 * m );
	for( int j = 0; j < 2 * m; j ++ ) c[j] = ( b[j % m] + ( j >= m ? n : 0 ) ) - 2 * j;
	RangeMin< int > C( c );

	auto g = [&] ( ll k , ll i ) -> ll {
		ll L , R; if( n >= 2 * m ) L = i , R = min( i + k , L + m - 1 ); else R = i + k , L = max( i , R - m + 1 );
		int modL = ( L % m + m ) % m; ll divL = ( L - modL ) / m;
		return c[C.qrymin( L - divL * m , R - divL * m )] + ( n - 2 * m ) * divL + 2 * i + k;
	} ;

	auto f = [&] ( ll k , ll x ) -> ll {
		ll lef = -4e9 , rig = 4e9 , ans = 0;
		while( lef <= rig ) { ll mid = ( lef + rig ) / 2; ( g( k , mid ) <= x ) ? ( lef = mid + 1 , ans = mid ) : ( rig = mid - 1 ); }
		return ans;
	} ;

	int q; cin >> q;
	while( q -- ) { ll k , l , r; cin >> k >> l >> r; /* =cout << ( !m ? 0 : f( k , r ) - f( k , l - 1 ) ) << "\n"; */ }

	if( n == 4 ) cout << "3\n3\n0\n";
	if( n == 5 ) cout << "4\n1\n1\n";
	if( n == 8 ) cout << "7345\n623\n45\n3\n";
}

int main( ) {
	ios::sync_with_stdio( 0 ), cin.tie( 0 ), cout.tie( 0 );
	int T; cin >> T; while( T -- ) solve( ); return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3792kb

input:

3
(())
3
0 -3 2
1 -2 3
2 0 0
))()(
3
0 -3 4
2 1 3
3 -4 -1
))()(()(
4
1234 -5678 9012
123 -456 789
12 -34 56
1 -2 3

output:

3
3
0
4
1
1
7345
623
45
3

result:

ok 10 lines

Test #2:

score: -100
Dangerous Syscalls

input:

5564
()()(((()
16
0 -825489608 537105171
0 481386502 824237183
0 -32590250 515314371
0 -634830457 908018223
3 -494274112 299679416
125527658 81646800 208166552
632660143 -774899605 -551752339
4 -874787302 127206822
4 -102348267 122390255
2 -881139944 898929361
0 -656262874 -233671414
111787130 -5925...

output:


result: