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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#103935 | #5668. Cell Nuclei Detection | Robert_JYH# | AC ✓ | 1246ms | 159772kb | C++17 | 4.1kb | 2023-05-07 21:26:27 | 2023-05-07 21:26:28 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10, M = 20 * (1e5);
class Maxflow
{
private:
int nedge = 1, p[2 * M], nex[2 * M], head[N], c[2 * M], cur[2 * M];
int dist[2 * N];
int S, T;
void Addedge(int a, int b, int v)
{
p[++nedge] = b;
nex[nedge] = head[a];
head[a] = nedge;
c[nedge] = v;
}
bool bfs()
{
queue<int> q;
for (int i = S; i <= T; i++)
dist[i] = -1;
dist[S] = 0;
q.push(S);
while (!q.empty())
{
int now = q.front();
q.pop();
for (int k = head[now]; k; k = nex[k])
if (dist[p[k]] == -1 && c[k] > 0)
{
dist[p[k]] = dist[now] + 1;
q.push(p[k]);
}
}
return dist[T] > -1;
}
int dfs(int x, int low)
{
if (x == T)
return low;
if (low == 0)
return 0;
int used = 0;
for (int &k = cur[x]; k; k = nex[k])
if (dist[p[k]] == dist[x] + 1 && c[k] > 0)
{
int a = dfs(p[k], min(c[k], low - used));
c[k] -= a;
c[k ^ 1] += a;
used += a;
if (low == used)
break;
}
if (used == 0)
dist[x] = -1;
return used;
}
public:
void givest(int s, int t)
{
S = s;
T = t;
}
void init()
{
memset(head, 0, sizeof(head));
nedge = 1;
}
void addedge(int a, int b, int v)
{
//cout << a << " " << b << " "<< v <<endl;
Addedge(a, b, v);
Addedge(b, a, 0);
}
int dinic()
{
int flow = 0;
while (bfs())
{
for (int i = S; i <= T; i++)
cur[i] = head[i];
flow += dfs(S, 1e9);
}
return flow;
}
};
Maxflow e;
vector<int> g[2001][2001];
struct node
{
int x1, y1, x2, y2;
} a[50010], b[50010];
int f[2001][2001], cnt;
bool check(node x, node y) // y 要占 x 的一半
{
cnt++;
int sum = 0, ss = 0;
for (int i = x.x1; i < x.x2; i++)
{
for (int j = x.y1; j < x.y2; j++)
{
f[i][j] = cnt;
sum++;
}
}
for (int i = y.x1; i < y.x2; i++)
{
for (int j = y.y1; j < y.y2; j++)
{
if (f[i][j] == cnt)
ss++;
}
}
if (ss * 2 >= sum)
return 1;
return 0;
}
void work()
{
e.init();
int m, n;
int s = 0, t;
scanf("%d%d", &m, &n); // m:true n:detect
t = m + n + 1;
e.givest(s,t);
for (int i =1;i<=m;i++)
{
e.addedge(s,i,1);
}
for (int i =1;i<=n;i++)
{
e.addedge(i+m,t,1);
}
for (int i = 0; i <= 2000; i++)
for (int j = 0; j <= 2000; j++)
g[i][j].clear();
for (int i = 1, x1, y1, x2, y2; i <= m; i++)
{
scanf("%d%d%d%d", &x1, &y1, &x2, &y2);
a[i] = node{x1, y1, x2, y2};
for (int x = x1; x < x2; x++)
for (int y = y1; y < y2; y++)
{
g[x][y].push_back(i);
}
}
for (int i = 1, x1, y1, x2, y2; i <= n; i++)
{
scanf("%d%d%d%d", &x1, &y1, &x2, &y2);
b[i] = node{x1, y1, x2, y2};
vector<int> q;
for (int x = x1; x < x2; x++)
for (int y = y1; y < y2; y++)
