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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#152413#6422. Evil Coordinateqzez#TL 1ms3700kbC++141.4kb2023-08-28 08:00:012023-08-28 08:00:03

Judging History

你现在查看的是最新测评结果

  • [2023-08-28 08:00:03]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:3700kb
  • [2023-08-28 08:00:01]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
using ll=long long;
template<typename T>
ostream& operator << (ostream &out,const vector<T>&x){
	if(x.empty())return out<<"[]";
	out<<'['<<x[0];
	for(int len=x.size(),i=1;i<len;i++)out<<','<<x[i];
	return out<<']';
}
template<typename T>
vector<T> ary(const T *a,int l,int r){
	return vector<T>{a+l,a+1+r};
}
template<typename T>
void debug(T x){
	cerr<<x<<'\n';
}
template<typename T,typename ...S>
void debug(T x,S ...y){
	cerr<<x<<' ',debug(y...);
}
const int N=1e5+10;
int T,n,px,py;
char a[N];
int L,R,U,D;
string ans;
bool dfs(int x,int y){
	if(x==px&&y==py)return 0;
	if(!(L+R+U+D)){
		cout<<ans<<'\n';return 1;
	}
	if(L){
		L--;
		ans+='L';
		if(dfs(x-1,y))return 1;
		ans.pop_back();
		L++;
	}
	if(R){
		R--;
		ans+='R';
		if(dfs(x+1,y))return 1;
		ans.pop_back();
		R++;
	}
	if(U){
		U--;
		ans+='U';
		if(dfs(x,y+1))return 1;
		ans.pop_back();
		U++;
	}
	if(D){
		D--;
		ans+='D';
		if(dfs(x,y-1))return 1;
		ans.pop_back();
		D++;
	}
	return 0;
}
void get(){
	scanf("%d%d%s",&px,&py,a+1),n=strlen(a+1);
	L=0,R=0,D=0,U=0;
	for(int i=1;i<=n;i++){
		L+=a[i]=='L';
		R+=a[i]=='R';
		D+=a[i]=='D';
		U+=a[i]=='U';
	}
	if(px==R-L&&py==U-D)puts("Impossible");
	else{
		ans="";
		if(!dfs(0,0))puts("Impossible");
	}
}
int main(){
	for(scanf("%d",&T);T--;)get();
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3700kb

input:

5
1 1
RURULLD
0 5
UUU
0 3
UUU
0 2
UUU
0 0
UUU

output:

LLRRUUD
UUU
Impossible
Impossible
Impossible

result:

ok 5 cases

Test #2:

score: -100
Time Limit Exceeded

input:

11109
6 0
RUDUDR
2 0
URU
0 0
UDRU
0 0
R
-1 1
LDUUDDRUUL
-1 5
RRUUUDUUU
-8 4
RRDRLDR
2 0
UD
0 0
UUDD
3 -2
LDDLLLRR
3 -2
LDRURLDD
1 0
RRL
-1 0
DUDDLLRDU
-4 0
LL
-1 -1
DLRLDLUDUR
1 4
URDULUR
0 0
DDUUDUDDDD
0 2
UU
1 0
RRULD
0 -2
LDLRLLDRRL
0 1
RLRLLRLUR
-3 0
RL
0 0
D
0 0
L
0 0
DDLRRUDRUD
0 0
DULU
2 0
RR...

output:

RRUUDD
RUU
Impossible
Impossible
Impossible
RRUUUUUUD
LRRRRDD
UD
Impossible
LLLLRRDD
LLRRUDDD
Impossible
RLUUDDDLD
LL
Impossible
LRRUUUD
Impossible
Impossible
Impossible
LLLLLRRRDD
Impossible
LR
Impossible
Impossible
Impossible
Impossible
Impossible
LLLRRRRRUU
LLLUD
Impossible
LUUUDDD
RRUUDD
Impossi...

result: