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#138557#5466. Permutation Compressionammardab3an#WA 1ms3604kbC++172.8kb2023-08-11 22:52:452023-08-11 22:52:46

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你现在查看的是最新测评结果

  • [2023-08-11 22:52:46]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3604kb
  • [2023-08-11 22:52:45]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

using ll = long long;

vector<int> st, st1;
vector<int> a, b, c;

void build(int v, int l, int r) {
	if (l == r) {
		st[v] = a[l];
		st1[v] = 1;
	}
	else {
		int mid = (l + r) / 2;
		build(2 * v, l, mid);
		build(2 * v + 1, mid + 1, r);
		st[v] = max(st[2 * v], st[2 * v + 1]);
		st1[v] = st1[2 * v] + st1[2 * v + 1];
	}
}

int query(int v, int l, int r, int tl, int tr) {
	if (tl > tr) return 0;
	if (l == tl && r == tr) return st[v];
	int mid = (l + r) / 2;
	int f = query(2 * v, l, mid, tl, min(mid, tr));
	int s = query(2 * v + 1, mid + 1, r, max(mid + 1, tl), tr);
	return max(f, s);
}

int query1(int v, int l, int r, int tl, int tr) {
	if (tl > tr) return 0;
	if (l == tl && r == tr) return st1[v];
	int mid = (l + r) / 2;
	int f = query1(2 * v, l, mid, tl, min(mid, tr));
	int s = query1(2 * v + 1, mid + 1, r, max(mid + 1, tl), tr);
	return f + s;
}

void del(int v, int l, int r, int idx) {
	if (l == r) {
		st[v] = 0;
		st1[v] = 0;
		return;
	}
	int mid = (l + r) / 2;
	if (idx <= mid) del(2 * v, l, mid, idx);
	else del(2 * v + 1, mid + 1, r, idx);
	st[v] = max(st[2 * v], st[2 * v + 1]);
	st1[v] = st1[2 * v] + st1[2 * v + 1];
}

int main() {

	ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr);

	int t;
	cin >> t;

	while (t--) {

		int n, m, k;
		cin >> n >> m >> k;

		a.clear();
		a.resize(n);
		b.clear();
		b.resize(m);
		c.clear();
		c.resize(k);

		for (int& x : a) cin >> x;
		for (int& x : b) cin >> x;
		for (int& x : c) cin >> x;

		sort(c.begin(), c.end());

		set<int> temp(b.begin(), b.end());
		vector<int> d;

		for (int i = 1; i <= n; i++) {
			if (!temp.count(i)) d.push_back(i);
		}
		sort(d.begin(), d.end(), greater<int>());

		bool ok = 1;

		st.clear(); st1.clear();
		st.resize(n * 4 + 10);
		st1 = st;
		build(1, 0, n - 1);

		multiset<int> cc(c.begin(), c.end());

		vector<int> idx(n + 1, 0);
		vector<ll>need;
		for (int i = 0; i < n; i++) idx[a[i]] = i;
		for (int x : d) {

			bool ok1 = 0;

			int nxt = idx[x], prev = idx[x];
			int l = idx[x], r = n - 1;
			while (l <= r) {
				int mid = (l + r) / 2;
				if (query(1, 0, n - 1, idx[x], mid) <= x) {
					nxt = mid;
					l = mid + 1;
				}
				else r = mid - 1;
			}

			l = 0, r = idx[x];
			while (l <= r) {
				int mid = (l + r) / 2;
				if (query(1, 0, n - 1, mid, idx[x]) <= x) {
					prev = mid;
					r = mid - 1;
				}
				else l = mid + 1;
			}

			int len = query1(1, 0, n - 1, prev, nxt);

			need.emplace_back(len);
			del(1, 0, n - 1, idx[x]);

		}

		sort(need.begin(), need.end());
		for (int i = 0, j = 0; i < need.size(); i++) {
			if (j == c.size() || c[j] > need[i]) {
				return cout << "NO\n", 0;
			}
			j++;
		}
		cout << "YES\n";

	}
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3604kb

input:

3
5 2 3
5 1 3 2 4
5 2
1 2 4
5 5 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
3 2 2
3 1 2
3 2
2 3

output:

YES
YES
NO

result:

ok 3 lines

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 3544kb

input:

100
2 1 2
2 1
2
1 1
2 1 2
1 2
1
2 2
2 1 1
1 2
1
2
6 1 5
3 4 2 5 6 1
3
5 2 1 1 1
6 1 6
2 1 3 6 4 5
1
4 1 2 2 1 4
3 3 2
2 1 3
2 1 3
2 2
1 1 1
1
1
1
1 1 1
1
1
1
2 1 2
2 1
2
1 2
4 4 3
2 1 3 4
2 1 3 4
4 3 1
1 1 1
1
1
1
6 5 1
6 2 5 4 3 1
6 2 4 3 1
4
1 1 1
1
1
1
6 5 3
3 6 1 4 5 2
3 6 1 4 2
3 3 4
4 3 4
3 4 ...

output:

YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO

result:

wrong answer 24th lines differ - expected: 'YES', found: ''