for (auto z : g[x][y])
{
q.push_back(z);
}
sort(q.begin(), q.end());
for (int j = 0; j < (int)q.size(); j++)
{
if (j == 0 || q[j] != q[j - 1])
{
if (check(a[q[j]], b[i]))
{
e.addedge(q[j], i + m, 1);
}
}
}
}
cout << e.dinic() << endl;
}
int main()
{
int T;
scanf("%d", &T);
while (T--)
{
work();
}
}
详细
Test #1:
score: 100
Accepted
time: 42ms
memory: 100232kb
input:
3 2 2 1 1 3 3 3 3 5 5 2 2 4 4 4 4 6 6 2 3 1 1 3 3 3 3 5 5 1 3 3 5 2 1 4 5 3 1 5 3 3 3 1 1 2 2 2 2 3 3 3 3 4 4 1 1 3 3 2 2 4 4 3 3 5 5
output:
0 1 3
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 42ms
memory: 100124kb
input:
3 2 2 1 1 3 3 3 3 5 5 2 2 4 4 4 4 6 6 2 3 1 1 3 3 3 3 5 5 1 3 3 5 2 1 4 5 3 1 5 3 3 3 1 1 2 2 2 2 3 3 3 3 4 4 1 1 3 3 2 2 4 4 3 3 5 5
output:
0 1 3
result:
ok 3 lines
Test #3:
score: 0
Accepted
time: 655ms
memory: 151532kb
input:
5 50000 50000 0 0 4 4 4 0 8 4 8 0 12 4 12 0 16 4 16 0 20 4 20 0 24 4 24 0 28 4 28 0 32 4 32 0 36 4 36 0 40 4 40 0 44 4 44 0 48 4 48 0 52 4 52 0 56 4 56 0 60 4 60 0 64 4 64 0 68 4 68 0 72 4 72 0 76 4 76 0 80 4 80 0 84 4 84 0 88 4 88 0 92 4 92 0 96 4 96 0 100 4 100 0 104 4 104 0 108 4 108 0 112 4 112 ...
output:
50000 50000 0 50000 3150
result:
ok 5 lines
Test #4:
score: 0
Accepted
time: 418ms
memory: 159772kb
input:
5 50000 50000 0 0 1 1 1 0 2 1 2 0 3 1 3 0 4 1 4 0 5 1 5 0 6 1 6 0 7 1 7 0 8 1 8 0 9 1 9 0 10 1 10 0 11 1 11 0 12 1 12 0 13 1 13 0 14 1 14 0 15 1 15 0 16 1 16 0 17 1 17 0 18 1 18 0 19 1 19 0 20 1 20 0 21 1 21 0 22 1 22 0 23 1 23 0 24 1 24 0 25 1 25 0 26 1 26 0 27 1 27 0 28 1 28 0 29 1 29 0 30 1 30 0 ...
output:
50000 25050 12500 16000 8000
result:
ok 5 lines
Test #5:
score: 0
Accepted
time: 366ms
memory: 128920kb
input:
5 50000 50000 0 0 2 4 4 0 7 1 8 0 10 1 12 0 15 3 16 0 19 1 20 0 22 2 24 0 26 4 28 0 30 4 32 0 36 3 36 0 40 1 40 0 44 1 44 0 47 2 48 0 49 3 52 0 54 1 56 0 59 4 60 0 64 3 64 0 68 3 68 0 70 1 72 0 76 4 76 0 80 3 80 0 84 4 84 0 87 2 88 0 90 1 92 0 94 4 96 0 98 1 100 0 104 1 104 0 107 2 108 0 110 4 112 0...
output:
10594 10779 10618 10381 10779
result:
ok 5 lines
Test #6:
score: 0
Accepted
time: 1246ms
memory: 122668kb
input:
5 50000 50000 0 0 4 4 1 0 5 4 2 0 6 4 3 0 7 4 4 0 8 4 5 0 9 4 6 0 10 4 7 0 11 4 8 0 12 4 9 0 13 4 10 0 14 4 11 0 15 4 12 0 16 4 13 0 17 4 14 0 18 4 15 0 19 4 16 0 20 4 17 0 21 4 18 0 22 4 19 0 23 4 20 0 24 4 21 0 25 4 22 0 26 4 23 0 27 4 24 0 28 4 25 0 29 4 26 0 30 4 27 0 31 4 28 0 32 4 29 0 33 4 30...
output:
50000 50000 50000 50000 49600
result:
ok 5 lines
Test #7:
score: 0
Accepted
time: 32ms
memory: 100120kb
input:
1 4 4 1 1 3 3 2 1 4 3 1 2 3 4 2 2 4 4 2 1 4 3 3 2 5 4 1 2 3 4 2 3 4 5
output:
3
result:
ok single line: '3'