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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#109032#6194. Knapsack ProblemLG_MonkeyTL 218ms290512kbC++142.2kb2023-05-27 10:06:492023-05-27 10:06:53

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-05-27 10:06:53]
  • 评测
  • 测评结果:TL
  • 用时:218ms
  • 内存:290512kb
  • [2023-05-27 10:06:49]
  • 提交

answer

#pragma GCC optimize("Ofast")

#include <bits/stdc++.h>
using namespace std;
#define pii pair<int, int>
#define mp make_pair
#define fi first
#define pb push_back
#define se second
#define deb(x) cerr << #x << "=" << (x) << "; "
#define ll long long
int k, c[100], a[100];
const int blo = 15;
ll dp[33][17][blo + 1][blo + 1][blo + 1][blo + 1];
signed main() {
	int T;
	cin >> T;
	while (T--) {
		memset(dp, 0xcf, sizeof dp);
		cin >> k;
		for (int i = 1; i < (1ll << k); i++) cin >> c[i];
		for (int i = 0; i < k; i++) cin >> a[i];
		dp[0][1][0][0][0][0] = 0;
		for (int i = 0; i <= 31; i++) {
			for (int j = 1; j < (1ll << k); j++) {
				for (int a1 = 0; a1 <= blo; a1++) {
					for (int a2 = 0; a2 <= blo; a2++) {
						for (int a3 = 0; a3 <= blo; a3++) {
							for (int a4 = 0; a4 <= blo; a4++) {
								// x[j][i] = 0
								dp[i][j + 1][a1][a2][a3][a4] = max(dp[i][j + 1][a1][a2][a3][a4], dp[i][j][a1][a2][a3][a4]);
								// x[j][i] = 1
								int b1 = a1, b2 = a2, b3 = a3, b4 = a4;
								if (j & 1) b1 += 2;
								if (j & 2) b2 += 2;
								if (j & 4) b3 += 2;
								if (j & 8) b4 += 2;
								if (b1 <= blo && b2 <= blo && b3 <= blo && b4 <= blo) dp[i][j + 1][b1][b2][b3][b4] = max(dp[i][j + 1][b1][b2][b3][b4], dp[i][j][a1][a2][a3][a4] + c[j] * (1ll << i));
							}
						}
					}
				}
			}
			
			for (int a1 = 0; a1 <= blo; a1++) {
				for (int a2 = 0; a2 <= blo; a2++) {
					for (int a3 = 0; a3 <= blo; a3++) {
						for (int a4 = 0; a4 <= blo; a4++) {
							bool flag = 1;
							if (k >= 1) {
								flag &= (bool)(a1 & 2) == (bool)(a[0] & (1ll << i)); 
							}
							if (k >= 2) {
								flag &= (bool)(a2 & 2) == (bool)(a[1] & (1ll << i));
							}
							if (k >= 3) {
								flag &= (bool)(a3 & 2) == (bool)(a[2] & (1ll << i));
							}
							if (k >= 4) {
								flag &= (bool)(a4 & 2) == (bool)(a[3] & (1ll << i));
							}
							if (flag) {
								ll x = dp[i][1 << k][a1][a2][a3][a4];
								dp[i + 1][1][a1 / 2][a2 / 2][a3 / 2][a4 / 2] = max(dp[i + 1][1][a1 / 2][a2 / 2][a3 / 2][a4 / 2], x);
							}
						}
					}
				}
			}
		}
		cout << dp[32][1][0][0][0][0] << "\n";
	}
    return 0;
} 

详细

Test #1:

score: 100
Accepted
time: 218ms
memory: 290512kb

input:

3
2
1 2 4
4 5
3
3226252 19270256 2430652 1187613 12496062 10286165 17494834
24 85 34
4
901133 6693218 13245489 14740234 16186210 11382783 19277321 3855635 16523184 10168517 16195031 971041 10303441 8395899 11618555
529321239 218214127 92942310 207467810

output:

18
1949753378
7832404777567179

result:

ok 3 number(s): "18 1949753378 7832404777567179"

Test #2:

score: -100
Time Limit Exceeded

input:

100
4
4488409 9842893 14331290 11289097 15777479 21131954 25620334 6146092 10634508 15988956 20477387 17435190 21923584 27278027 31766493
200477197 258791439 590664017 982949628
4
5484152 19851747 25335961 6555937 12039831 26407861 31891996 10897184 16381166 30749333 36233145 17453055 22937114 37304...

output:

16156444320083421
24565535429631234
29418802996321901
30685727712782520
21026118053726857
27272339796311010
28831028447377015
34577176834491128
9058894962996375
21525085254465501
6657186892229297
16750628911275484
11217846865301187
12674726744043780
33873234230125448
3890237279573366
319038768614465...

result: