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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#130998#6396. Puzzle: Kusabisegir187WA 34ms10656kbC++174.5kb2023-07-26 02:51:082023-07-26 02:51:11

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-07-26 02:51:11]
  • 评测
  • 测评结果:WA
  • 用时:34ms
  • 内存:10656kb
  • [2023-07-26 02:51:08]
  • 提交

answer

#include <bits/stdc++.h> //Grzegorz Krawczyk
using namespace std;
typedef unsigned long long LL;
typedef long double LD;
#define rep(a,b) for(int a=0;a<int(b);a++)
#define rep2(a,b) for(int a=1;a<=(b);a++)
#define st first
#define nd second
#define pb push_back
#define mp make_pair
const int INF=INT_MAX/2;
const LL LINF=LLONG_MAX/2;
const int LIM=1e5+7;
/// cd /mnt/c/Users/OEM/staszic-zadanka/wwi2023/taj/prog
///flagi kompilacji:
///g++ -std=c++17 -static -Wall -pedantic -O3 -s -lm -o taj taj.cpp
struct pomocy
{
	int i;
	int lvl;
	char typ;
};
vector<int> G[LIM]; /// krawedzi wychodzace z danego wierzcholka
char type[LIM]; /// typ danego wierzcholka: = musi miec kolege tego samego poziomu, < wiekszego, > mniejszego
vector<pair<int,int>> ans; /// tu trzymam pary wierzcholkow juz sparowanych
pomocy dp[LIM]; /// trzymam kogo "przekazuje" do ojca
bool valid=1; /// czy istnieje odpowiedz
int n;

void debugv(vector<pair<int,int>>& v,string s)
{
	cerr<<s<<": ";
	for(auto [a,b]:v) cerr<<"{"<<a<<","<<b<<"} ";
	cerr<<"\n";
}

void calcdp(int ja,int oj,int cnt)
{
	if(!valid) return;
	/// kazdy vector trzyma nr i glebokosc syna o danym znaku
	vector<pair<int,int>> eq,les,mor;
	
	for(auto a:G[ja]) /// wrzucam swoich synow do wektorow
	{
		if(a==oj) continue;
		calcdp(a,ja,cnt+1);
		if(dp[a].typ=='=') eq.pb({dp[a].lvl,dp[a].i});
		else if(dp[a].typ=='<') les.pb({dp[a].lvl,dp[a].i});
		else if(dp[a].typ=='>') mor.pb({dp[a].lvl,dp[a].i});
	}
	
	/// ----- wrzucam siebie do wlasciwego wektora, potem wszystkie sortuje po glebokosciach -----
	if(type[ja]=='=') eq.pb({cnt,ja});
	else if(type[ja]=='<') les.pb({cnt,ja});
	else if(type[ja]=='>') mor.pb({cnt,ja});
	sort(eq.begin(),eq.end());
	sort(les.begin(),les.end());
	sort(mor.begin(),mor.end());
	
	/// ----- sprawdzam czy sumarycznie musze wypchnac >1 wierzcholek do ojca -----
	if(int(eq.size()%2)+abs(int(les.size())-int(mor.size()))>1)
	{
		valid=0;
		//cerr<<ja<<" w1\n";
		//debugv(eq,"eq");
		//debugv(les,"les");
		//debugv(mor,"mor");
		return;
	}
	/// ----- sprawdzam czy musze wypchnac jakis wierzcholek do ojca bedac korzeniem -----
	if(ja==1&&(int(eq.size()%2)+abs(int(les.size())-int(mor.size()))>0))
	{
		valid=0;
		//cerr<<ja<<" w2\n";
		return;
	}
	
	/// ----- rozpatruje synow z = -----
	for(int i=0;i<int(eq.size())-1;i+=2)
	{
		if(eq[i].st==eq[i+1].st)
		{
			ans.pb({eq[i].nd,eq[i+1].nd});
			continue;
		}
		if((eq.size()%2==0)||(i%2==1))
		{
			valid=0;
			//cerr<<ja<<" w3\n";
			return;
		}
		dp[ja]={eq[i].nd,eq[i].st,'='};
		i--;
	}
	if((eq.size()%2==1)&&dp[ja].i==0) dp[ja]={eq.back().nd,eq.back().st,'='};
	
