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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#111574#5504. Flower GardenAK_DreamRE 7ms41552kbC++142.6kb2023-06-07 16:35:522023-06-07 16:35:57

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-06-07 16:35:57]
  • 评测
  • 测评结果:RE
  • 用时:7ms
  • 内存:41552kb
  • [2023-06-07 16:35:52]
  • 提交

answer

#include <bits/stdc++.h>
#define N 1000005
#define pb push_back 
using namespace std;

template <typename T>
inline void read(T &num) {
	T x = 0, ff = 1; char ch = getchar();
	for (; ch > '9' || ch < '0'; ch = getchar()) if (ch == '-') ff = -1;
	for (; ch <= '9' && ch >= '0'; ch = getchar()) x = (x<<3)+(x<<1)+(ch^'0');
	num = x * ff; 
}

int n, Q, tot;
int lc[N], rc[N];
int dfn[N], low[N], stk[N], in[N], col[N], siz[N], top, tme, scc;
vector<int> E[N];

void build(int &p, int l, int r, int tp) {
	if (l == r) return p=l, void();
	p = ++tot; E[p].clear(); 
	int mid = (l+r)>>1;
	build(lc[p],l,mid,tp); build(rc[p],mid+1,r,tp);
	if (!tp) E[lc[p]].pb(p), E[rc[p]].pb(p);
	else E[p].pb(lc[p]), E[p].pb(rc[p]); 
}
void qry(int p, int l, int r, int x, int y, int v, int tp) {
	if (x <= l && r <= y) {
		if (!tp) E[p].pb(v); else E[v].pb(p);
		return;
	}
	int mid = (l+r)>>1;
	if (x <= mid) qry(lc[p],l,mid,x,y,v,tp);
	if (mid < y) qry(rc[p],mid+1,r,x,y,v,tp);
}

void tarjan(int x) {
	dfn[x] = low[x] = ++tme;
	stk[++top] = x; in[x] = 1;
	for (auto y : E[x]) {
		if (!dfn[y]) tarjan(y), low[x] = min(low[x], low[y]);
		else if (in[y]) low[x] = min(low[x], dfn[y]);
	}
	if (dfn[x] == low[x]) {
		int z = 0; siz[++scc] = 0;
		do {
			z = stk[top--];
			in[z] = 0; col[z] = scc;
			if (z <= n) ++siz[scc];
		} while (z != x);
	}
}
void dfs(int x, int &sum) {
	if (x <= n) ++sum;
	dfn[x] = 0;
	for (auto y : E[x]) if (dfn[y]) dfs(y, sum);
}

void solve() {
	read(n); read(Q); n *= 3;
	tot = n; 
	for (int i = 1; i <= n; i++) E[i].clear();
	int rt0 = 0, rt1 = 0;
	build(rt0,1,n,0); build(rt1,1,n,1);
	while (Q--) {
		int l, r, x, y; read(l); read(r); read(x); read(y);
		int t = ++tot; E[t].clear();
		qry(rt0,1,n,l,r,t,0); qry(rt1,1,n,x,y,t,1); 
	}
	for (int i = 1; i <= tot; i++) dfn[i] = 0;
	tme = scc = 0;
	for (int i = 1; i <= tot; i++) if (!dfn[i]) tarjan(i);
	int k = 0, sum = 0;
	for (int i = 1; i <= scc; i++) {
		sum += siz[i];
		if (sum >= n/3) {
			if (sum <= 2*n/3) k = i; 
			else assert(siz[i] >= n/3), k = -i;
			break;
		}
	}
	if (k > 0) {
		puts("TAK"); sum = 0;
		for (int i = 1; i <= n; i++) putchar(col[i]<=k?'F':'R'), sum += (col[i]<=k);
		putchar('\n'); return;
	}
	assert(sum == n);
	k = -k;
	for (int i = 1; i <= tot; i++) if (col[i] == k) {
		sum = 0; dfs(k, sum);
		if (sum > 2*n/3) { puts("NIE"); return; }
		puts("TAK"); sum = 0;
		for (int j = 1; j <= n; j++) putchar(!dfn[j]?'F':'R'), sum += (!dfn[j]);
		putchar('\n'); return;
	}
}

int main() {
	int ttt; read(ttt);
	while (ttt--) solve();	
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 7ms
memory: 41552kb

input:

2
1 3
1 1 2 2
1 2 3 3
1 1 3 3
1 3
1 1 2 2
2 2 3 3
3 3 1 1

output:

TAK
RRF
NIE

result:

ok good!

Test #2:

score: -100
Dangerous Syscalls

input:

10
33333 100000
28701 40192 93418 95143
95902 97908 78378 78461
36823 44196 22268 23996
23977 24786 33315 48829
83965 90411 4923 8445
20235 21177 32543 47454
29598 35414 72477 73049
2014 12632 42163 46466
64305 65518 98825 99552
32331 41625 92772 96224
26500 54122 76990 77126
18249 20335 31165 36080...

output:


result: