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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#110888#5069. VacationLitDarknessWA 767ms106200kbC++147.3kb2023-06-04 15:42:292023-06-04 15:42:31

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-06-04 15:42:31]
  • 评测
  • 测评结果:WA
  • 用时:767ms
  • 内存:106200kb
  • [2023-06-04 15:42:29]
  • 提交

answer

#include <bits/stdc++.h>
#define For(i, a, b) for (int i = a; i <= b; ++i)
#define Rep(i, a, b) for (int i = a; i >= b; --i)
using namespace std;
namespace io {
template<typename T>inline void read(T &x) {
  char ch, f = 0; x = 0;
  while (!isdigit(ch = getchar())) f |= ch == '-';
  while (isdigit(ch)) x = (x << 1) + (x << 3) + (ch ^ 48), ch = getchar();
  x = f? -x: x;
}
char ch[40];
template<typename T>inline void write(T x) {
  (x < 0) && (putchar('-'), x = -x);
  x || putchar('0');
  int i = 0;
  while (x) ch[i++] = x % 10 ^ 48, x /= 10;
  while (i) putchar(ch[--i]);
}
}
#define rd io::read
#define wt io::write
using i64 = long long;
const int maxN = 2e6 + 5;
int a[maxN], c, n, blo, m;
struct Node1 {
  i64 sum, pre, suf, ans;
  Node1 operator+ (const Node1 &a) const {
    return {sum + a.sum, max(pre, sum + a.pre), max(a.suf, a.sum + suf), max({ans, a.ans, suf + a.pre})};
  }
};
struct Seg1 {
  vector<Node1> T;
  int len, beg;
  inline void init(int l) { len = l; T.resize(l << 2|1); }
  void build(int k, int l, int r) {
    if (l == r) {
      T[k].sum = a[beg + l - 1];
      T[k].ans = T[k].suf = T[k].pre = max(0, a[beg + l - 1]);      
      return;   
    }
    int mid = l + r >> 1;
    build(k << 1, l, mid);
    build(k << 1|1, mid + 1, r);
    T[k] = T[k << 1] + T[k << 1|1];
  }
  void update(int x, int v, int k, int l, int r) {
    if (l == r) {
      T[k].sum = v;
      T[k].ans = T[k].suf = T[k].pre = max(0, v);
      return;
    }
    int mid = l + r >> 1;
    if (x <= mid) update(x, v, k << 1, l, mid);
    else update(x, v, k << 1|1, mid + 1, r);
    T[k] = T[k << 1] + T[k << 1|1];
  }
  Node1 query(int x, int y, int k, int l, int r) {
    if (x <= l && r <= y) return T[k];
    int mid = l + r >> 1;
    if (x <= mid) {
      if (y > mid) return query(x, y, k << 1, l, mid) + query(x, y, k << 1|1, mid + 1, r);
      return query(x, y, k << 1, l, mid);
    }
    return query(x, y, k << 1|1, mid + 1, r);
  }
};
int bel[maxN], R[maxN];
struct Node2 {
  i64 sa, sb, pa, pb, ans;
  Node2 operator+ (const Node2 &a) const {
    return {sa + a.sa, sb + a.sb, max(pa, sa + a.pa), max(pb, sb + a.pb), max({ans + a.sb, a.ans + sa, pa + a.pb})};
  }
};
struct Seg2 {
  vector<Node2> T;
  int len, beg;
  inline void init(int l) { len = l; T.resize(l << 2|1); }
  void build(int k, int l, int r) {
    if (l == r) {
      T[k].sa = a[min(beg + l - 1 + c, n + 1)];
      T[k].sb = a[beg + l - 1];
      T[k].pa = max(T[k].sa, 0ll);
      T[k].pb = max(T[k].sb, 0ll);
      T[k].ans = max(T[k].pa, T[k].pb);
      return;
    }
    int mid = l + r >> 1;
    build(k << 1, l, mid);
    build(k << 1|1, mid + 1, r);
    T[k] = T[k << 1] + T[k << 1|1];
  }
  Node2 query(int x, int y, int op, int k, int l, int r) {
    if (x <= l && r <= y) return T[k];
    if (x > r || y < l) {
      Node2 r = T[k]; r.ans = -1e18;
      if (op) r.pa = -1e18;
      else r.pb = -1e18;
      return r;
    }
    int mid = l + r >> 1;
    return query(x, y, op, k << 1, l, mid) + query(x, y, op, k << 1|1, mid + 1, r);
  }
  i64 Squery(int x, int y, int op) {
    i64 v = query(x, y, op, 1, 1, len).ans;
    return v;
  }
  void update(int x, int op, int v, int k, int l, int r) {
    if (l == r) {
      if (op == 0) {
        T[k].sa = v; T[k].pa = max(T[k].sa, 0ll);
      } else {
        T[k].sb = v; T[k].pb = max(T[k].sb, 0ll);
      }
      T[k].ans = max(T[k].pa, T[k].pb);
      return;
    }
    int mid = l + r >> 1;
    if (x <= mid) update(x, op, v, k << 1, l, mid);
    else update(x, op, v, k << 1|1, mid + 1, r);
    T[k] = T[k << 1] + T[k << 1|1];
  }
};
vector<Seg1> T1;
vector<Seg2> T2;
vector<i64> mx, sx;
int lf[maxN];
void bbuild(int k = 1, int l = 1, int r = blo - 1) {
  if (l == r) {
    lf[l] = k;
    sx[k] = T2[l].T[1].ans;
    return;
  }
  int mid = l + r >> 1;
  bbuild(k << 1, l, mid);
  bbuild(k << 1|1, mid + 1, r);
  sx[k] = max(sx[k << 1], sx[k << 1|1]);
}
inline void uupdate(int x) {
  sx[lf[x]] = T2[x].T[1].ans;
  x = lf[x] >> 1;
  while (x) {
    sx[x] = max(sx[x << 1], sx[x << 1|1]); x >>= 1;
  }
}
i64 qqu(int x, int y, int k = 1, int l = 1, int r = blo - 1) {
  if (x <= l && r <= y) return sx[k];
  int mid = l + r >> 1; i64 ans = 0;
  if (x <= mid) ans = max(ans, qqu(x, y, k << 1, l, mid));
  if (y > mid) ans = max(ans, qqu(x, y, k << 1|1, mid + 1, r));
  return ans;
}
void build(int k = 1, int l = 1, int r = blo) {
  if (l == r) {
    if (l < blo) {
      T1[l].init(c); T2[l].init(c);
      T1[l].beg = T2[l].beg = (l - 1) * c + 1;
      T2[l].build(1, 1, c);
    } else {
      T1[l].init(n - (l - 1) * c);
      T1[l].beg = (l - 1) * c + 1;
    }
    T1[l].build(1, 1, T1[l].len);
    mx[k] = T1[l].T[1].ans;
    return;
  }
  int mid = l + r >> 1;
  build(k << 1, l, mid);
  build(k << 1|1, mid + 1, r);
  mx[k] = max(mx[k << 1], mx[k << 1|1]);
}
void update(int x, int v, int k = 1, int l = 1, int r = blo) {
  if (l == r) {
    int rr = x - R[l - 1];
    T1[l].update(rr, v, 1, 1, T1[l].len);
    if (l > 1) {
      T2[l - 1].update(rr, 0, v, 1, 1, T2[l - 1].len);
      uupdate(l - 1);
    }
    if (l < bel[n]) {
      T2[l].update(rr, 1, v, 1, 1, T2[l].len);
      uupdate(l);
    }
    mx[k] = T1[l].T[1].ans;
    return;
  }
  int mid = l + r >> 1;
  if (bel[x] <= mid) update(x, v, k << 1, l, mid);
  else update(x, v, k << 1|1, mid + 1, r);
  mx[k] = max(mx[k << 1], mx[k << 1|1]);
}
i64 query(int x, int y, int k = 1, int l = 1, int r = blo) {
  if (x <= l && r <= y) return mx[k];
  int mid = l + r >> 1; i64 ans = 0;
  if (x <= mid) ans = max(ans, query(x, y, k << 1, l, mid));
  if (y > mid) ans = max(ans, query(x, y, k << 1|1, mid + 1, r));
  return ans;
}
inline int gv(int x) { return x - R[bel[x] - 1]; }
i64 ask(int x, int y) {
  if (bel[x] == bel[y]) 
    return T1[bel[x]].query(gv(x), gv(y), 1, 1, R[bel[x]] - R[bel[x] - 1]).ans;
  if (y - x + 1 <= c) {
    Node1 p = T1[bel[x]].query(gv(x), T1[bel[x]].len, 1, 1, T1[bel[x]].len) + T1[bel[y]].query(1, gv(y), 1, 1, T1[bel[y]].len);
    return p.ans;
  }
  if (bel[y] == bel[x] + 1) {
    Node1 p;
    if (x > R[bel[x] - 1] + 1) p = T1[bel[x]].query(gv(x), T1[bel[x]].len, 1, 1, T1[bel[x]].len) + T1[bel[x + c - 1]].query(1, gv(x + c - 1), 1, 1, T1[bel[y]].len);
    else p = T1[bel[x]].T[1];
    i64 ans = max(p.ans, T1[bel[y]].query(1, gv(y), 1, 1, T1[bel[y]].len).ans);
    return max(ans, T2[bel[x]].Squery(gv(x + c), gv(y), 0));
  }
  i64 ans = max({query(bel[x] + 1, bel[y] - 1), T1[bel[x]].query(gv(x), T1[bel[x]].len, 1, 1, T1[bel[x]].len).ans, T1[bel[y]].query(1, gv(y), 1, 1, T1[bel[y]].len).ans});
  if (bel[y] - bel[x] > 2) ans = max(ans, qqu(bel[x] + 1, bel[y] - 2));
  ans = max({ans, T2[bel[x]].Squery(gv(x), c, 0), T2[bel[y] - 1].Squery(1, gv(y), 1)});
  return ans;
}
int main() {
  rd(n); rd(m); rd(c);
  blo = (n - 1) / c + 1;
  For (i, 1, n) {
    rd(a[i]);
    bel[i] = (i - 1) / c + 1;
  }
  For (i, 1, blo) 
    R[i] = min(R[i - 1] + c, n);
  T1.resize(blo + 1); T2.resize(blo + 1); mx.resize(blo << 2|1); sx.resize(blo << 2|1);
  build(); bbuild();
  int op, x, y; 
  For (i, 1, m) {
    rd(op); rd(x); rd(y);
    if (op == 1) {
      update(x, y);
    } else {
      wt(ask(x, y)); putchar('\n');
    }
  }
  return 0;
}

详细

Test #1:

score: 100
Accepted
time: 2ms
memory: 3440kb

input:

5 6 3
0 -5 -3 8 -3
2 3 5
1 2 5
2 1 5
1 4 -3
2 3 5
2 1 5

output:

8
10
0
5

result:

ok 4 number(s): "8 10 0 5"

Test #2:

score: 0
Accepted
time: 767ms
memory: 106200kb

input:

200000 500000 1
387060158 961744470 37167782 737122872 -532977662 1604246 -30977399 871848791 444997246 454204578 -813187501 -660394286 448014171 -835115276 -631880452 887715308 258530352 805589560 -414653327 -156732249 -335096199 -80266237 367896009 738406627 -903652056 446120866 415658444 -1347916...

output:

999902477
999981999
999343404
999847372
999957587
998160312
999981999
999981999
999981999
999980061
999981999
999981999
999981999
999876122
999981999
999996602
999981999
999981999
999981999
999723649
999981999
999957587
999896087
999981999
999981999
999981999
999981999
999981999
999957587
999981999
...

result:

ok 250051 numbers

Test #3:

score: -100
Wrong Answer
time: 570ms
memory: 70036kb

input:

200000 500000 5
802774074 383481934 -295470374 285359286 751657057 197444479 626916547 -828168464 288373833 -493446966 -208422769 956745384 919286225 959643271 -176531848 -380256966 357111771 -50890039 -637284768 -337010918 259019684 752475630 -259898780 98620995 -704832505 -532710796 -971600790 -84...

output:

4544135313
4544135313
4443416295
3390067591
4544135313
4544135313
4322308420
4386413596
4386413596
4165697630
4322308420
4287938127
4443416295
4544135313
4386413596
4165697630
4386413596
4386413596
4386413596
4323325838
4443416295
4386413596
4385851999
4544135313
4443416295
4443416295
4323325838
432...

result:

wrong answer 782nd numbers differ - expected: '1710800429', found: '1618231479'