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#108441#6396. Puzzle: Kusabiberarchegas#WA 1ms3480kbC++177.5kb2023-05-25 01:27:432023-05-25 01:27:44

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-05-25 01:27:44]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3480kb
  • [2023-05-25 01:27:43]
  • 提交

answer

#include <bits/stdc++.h>
    
using namespace std;
using ll = long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
    
mt19937 rng((int) chrono::steady_clock::now().time_since_epoch().count());
    
const int MOD = 1e9 + 7;
const int MAXN = 2e5 + 5;
const int INF = 2e9;

struct dinic {
	const bool scaling = false;
	int lim;
	struct edge {
		int to, cap, rev, flow;
		bool res;
		edge(int to_, int cap_, int rev_, bool res_)
			: to(to_), cap(cap_), rev(rev_), flow(0), res(res_) {}
	};

	vector<vector<edge>> g;
	vector<int> lev, beg;
	ll F;
	dinic(int n) : g(n), F(0) {}

	void add(int a, int b, int c) {
		g[a].emplace_back(b, c, g[b].size(), false);
		g[b].emplace_back(a, 0, g[a].size()-1, true);
	}
	bool bfs(int s, int t) {
		lev = vector<int>(g.size(), -1); lev[s] = 0;
		beg = vector<int>(g.size(), 0);
		queue<int> q; q.push(s);
		while (q.size()) {
			int u = q.front(); q.pop();
			for (auto& i : g[u]) {
				if (lev[i.to] != -1 or (i.flow == i.cap)) continue;
				if (scaling and i.cap - i.flow < lim) continue;
				lev[i.to] = lev[u] + 1;
				q.push(i.to);
			}
		}
		return lev[t] != -1;
	}
	int dfs(int v, int s, int f = INF) {
		if (!f or v == s) return f;
		for (int& i = beg[v]; i < g[v].size(); i++) {
			auto& e = g[v][i];
			if (lev[e.to] != lev[v] + 1) continue;
			int foi = dfs(e.to, s, min(f, e.cap - e.flow));
			if (!foi) continue;
			e.flow += foi, g[e.to][e.rev].flow -= foi;
			return foi;
		}
		return 0;
	}
	ll max_flow(int s, int t) {
		for (lim = scaling ? (1<<30) : 1; lim; lim /= 2)
			while (bfs(s, t)) while (int ff = dfs(s, t)) F += ff;
		return F;
	}

	// arestas com fluxo
	vector<pii> flow_edges(int s, int t) {
		max_flow(s, t);
		vector<pii> ans;
		int n = g.size();
		for (int i = 0; i < n; i++) {
			for (auto edge : g[i]) {
				if (!edge.res && edge.flow) 
					ans.emplace_back(i, edge.to);
			}
		}
		return ans;
	}
};

int v[155][155], n, m, dx[] = {0, 0, 1, -1}, dy[] = {1, -1, 0, 0}, qtd[155][155];
char ans[155][155];

int coorToId(int x, int y) {
    return m * x + y;
}

pii idToCoord(int id) {
    return {id / m, id % m};
}

bool valid(int x, int y) {
    return x >= 0 && x < n && y >= 0 && y < m;
}

int main () {
    ios::sync_with_stdio(false);
    cin.tie(0);
    cin >> n >> m;
    char c;
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < m; j++) {
            cin >> c;
            v[i][j] = c - '0';
            if (j < m - 1)
                cin >> c;
        }
        if (i < n - 1)
            for (int j = 0; j < 2 * m - 1; j++) cin >> c;
    }
    dinic g(n * m + 2);
    int source = n * m, sink = n * m + 1;
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < m; j++) {
            if ((i == 0 || i == n - 1) && (j == 0 || j == m - 1)) {
                // corner
                if (v[i][j] != 2) continue;
                if ((i + j) % 2 == 0) {
                    g.add(source, coorToId(i, j), 1);
                }
                else {
                    g.add(coorToId(i, j), sink, 1);
                }
                for (int k = 0; k < 4; k++) {
                    int nx = i + dx[k], ny = j + dy[k];
                    if (valid(nx, ny) && (v[nx][ny] == 2 || v[nx][ny] == 4)) {
                        if ((i + j) % 2 == 0) {
                            g.add(coorToId(i, j), coorToId(nx, ny), 1);
                        }
                        else {
                            g.add(coorToId(nx, ny), coorToId(i, j), 1);
                        }
                    }
                }
            }
            else if (i == 0 || i == n - 1 || j == 0 || j == m - 1) {
                // borda
                if (v[i][j] != 4) continue;
                if ((i + j) % 2 == 0) {
                    g.add(source, coorToId(i, j), 1);
                }
                else {
                    g.add(coorToId(i, j), sink, 1);
                }
                for (int k = 0; k < 4; k++) {
                    int nx = i + dx[k], ny = j + dy[k];
                    if (valid(nx, ny) && (v[nx][ny] == 2 || v[nx][ny] == 4)) {
                        if (v[nx][ny] == 4 && ((nx != i && (i == 0 || i == n - 1) && (nx == 0 || nx == n - 1)) 
                            || (ny != j && (j == 0 || j == m - 1) && (ny == 0 || ny == m - 1)))) continue;
                        if ((i + j) % 2 == 0) {
                            g.add(coorToId(i, j), coorToId(nx, ny), 1);
                        }
                        else {
                            g.add(coorToId(nx, ny), coorToId(i, j), 1);
                        }
                    }
                }
            }
            else {
                // resto
                if (v[i][j] != 7) continue;
                if ((i + j) % 2 == 0) {
                    g.add(source, coorToId(i, j), 1);
                }
                else {
                    g.add(coorToId(i, j), sink, 1);
                }
                for (int k = 0; k < 4; k++) {
                    int nx = i + dx[k], ny = j + dy[k];
                    if (valid(nx, ny) && v[nx][ny] == 7) {
                        if ((i + j) % 2 == 0) {
                            g.add(coorToId(i, j), coorToId(nx, ny), 1);
                        }
                        else {
                            g.add(coorToId(nx, ny), coorToId(i, j), 1);
                        }
                    }
                }
            }
        }
    }
    vector<pii> edges = g.flow_edges(source, sink);
    for (pii x : edges) {
        qtd[idToCoord(x.first).first][idToCoord(x.first).second]++;
        qtd[idToCoord(x.second).first][idToCoord(x.second).second]++;
    }
    bool ok = true;
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < m; j++) {
            if ((i == 0 || i == n - 1) && (j == 0 || j == m - 1)) {
                // corner
                if (v[i][j] != 2) continue;
                ok &= qtd[i][j] == 2;
            }
            else if (i == 0 || i == n - 1 || j == 0 || j == m - 1) {
                // borda
                if (v[i][j] != 4) continue;
                ok &= qtd[i][j] == 2;
            }
            else {
                // resto
                if (v[i][j] != 7) continue;
                ok &= qtd[i][j] == 2;
            }
        }
    }
    if (!ok) cout << "NO\n";
    else {
        cout << "YES\n";
        for (int i = 0; i < 2 * n; i++) {
            for (int j = 0; j < 2 * m; j++) {
                ans[i][j] = '#';
            }
        }
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < m; j++) {
                ans[2 * i][2 * j] = v[i][j] + '0';
            }
        }
        for (pii x : edges) {
            if (x.first == source || x.second == source || x.first == sink || x.second == sink) continue;
            pii p = idToCoord(x.first);
            pii s = idToCoord(x.second);
            if (s.first == p.first + 1) {
                ans[2 * p.first + 1][2 * p.second] = '.';
            }
            else if (s.first == p.first - 1) {
                ans[2 * p.first - 1][2 * p.second] = '.';
            }
            else if (s.second == p.second + 1) {
                ans[2 * p.first][2 * p.second + 1] = '.';
            }
            else {
                ans[2 * p.first][2 * p.second - 1] = '.';
            }
        }
        for (int i = 0; i < 2 * n - 1; i++) {
            for (int j = 0; j < 2 * m - 1; j++) cout << ans[i][j];
            cout << '\n';
        }
    }
    return 0;
}

详细

Test #1:

score: 0
Wrong Answer
time: 1ms
memory: 3480kb

input:

8
2 1 -
3 1 -
4 2 Tong
5 2 Tong
6 3 Duan
7 3 -
8 7 Chang

output:

YES
1#3
###
2#o
###
2#o
###
3#u
###
3#8
###
a#g
###
g#g
###
g#g

result:

wrong output format Expected integer, but "1#3" found