	/// ----- rozpatruje synow gdy wiecej < -----
	if(les.size()>mor.size())
	{
		for(int i=(int)les.size()-1,j=(int)mor.size()-1;i>=0&&j>=0;i--,j--)
		{
			if(ja==686) cout<<"   "<<i<<','<<j<<'\n';
			if(les[i].st<mor[j].st)
			{
				ans.pb({les[i].nd,mor[j].nd});
				continue;
			}
			if(i==j)
			{
				valid=0;
				//cerr<<ja<<" w4\n";
				return;
			}
			dp[ja]={les[i].nd,les[i].st,'<'};
			j++;
		}
		if(dp[ja].i==0) dp[ja]={les[0].nd,les[0].st,'<'};
	}
	
	/// ----- rozpatruje synow gdy wiecej > lub po rowno <> -----
	for(int i=0,j=0;i<int(les.size())&&j<int(mor.size());i++,j++)
	{
		if(les[i].st<mor[j].st)
		{
			ans.pb({les[i].nd,mor[j].nd});
			continue;
		}
		if(les.size()==mor.size()||i!=j)
		{
			valid=0;
			//cerr<<ja<<" w5\n";
			return;
		}
		dp[ja]={mor[j].nd,mor[j].st,'>'};
		i--;
	}
	if((les.size()<mor.size())&&dp[ja].i==0) dp[ja]={mor.back().nd,mor.back().st,'>'};
	
	if(n==1e5&&ja==686)
	{
		cout<<ja<<": "<<type[ja]<<','<<ans.size()<<"\n";
		cout<<eq.size()<<' '<<les.size()<<' '<<mor.size()<<'\n';
	}
	if(n==1e5&&dp[ja].i==68071)
	{
		cout<<ja<<":"<<ans.size()<<','<<oj<<" {"<<dp[ja].i<<','<<dp[ja].lvl<<','<<dp[ja].typ<<"} ";
		cout<<eq.size()<<','<<les.size()<<','<<mor.size()<<'\n';
	}
}
int main()
{
    ios_base::sync_with_stdio(0); cin.tie(0);
	cin>>n;
	rep(i,n-1)
	{
		int a,b;
		string s;
		cin>>a>>b>>s;
		G[a].pb(b);
		G[b].pb(a);
		if(s=="Tong") type[a]='=';
		else if(s=="Duan") type[a]='<';
		else if(s=="Chang") type[a]='>';
	}
	calcdp(1,1,1);
	if(!valid)
	{
		cout<<"NO\n";
		//for(auto [a,b]:ans) cerr<<a<<' '<<b<<'\n';
		return 0;
	}
	if(n==1e5)
	{
		rep(i,ans.size())
		{
			int a=ans[i].st,b=ans[i].nd;
			if(a==68071||b==68071) cout<<i<<' '<<a<<' '<<b<<'\n';
		}
	}
	cout<<"YES\n";
	for(auto [a,b]:ans) cout<<a<<' '<<b<<'\n';
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 5816kb

input:

8
2 1 -
3 1 -
4 2 Tong
5 2 Tong
6 3 Duan
7 3 -
8 7 Chang

output:

YES
4 5
6 8

result:

ok Correct.

Test #2:

score: 0
Accepted
time: 1ms
memory: 6020kb

input:

10
2 1 Duan
3 2 Duan
4 2 -
5 4 Chang
6 2 Chang
7 1 Duan
8 6 Tong
9 6 Tong
10 3 Chang

output:

YES
3 10
8 9
2 6
7 5

result:

ok Correct.

Test #3:

score: 0
Accepted
time: 1ms
memory: 5876kb

input:

2
2 1 Tong

output:

NO

result:

ok Correct.

Test #4:

score: -100
Wrong Answer
time: 34ms
memory: 10656kb

input:

100000
2 1 Duan
3 1 Duan
4 3 -
5 4 Duan
6 3 -
7 4 Duan
8 4 -
9 8 -
10 7 Duan
11 9 -
12 7 Duan
13 7 Duan
14 8 Duan
15 13 -
16 10 Duan
17 11 Duan
18 12 -
19 1 Duan
20 5 Duan
21 4 Duan
22 14 Duan
23 16 -
24 22 Duan
25 16 Duan
26 13 -
27 13 -
28 17 -
29 5 Duan
30 22 -
31 23 -
32 9 Duan
33 5 -
34 30 Duan...

output:

68071:37,8419 {68071,8,>} 0,0,1
8419:39,1145 {68071,8,>} 2,1,2
1145:41,686 {68071,8,>} 0,0,1
   1,0
686: <,43
0 2 1
41 86193 68071
42 686 68071
YES
46666 56115
38802 88119
10006 93143
76473 31531
15988 42604
6569 30148
2008 11412
46703 64525
70618 71289
47748 81204
20514 42353
46131 97634
82155 8351...

result:

wrong answer YES or NO expected in answer, but 68071:37,8419 found.