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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#107246 | #5307. Subgraph Isomorphism | shihoghmean | WA | 11ms | 94044kb | C++14 | 3.2kb | 2023-05-20 16:27:24 | 2023-10-15 17:25:32 |
Judging History
answer
// Problem: G. Subgraph Isomorphism
// Contest: Codeforces - The 2022 ICPC Asia Hangzhou Regional Programming Contest
// URL: https://codeforces.com/gym/104090/problem/G
// Memory Limit: 1024 MB
// Time Limit: 3000 ms
#include<bits/stdc++.h>
using namespace std;
#define int unsigned long long
#define ll long long
#define fo(i,a,b) for(int i=a;i<=b;i++)
#define fr(i,a,b) for(int i=a;i>=b;i--)
#define py puts("YES")
#define pn puts("NO")
#define pt puts("")
#define pb push_back
#define wt(x) write(x),puts("")
#define wr(x) write(x) ,putchar(' ')
#define tx printf("fds")
#define mp make_pair
#define fi first
#define se second
inline int read(){
int x=0,k=1;
char ch=getchar();
while(ch<'0'||ch>'9'){
if(ch=='-') k=-1;
ch=getchar();
}
while(ch>='0'&&ch<='9'){
x=(x<<1)+(x<<3)+ch-48;
ch=getchar();
}
return x*k;
}
void write(int x){
if(x<0){
x=-x;
putchar('-');
}
if(x>9) write(x/10);
putchar(x%10+'0');
}
int power(int x,int y,int mod){
int num=1;
while(y){
if(y&1) num=(num*x)%mod;
x=x*x%mod;
y>>=1;
}
return num;
}
int mul(int x,int y,int mod){
int num=0;
while(y){
if(y&1) num=(num+x)%mod;
x=(x+x)%mod;
y>>=1;
}
return num;
}
const int N=1e6+7,mod=998244353;
int n,m,tot,tot1;
int head[N];
struct edge{
int to,next;
}e[N];
void add(int u,int v){
e[++tot]={v,head[u]};
head[u]=tot;
}
int vis[N],is_round[N],END,siz[N],st[N],top,f[N];
int p[10000001],prime[N];
void pre(){
for(int i=2;i<=10000000;i++){
if(!p[i]) prime[++tot1]=i;
for(int j=1;j<=tot1&&i*prime[j]<=n;j++){
p[i*prime[j]]=1;
if(i%prime[j]==0) break;
}
}
}
void dfs(int u,int fa){
if(vis[u]){
while(st[top]!=u){
is_round[st[top]]=1;
top--;
}
is_round[u]=1;
END=1;
return ;
}
vis[u]=1;
st[++top]=u;
for(int i=head[u];i;i=e[i].next){
int v=e[i].to;
if(v==fa) continue;
dfs(v,u);
if(END) return ;
while(st[top]!=u){
top--;
}
}
}
void dfs1(int u,int fa){
f[u]=1;
siz[u]=1;
for(int i=head[u];i;i=e[i].next){
int v=e[i].to;
if(is_round[v]||v==fa) continue;
dfs1(v,u);
siz[u]+=siz[v];
f[u]+=f[v]*prime[siz[v]];
}
}
void dfs2(int u,int fa){
st[++top]=u;
vis[u]=1;
for(int i=head[u];i;i=e[i].next){
int v=e[i].to;
if(v==fa||vis[v]||!is_round[v]) continue;
dfs2(v,u);
}
}
bool solve(){
fo(i,1,n) vis[i]=0,is_round[i]=0,siz[i]=0,f[i]=0;
END=0;
top=0;
dfs(1,0);
top=0;
fo(u,1,n){
if(is_round[u]) dfs1(u,0);
vis[u]=0;
}
fo(u,1,n){
if(is_round[u]){
dfs2(u,0);
break;
}
}
int fl=0,fll=0;
fo(i,2,top){
if(f[st[i]]!=f[st[i-1]]) fl=1;
}
// wr(top);
if(!fl){
return true;
}
if(top%2==1) return true;
fo(i,1,top){
if(i==1){
if(f[st[i]]!=f[st[top-1]]) fll=1;
}
else if(i==2){
if(f[st[i]]!=f[st[top]]) fll=1;
}
else{
if(f[st[i]]!=f[st[i-2]]) fll=1;
}
}
if(!fl) return true;
return false;
}
signed main(){
pre();
int tt=read();
while(tt--){
n=read();m=read();
fo(i,0,tot) head[i]=0;
tot=0;
fo(i,1,m){
int x=read(),y=read();
add(x,y);add(y,x);
}
if(m==n-1){
py;
continue;
}
if(m>n){
pn;
continue;
}
if(solve()) py;
else pn;
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 11ms
memory: 94044kb
input:
4 7 6 1 2 2 3 3 4 4 5 5 6 3 7 3 3 1 2 2 3 3 1 5 5 1 2 2 3 3 4 4 1 1 5 1 0
output:
YES YES NO YES
result:
ok 4 token(s): yes count is 3, no count is 1
Test #2:
score: -100
Wrong Answer
time: 11ms
memory: 94044kb
input:
33192 2 1 1 2 3 2 1 3 2 3 3 3 1 2 1 3 2 3 4 3 1 4 2 4 3 4 4 3 1 3 1 4 2 4 4 4 1 3 1 4 2 4 3 4 4 4 1 3 1 4 2 3 2 4 4 5 1 3 1 4 2 3 2 4 3 4 4 6 1 2 1 3 1 4 2 3 2 4 3 4 5 4 1 5 2 5 3 5 4 5 5 4 1 4 1 5 2 5 3 5 5 5 1 4 1 5 2 5 3 5 4 5 5 5 1 4 1 5 2 4 3 5 4 5 5 5 1 4 1 5 2 4 2 5 3 5 5 6 1 4 1 5 2 4 2 5 3 ...
output:
YES YES YES YES YES YES YES NO NO YES YES YES YES NO NO NO NO YES YES NO NO NO YES NO NO NO NO NO NO NO YES YES YES YES YES YES NO NO NO NO NO NO NO NO YES YES NO YES YES YES YES NO NO NO NO NO NO NO YES YES NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO YES NO NO NO NO NO NO NO NO NO NO NO NO NO N...
result:
wrong answer expected NO, found YES [6th token]