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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#111632 | #5504. Flower Garden | namelessgugugu | WA | 5831ms | 255524kb | C++14 | 4.9kb | 2023-06-07 19:57:08 | 2023-06-07 19:57:09 |
Judging History
answer
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <vector>
#define FILEIO(filename) (freopen(filename ".in", "r", stdin), freopen(filename ".out", "w", stdout))
typedef long long ll;
typedef unsigned long long ull;
const int N = 500005;
int Test;
int n, q, nn, rt, pos[N];
struct Limit
{
int a, b, c, d;
} e[N];
int id[N], ls[N], rs[N], tot;
std::vector<int> E[N];
int build(int l, int r, int ty)
{
if(l == r)
{
if(ty == 0)
{
int x = ++tot;
id[x] = l, pos[l] = x;
return x;
}
else
return pos[l];
}
int x = ++tot;
int mid = (l + r) >> 1;
ls[x] = build(l, mid, ty);
rs[x] = build(mid + 1, r, ty);
if (ty == 0)
{
E[ls[x]].push_back(x);
E[rs[x]].push_back(x);
}
else
{
E[x].push_back(ls[x]);
E[x].push_back(rs[x]);
}
return x;
}
void add(int x, int l, int r, int ql, int qr, int v, int ty)
{
if(l >= ql && r <= qr)
{
if(ty == 0)
E[x].push_back(v + 6 * n - 1);
else
E[v + 6 * n - 1].push_back(x);
return;
}
int mid = (l + r) >> 1;
if(ql <= mid)
add(ls[x], l, mid, ql, qr, v, ty);
if(qr > mid)
add(rs[x], mid + 1, r, ql, qr, v, ty);
return;
}
std::vector<int> G[2][N];
int dfn[N], low[N], tt;
int stk[N], top;
bool ins[N];
int cnt;
int bel[N], siz[N];
void tarjan(int x)
{
dfn[x] = low[x] = ++tt;
stk[++top] = x;
for(int y : E[x])
{
if(!dfn[y])
tarjan(y), low[x] = std::min(low[x], low[y]);
else if(ins[y])
low[x] = std::min(low[x], dfn[y]);
}
if(dfn[x] == low[x])
{
++cnt;
for (int tmp = -1; tmp != x;)
{
tmp = stk[top--];
ins[tmp] = 0;
bel[tmp] = cnt;
if (id[tmp])
++siz[cnt];
}
}
return;
}
int col[N];
char ans[N];
int main(void) // Rose:0 Violet:1
{
scanf("%d", &Test);
while(Test--)
{
scanf("%d%d", &n, &q), nn = 9 * n + q - 2;
memset(pos, 0, sizeof(int) * (3 * n + 5));
tot = 0;
for (int i = 1; i <= 12 * n + 5; ++i)
E[i].clear(), id[i] = ls[i] = rs[i] = 0;
for (int o = 0; o < 2;++o)
for (int i = 1; i <= nn + 5; ++i)
G[o][i].clear();
memset(dfn, 0, sizeof(int) * (nn + 5)), tot = 0;
memset(low, 0, sizeof(int) * (nn + 5));
cnt = 0;
memset(bel, 0, sizeof(int) * (nn + 5));
memset(siz, 0, sizeof(int) * (nn + 5));
memset(col, 0, sizeof(int) * (nn + 5));
memset(ans, 0, sizeof(char) * (nn + 5));
for (int i = 1; i <= q;++i)
scanf("%d%d%d%d", &e[i].a, &e[i].b, &e[i].c, &e[i].d);
rt = build(1, 3 * n, 0);
for (int i = 1; i <= q; ++i)
add(rt, 1, 3 * n, e[i].a, e[i].b, i, 0);
rt = build(1, 3 * n, 1);
for (int i = 1; i <= q;++i)
add(rt, 1, 3 * n, e[i].c, e[i].d, i, 1);
for (int i = 1; i <= nn; ++i)
if (!dfn[i])
tarjan(i);
for (int i = 1; i <= nn;++i)
for(int j : E[i])
if(bel[i] != bel[j])
G[0][bel[i]].push_back(bel[j]), G[1][bel[j]].push_back(bel[i]);
int big = -1;
for (int i = 1; i <= cnt;++i)
if(siz[i] >= n)
{
big = i;
break;
}
bool flag = 0;
if (big == -1)
{
flag = 1;
int now = 0;
for (int i = 1; now < n && i <= cnt;++i)
col[i] = 1, now += siz[i];
}
else
{
for (int o = 0; o < 2; ++o)
{
for (int i = 1; i <= cnt;++i)
col[i] = o;
col[big] = o ^ 1;
for (int i = 1; i <= cnt; ++i)
if(col[i] != o)
{
for(int j : G[o][i])
col[j] = o ^ 1;
}
for (int i = cnt; i >= 1; --i)
if (col[i] != o)
{
for (int j : G[o][i])
col[j] = o ^ 1;
}
int now = 0;
for (int i = 1; i <= cnt;++i)
now += col[i] * siz[i];
if(now >= n && now <= 2 * n)
{
flag = 1;
break;
}
}
}
if(!flag)
puts("NIE");
else
{
puts("TAK");
for (int i = 1; i <= nn;++i)
if(id[i])
ans[id[i]] = col[bel[i]] ? 'F' : 'R';
puts(ans + 1);
}
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 5ms
memory: 58284kb
input:
2 1 3 1 1 2 2 1 2 3 3 1 1 3 3 1 3 1 1 2 2 2 2 3 3 3 3 1 1
output:
TAK RRF NIE
result:
ok good!
Test #2:
score: -100
Wrong Answer
time: 5831ms
memory: 255524kb
input:
10 33333 100000 28701 40192 93418 95143 95902 97908 78378 78461 36823 44196 22268 23996 23977 24786 33315 48829 83965 90411 4923 8445 20235 21177 32543 47454 29598 35414 72477 73049 2014 12632 42163 46466 64305 65518 98825 99552 32331 41625 92772 96224 26500 54122 76990 77126 18249 20335 31165 36080...
output:
TAK RFFRRRRRRRRRRFRFRRRFRFRFRRFRRRRRRRRRRFRRRRFFRRRRRRRRRRFRFRRRFFRRRRFRFRRRFFRRRRRRFFRRRFFRRRRRRRRRRRFFRRRRRRRRRFRFFFRRRRFFRRRFRRRRRRRFRFRFFRRRRRRRRRFFRRRRRRFRRRFRFRRRRRRRRRRFFRFRFRRRRRFRFRRRRRRFFRRRFRRRRRFRRRRFRFRRRFFFRFRFRFRFRRRFRRRFRFRRRRFFRRRRFFRRFRFRFRRRRRFRRRFFFRRRRRFRRRRFRRRRRFRFRRRFFRFRRRFR...
result:
wrong answer zla odpowiedz!