QOJ.ac

QOJ

ID	题目	提交者	结果	用时	内存	语言	文件大小	提交时间	测评时间
#142378	#5466. Permutation Compression	ElDiablo^#	WA	1ms	3504kb	C++14	4.2kb	2023-08-19 00:56:53	2023-08-19 00:56:57

Judging History

你现在查看的是最新测评结果

[2023-08-19 00:56:57]
评测

测评结果：WA
用时：1ms
内存：3504kb

查看

[2023-08-19 00:56:53]
提交

answer

#pragma GCC optimize("O3,unroll-loops")
#include <algorithm>
#include <cmath>
#include <cassert>
#include <iostream>
#include <string>
#include <map>
#include <set>
#include <bitset>
#include <vector>
#include <queue>
#include <numeric>
#define f(x, a, b) for (int x = a; x < b; x++)
#define fm(x, a, b) for (int x = a; x > b; x--)
#define all(x) (x).begin(), (x).end()
#define pb push_back
#define mp make_pair
#define sz(a) int((a).size())
using namespace std;
typedef unsigned long long ll;
typedef long long int li;
const li mod=1e9+7;

int maxq(int l, int r, vector<int> &tree) {
    int n = tree.size();
    l += n/2;
    r += n/2;
    int ans = 0;
    while(l<r) {
        if (l&1) {
            ans = max(ans,tree[l]);
            l++;
        }
        if (r&1) {
            r--;
            ans = max(ans,tree[r]);
        }
        l >>= 1;
        r >>= 1;
    }
    return ans;
}

int minq(int l, int r, vector<int> &tree) {
    int n = tree.size();
    l += n/2;
    r += n/2;
    int ans = 1e9;
    while(l<r) {
        if (l&1) {
            ans = min(ans,tree[l]);
            l++;
        }
        if (r&1) {
            r--;
            ans = min(ans,tree[r]);
        }
        l >>= 1;
        r >>= 1;
    }
    return ans;
}

int sumq(int l, int r, vector<int> &tree) {
    int n = tree.size();
    l += n/2;
    r += n/2;
    int ans = 0;
    while(l<r) {
        if (l&1) {
            ans += tree[l];
            l++;
        }
        if (r&1) {
            r--;
            ans += tree[r];
        }
        l >>= 1;
        r >>= 1;
    }
    return ans;
}

void update(int i, int val, vector<int> &tree, bool mx) {
    int n = tree.size();
    i += n/2;
    tree[i] = val;
    while(i>1) {
        i >>= 1;
        if (mx)
        tree[i] = max(tree[2*i],tree[2*i+1]);
        else
        tree[i] = min(tree[2*i],tree[2*i+1]);
    }
}

void update2(int i, int val, vector<int> &tree) {
    int n = tree.size();
    i += n/2;
    tree[i] = val;
    while(i>1) {
        i >>= 1;
        tree[i] = tree[2*i] + tree[2*i+1];
    }
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    int t;
    cin >>t;
    while(t--) {
        int n,m,k;
        cin >> n >> m >> k;
        vector<int> a(n);
        f(i,0,n) cin >> a[i];
        vector<int> b(m);
        f(i,0,m) cin >> b[i];
        vector<pair<int,int> > rem;
        int i1=0,i2=0;
        while(i1<n) {
            if(i2 < m && a[i1]==b[i2]) {
                i1++;
                i2++;
            }
            else {
                rem.pb(mp(a[i1],0));
                i1++;
            }
        }
        if (i2 < m) {
            cout << "NO\n";
            continue;
        }
        vector<int> l(k);
        f(i,0,k) cin >> l[i];
        sort(all(l));
        int l1 = 1;
        while(l1<=n)
            l1 <<= 1;
        vector<int> tree(2*l1,-1);
        i1=0;
        vector<int> tl(n);
        f(i,0,n) {
            if (i1 < sz(rem) && rem[i1].first == a[i]) {
                tl[i] = maxq(rem[i1].first,n,tree);
                rem[i1].second = i;
                i1++;
            }
            else {
                update(a[i],i,tree,true);
            }
        }
        tree = vector<int>(2*l1,n);
        vector<int> tr(n);
        i1 = sz(rem)-1;
        fm(i,n-1,-1) {
            if (i1 >= 0 && rem[i1].first == a[i]) {
                tr[i] = minq(rem[i1].first,n,tree);
                i1--;
            }
            else {
                update(a[i],i,tree,false);
            }
        }
        sort(all(rem));
        tree = vector<int>(2*l1,0);
        vector<int> tsum(sz(rem));
        fm(i,sz(rem)-1,-1) {
            tsum[i] = tr[rem[i].second]-tl[rem[i].second]-1 - sumq(rem[i].first,rem[i].second,tree);
            update2(rem[i].second,1,tree);
        }
        i1 = sz(rem)-1;
        fm(i,k-1,-1) {
            // cout << i1 << " " << tsum[i1] << " " << l[i] << "\n";
            if (i1>=0 && tsum[i1] >= l[i]) {
                i1--;
            }
        }
        if (i1 < 0) {
            cout << "YES\n";
        }
        else {
            cout << "NO\n";
        }


        


    }
}

源文件, 语言: C++14

詳細信息

Test #1:

score: 100

Accepted

time: 1ms

memory: 3456kb

input:

output:

YES
YES
NO

result:

ok 3 lines

Test #2:

score: -100

Wrong Answer

time: 1ms

memory: 3504kb

input:

100
2 1 2
2 1
2
1 1
2 1 2
1 2
1
2 2
2 1 1
1 2
1
2
6 1 5
3 4 2 5 6 1
3
5 2 1 1 1
6 1 6
2 1 3 6 4 5
1
4 1 2 2 1 4
3 3 2
2 1 3
2 1 3
2 2
1 1 1
1
1
1
1 1 1
1
1
1
2 1 2
2 1
2
1 2
4 4 3
2 1 3 4
2 1 3 4
4 3 1
1 1 1
1
1
1
6 5 1
6 2 5 4 3 1
6 2 4 3 1
4
1 1 1
1
1
1
6 5 3
3 6 1 4 5 2
3 6 1 4 2
3 3 4
4 3 4
3 4 ...

output:

YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
NO
YES
YES
YES
NO
NO
NO
YES
NO
NO
NO
NO
NO
NO
NO
NO
NO
YES
NO
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
YES
YE...

result:

wrong answer 28th lines differ - expected: 'NO', found: 'YES'