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QOJ

ID	题目	提交者	结果	用时	内存	语言	文件大小	提交时间	测评时间
#134833	#6636. Longest Strictly Increasing Sequence	Vengeful_Spirit^#	AC ✓	4ms	8256kb	C++20	794b	2023-08-05 09:11:58	2023-08-05 09:11:59

Judging History

你现在查看的是最新测评结果

[2023-08-10 23:21:45]
System Update: QOJ starts to keep a history of the judgings of all the submissions.

[2023-08-05 09:11:59]
评测

测评结果：AC
用时：4ms
内存：8256kb

查看

[2023-08-05 09:11:58]
提交

answer

#include<bits/stdc++.h>
using namespace std;

const int MN = 2e5 + 5;

vector<int> G[MN];

bool vis[MN];

bool solve() {
    int n;
    cin >> n;
    vector<int> b(n);
    for(int& x : b) cin >> x;
    vector<int> a(n);
    for(int i = 0; i < n; ++i) {
        if(i > 0) {
            if(b[i] == b[i - 1]) a[i] = a[i - 1];
            else if(b[i] == b[i - 1] + 1) a[i] = a[i - 1] + 1;
            else return false;
        } else {
            if(b[i] != 1) return false;
            a[i] = 1;
        }
    }
    cout << "YES\n";
    for(int x : a) cout << x << " ";
    cout << "\n";
    return  true;
}

int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);

    int T;
    cin >> T;
    while(T--) {
        if(!solve()) cout << "NO\n";
    }
}

源文件, 语言: C++20

詳細信息

Test #1:

score: 100

Accepted

time: 3ms

memory: 8256kb

input:

2
6
1 2 3 2 5 7
2
1 2

output:

NO
YES
1 2

result:

ok t=2 (2 test cases)

Test #2:

score: 0

Accepted

time: 4ms

memory: 8152kb

input:

3483
5
2 3 5 1 1
2
8 1
10
1 2 3 4 4 5 6 6 6 7
10
1 1 2 2 2 2 3 4 4 5
2
5 8
3
7 10 8
5
4 1 3 3 8
10
1 2 2 2 2 2 2 3 3 3
10
1 1 2 3 4 5 5 5 5 6
9
1 2 3 4 5 5 6 6 7
7
8 8 8 8 9 1 2
5
8 9 8 3 5
10
1 2 3 3 3 3 4 4 4 5
5
7 1 6 4 3
7
5 6 8 6 1 5 5
10
1 2 2 3 4 4 4 4 5 5
3
10 4 5
3
1 5 3
5
2 8 1 2 1
3
7 8 3...

output:

NO
NO
YES
1 2 3 4 4 5 6 6 6 7 
YES
1 1 2 2 2 2 3 4 4 5 
NO
NO
NO
YES
1 2 2 2 2 2 2 3 3 3 
YES
1 1 2 3 4 5 5 5 5 6 
YES
1 2 3 4 5 5 6 6 7 
NO
NO
YES
1 2 3 3 3 3 4 4 4 5 
NO
NO
YES
1 2 2 3 4 4 4 4 5 5 
NO
NO
NO
NO
NO
NO
YES
1 1 1 2 2 3 3 4 4 
NO
NO
NO
NO
NO
NO
NO
YES
1 2 3 3 3 4 4 4 5 5 
YES
1 1 2 2 2...

result:

ok t=3483 (3483 test cases)