QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#125325#6353. Kth Lex Min Min Min SubpalindromesGenshinImpactsFault#WA 2ms3484kbC++144.3kb2023-07-16 15:47:022023-07-16 15:47:06

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-07-16 15:47:06]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:3484kb
  • [2023-07-16 15:47:02]
  • 提交

answer

#include <bits/stdc++.h>
#define fst first
#define snd second
#define pb push_back
using namespace std;
typedef long long ll;
const int N = 1000010;

const string ans2[] = {
"001011",
"001101",
"010011",
"010110",
"011001",
"011010",
"100101",
"100110",
"101001",
"101100",
"110010",
"110100"
};

namespace Sub {
vector<pair<int, string>> a;
string ss;
void dfs(int x, int n) {
    if(x == n + 1) {
        int cnt = n;
        for(int i = 0; i < n; ++ i) {
            for(int j = i - 1, k = i + 1; j >= 0 && k < n; -- j, ++ k) {
                if(ss[j] == ss[k]) {
                    ++ cnt;
                }
                else {
                    break;
                }
            }
        }
        for(int i = 0; i + 1 < n; ++ i) {
            for(int j = i, k = i + 1; j >= 0 && k < n; -- j, ++ k) {
                if(ss[j] == ss[k]) {
                    ++ cnt;
                }
                else {
                    break;
                }
            }
        }
        a.push_back({cnt, ss});
        return;
    }
    ss+='0';
    dfs(x+1,n);
    ss.pop_back();
    ss+='1';
    dfs(x+1,n);
    ss.pop_back();
}
void MAIN(int nn, int mm, ll kk) {
    a.clear(), ss.clear();
    int n, m; ll k;
    n = nn, m = mm, k = kk;
    dfs(1, n);
    sort(a.begin(),a.end());
    for(; a.back().fst != a[0].fst;) a.pop_back();
    if((int)a.size() < k) cout << "-1\n";
    else {
        for(auto v : a[k - 1].snd) cout << v - '0' + 1 << " ";
    }
    return ;
}
}

ll f[N];

bool check(int n, int m, ll k) {
    k /= m;
    if(n > 1) k /= (m - 1);
    for(int i = 3; i <= n; i++) k /= (m - 2);
    return k > 0;
}
int main() {
    ios::sync_with_stdio(0); cin.tie(nullptr);
    int n, m; ll k;
    cin >> n >> m >> k;
    if(m <= 2 && n <= 10) {
        Sub::MAIN(n, m, k); return 0;
    }
    else if(m == 2) {
        if(k > 12) cout << "-1\n";
        else {
            int id = k - 1;
            for(int i = 1; i <= n; i++) cout << ans2[id][(i - 1) % 6] - '0' + 1 << " \n"[i == n];
        }
        return 0;
    }
    else if(m == 1) {
        if(k > 1) cout << "-1\n";
        else {
            for(int i = 1; i <= n; i++) cout << "1 ";
        }
        return 0;
    }
    else if(m == 3) {
        if(k > 6) cout << "-1\n";
        else {
            vector<int> ans(2);
            if(k <= 2) ans[0] = 1;
            else if(k <= 4) ans[0] = 2;
            else ans[0] = 3;
            if(k == 1 || k == 6) ans[1] = 2;
            else if(k == 2 || k == 4) ans[1] = 3;
            else ans[1] = 1;
            for(int i = 2; i < n; i++) {
                ans.pb(ans[(int)ans.size() - 1] ^ ans[(int)ans.size() - 2]);
            }
            for(auto v : ans) cout << v << " ";
        }
        return 0;
    }
    if(check(n, m, k)) {
        cout << "-1\n"; return 0;
    }
    if(n == 1) {
        cout << k << "\n"; return 0;
    }
    if(n == 2) {
        cout << (k + m - 2) / (m - 1) << " ";
        int val = (k + m - 2) / (m - 1), rem = k % (m - 1);
        if(rem == 0) rem = m - 1;
        if(rem >= val) ++rem;
        cout << rem << "\n"; return 0;
    }
    fill(f + 1, f + n + 1, -1);
    f[0] = 1;
    int len;
    for(int i = 1; i <= n; i++) {
        if(f[i - 1] > (k + m - 3) / (m - 2)) {
            len = i - 1; break;
        }
        f[i] = 1ll * f[i - 1] * (m - 2);
    }
    vector<int> ans;
    for(int i = 1; i <= n; i++) {
        if(i == 1) {
            if(f[n - 2] == -1) ans.pb(1);
            else if((k + m - 2) / (m - 1) < f[n - 2]) {
                ans.pb(1);
                continue;
            }
            ll siz = f[n - 2] * (m - 1);
            ans.pb((k + siz - 1) / siz);
            k %= siz; if(!k) k = siz;
            continue;
        }
        int value;
        if(f[n - i] == -1) value = 2;
        else value = (k + f[n - i] - 1) / f[n - i];
        vector<int> tmp;
        for(int i = (int)ans.size() - 1; i >= 0 && (int)ans.size() - i <= 2; i--)
            tmp.pb(ans[i]);
        sort(tmp.begin(), tmp.end());
        for(auto v : tmp)
            if(value >= v) ++value;
        ans.pb(value);
        if(f[n - i] != -1) {
            k %= f[n - i];
            if(k == 0) k = f[n - i];
        }
    }
    for(auto v : ans) cout << v << " ";
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 2ms
memory: 3412kb

input:

1 1 1

output:

1 

result:

ok 1 number(s): "1"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3440kb

input:

2 2 2

output:

2 1 

result:

ok 2 number(s): "2 1"

Test #3:

score: 0
Accepted
time: 0ms
memory: 3476kb

input:

3 3 3

output:

2 1 3 

result:

ok 3 number(s): "2 1 3"

Test #4:

score: 0
Accepted
time: 1ms
memory: 3476kb

input:

9 9 8244353

output:

2 4 1 2 6 8 1 2 7 

result:

ok 9 numbers

Test #5:

score: 0
Accepted
time: 1ms
memory: 3420kb

input:

10 7 998244353

output:

-1

result:

ok 1 number(s): "-1"

Test #6:

score: 0
Accepted
time: 1ms
memory: 3484kb

input:

3 1000 994253860

output:

998 244 353 

result:

ok 3 number(s): "998 244 353"

Test #7:

score: -100
Wrong Answer
time: 1ms
memory: 3472kb

input:

58 4 864691128455135232

output:

-1

result:

wrong answer 1st numbers differ - expected: '4', found: '-1'