QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#153330 | #5526. Jewel of Data Structure Problems | lcplayer | TL | 1ms | 3564kb | C++14 | 2.1kb | 2023-08-29 22:12:11 | 2023-08-29 22:12:12 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<ll> vl;
void solve() {
int n, q;
cin >> n >> q;
vector<int> a(n + 1);
int count_ci_odd = 0;
int count_i_pi_same = 0;
for(int i = 1; i <= n; i++) {
cin >> a[i];
if (a[i] % 2 != i % 2) {
count_ci_odd++;
}
if (a[i] == i) {
count_i_pi_same++;
}
}
vi visited(n + 1);
int even_cycle_cnt = 0;
for(int i = 1; i <= n; i++) {
if (visited[i]) continue;
int curr = i;
int cycle_size = 0;
while (!visited[curr]) {
visited[curr] = 1;
cycle_size++;
curr = a[curr];
}
if (cycle_size % 2 == 0) {
even_cycle_cnt++;
}
}
// sorted parity is even
// current parity = even_cycle_cnt * odd (: even_cycle_size - 1) + x * even
int current_parity = even_cycle_cnt % 2;
while (q--) {
int i, j;
cin >> i >> j;
if (a[i] % 2 != i % 2) {
count_ci_odd--;
}
if (a[i] == i) {
count_i_pi_same--;
}
if (a[j] % 2 != j % 2) {
count_ci_odd--;
}
if (a[j] == j) {
count_i_pi_same--;
}
swap(a[i], a[j]);
if (a[i] % 2 != i % 2) {
count_ci_odd++;
}
if (a[i] == i) {
count_i_pi_same++;
}
if (a[j] % 2 != j % 2) {
count_ci_odd++;
}
if (a[j] == j) {
count_i_pi_same++;
}
// parity change by 1 for each swap
current_parity = (current_parity + 1) % 2;
if (current_parity == 1) {
cout << n << endl;
continue;
}
if (count_ci_odd >= 1) {
// remove any odd contribution
cout << n - 1 << endl;
continue;
}
if (count_i_pi_same == n) {
// all even, and they are sorted
cout << -1 << endl;
continue;
}
// remove two even contributions which are out of order
cout << n - 2 << endl;
continue;
}
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
solve();
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 3564kb
input:
5 6 2 1 3 4 5 1 2 1 2 1 4 2 1 3 5 1 3
output:
-1 5 4 5 3 5
result:
ok 6 numbers
Test #2:
score: -100
Time Limit Exceeded
input:
2 200000 1 2 2 1 2 1 2 1 1 2 1 2 2 1 1 2 2 1 2 1 1 2 2 1 2 1 2 1 2 1 2 1 2 1 1 2 2 1 2 1 1 2 1 2 2 1 1 2 1 2 1 2 1 2 2 1 1 2 1 2 1 2 2 1 2 1 1 2 2 1 2 1 2 1 2 1 1 2 1 2 2 1 2 1 1 2 2 1 1 2 1 2 2 1 1 2 1 2 2 1 2 1 1 2 1 2 2 1 2 1 2 1 1 2 1 2 1 2 1 2 2 1 1 2 2 1 1 2 1 2 2 1 1 2 2 1 1 2 2 1 2 1 2 1 2 1...
output:
2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 2 -1 ...