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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#103718#6400. Game: CelestehitonanodeWA 357ms3948kbC++1713.9kb2023-05-07 13:13:172023-05-07 13:13:17

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你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-05-07 13:13:17]
  • 评测
  • 测评结果：WA
  • 用时：357ms
  • 内存：3948kb
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  • [2023-05-07 13:13:17]
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answer

#include <algorithm>
#include <array>
#include <bitset>
#include <cassert>
#include <chrono>
#include <cmath>
#include <complex>
#include <deque>
#include <forward_list>
#include <fstream>
#include <functional>
#include <iomanip>
#include <ios>
#include <iostream>
#include <limits>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <tuple>
#include <type_traits>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
using lint = long long;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(nullptr), ios::sync_with_stdio(false), cout << fixed << setprecision(20); }; } fast_ios_;
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template <typename T, typename V>
void ndarray(vector<T>& vec, const V& val, int len) { vec.assign(len, val); }
template <typename T, typename V, typename... Args> void ndarray(vector<T>& vec, const V& val, int len, Args... args) { vec.resize(len), for_each(begin(vec), end(vec), [&](T& v) { ndarray(v, val, args...); }); }
template <typename T> bool chmax(T &m, const T q) { return m < q ? (m = q, true) : false; }
template <typename T> bool chmin(T &m, const T q) { return m > q ? (m = q, true) : false; }
const std::vector<std::pair<int, int>> grid_dxs{{1, 0}, {-1, 0}, {0, 1}, {0, -1}};
int floor_lg(long long x) { return x <= 0 ? -1 : 63 - __builtin_clzll(x); }
template <class T1, class T2> T1 floor_div(T1 num, T2 den) { return (num > 0 ? num / den : -((-num + den - 1) / den)); }
template <class T1, class T2> std::pair<T1, T2> operator+(const std::pair<T1, T2> &l, const std::pair<T1, T2> &r) { return std::make_pair(l.first + r.first, l.second + r.second); }
template <class T1, class T2> std::pair<T1, T2> operator-(const std::pair<T1, T2> &l, const std::pair<T1, T2> &r) { return std::make_pair(l.first - r.first, l.second - r.second); }
template <class T> std::vector<T> sort_unique(std::vector<T> vec) { sort(vec.begin(), vec.end()), vec.erase(unique(vec.begin(), vec.end()), vec.end()); return vec; }
template <class T> int arglb(const std::vector<T> &v, const T &x) { return std::distance(v.begin(), std::lower_bound(v.begin(), v.end(), x)); }
template <class T> int argub(const std::vector<T> &v, const T &x) { return std::distance(v.begin(), std::upper_bound(v.begin(), v.end(), x)); }
template <class IStream, class T> IStream &operator>>(IStream &is, std::vector<T> &vec) { for (auto &v : vec) is >> v; return is; }

template <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec);
template <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr);
template <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec);
template <class OStream, class T, class U> OStream &operator<<(OStream &os, const pair<T, U> &pa);
template <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec);
template <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec);
template <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec);
template <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec);
template <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa);
template <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp);
template <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp);
template <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl);

template <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }
template <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr) { os << '['; for (auto v : arr) os << v << ','; os << ']'; return os; }
template <class... T> std::istream &operator>>(std::istream &is, std::tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }
template <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl) { os << '('; std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os << ')'; }
template <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec) { os << "deq["; for (auto v : vec) os << v << ','; os << ']'; return os; }
template <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa) { return os << '(' << pa.first << ',' << pa.second << ')'; }
template <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
template <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
#ifdef HITONANODE_LOCAL
const string COLOR_RESET = "\033[0m", BRIGHT_GREEN = "\033[1;32m", BRIGHT_RED = "\033[1;31m", BRIGHT_CYAN = "\033[1;36m", NORMAL_CROSSED = "\033[0;9;37m", RED_BACKGROUND = "\033[1;41m", NORMAL_FAINT = "\033[0;2m";
#define dbg(x) std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << " = " << (x) << NORMAL_FAINT << " (L" << __LINE__ << ") " << __FILE__ << COLOR_RESET << std::endl
#define dbgif(cond, x) ((cond) ? std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << " = " << (x) << NORMAL_FAINT << " (L" << __LINE__ << ") " << __FILE__ << COLOR_RESET << std::endl : std::cerr)
#else
#define dbg(x) ((void)0)
#define dbgif(cond, x) ((void)0)
#endif


// Sliding-Window Aggregation based queue
// - `std::queue`-like data structure with monoid operation
// - Each operation is amortized O(1)
// - Verification:
// https://www.hackerrank.com/contests/tsg-live-4-programming-contest/challenges/tsg-live-4-procon-lcm-interval/submissions/code/1317888077
// - Reference:
// https://github.com/NiMiLib/NoshiMochiLibrary/blob/queue_aggregation/lib/data_structure/sequence/queue_aggregation.hpp
template <typename T_VAL, typename T_PROD, T_PROD (*val2prod)(T_VAL), T_PROD (*op)(T_PROD, T_PROD)>
struct swag_queue {
    std::stack<std::pair<T_VAL, T_PROD>, std::vector<std::pair<T_VAL, T_PROD>>> front_stack,
        back_stack;

    swag_queue() {}
    bool empty() const { return front_stack.empty() and back_stack.empty(); }
    int size() const { return front_stack.size() + back_stack.size(); }
    T_PROD fold_all() const {
        if (empty()) {
            exit(1);
            // return ID_;
        } else if (front_stack.empty())
            return back_stack.top().second;
        else if (back_stack.empty())
            return front_stack.top().second;
        else
            return op(front_stack.top().second, back_stack.top().second);
    }
    void push(const T_VAL &x) {
        if (back_stack.empty())
            back_stack.emplace(x, val2prod(x));
        else
            back_stack.emplace(x, op(back_stack.top().second, val2prod(x)));
    }
    const T_VAL &front() {
        if (front_stack.empty()) {
            front_stack.emplace(back_stack.top().first, val2prod(back_stack.top().first));
            back_stack.pop();
            while (!back_stack.empty()) {
                T_VAL t = back_stack.top().first;
                front_stack.emplace(t, op(val2prod(t), front_stack.top().second));
                back_stack.pop();
            }
        }
        return front_stack.top().first;
    }

    T_VAL pop() {
        T_VAL t = front();
        front_stack.pop();
        return t;
    }
};


template <class S, S (*op)(S, S), S (*e)()> struct persistent_segtree {
    struct Root {
        int id;
    };

    explicit persistent_segtree(int n) : persistent_segtree(std::vector<S>(n, e())) {}
    explicit persistent_segtree(const std::vector<S> &v) : _n(int(v.size())) {
        lg = 1;
        while ((1 << lg) < _n) ++lg;
        size = 1 << lg;

        d = std::vector<S>(2 * size, e());
        left = right = parent = std::vector<int>(2 * size, -1);

        for (int i = 0; i < _n; i++) d[size + i] = v[i];
        for (int i = size - 1; i >= 1; i--) {
            left.at(i) = 2 * i;
            right.at(i) = 2 * i + 1;
            parent.at(2 * i) = parent.at(2 * i + 1) = i;
            d.at(i) = op(d.at(2 * i), d.at(2 * i + 1));
        }
    }


    Root set(const Root &root, int p, const S &x) {
        assert(0 <= p && p < _n);

        int cur = root.id;
        for (int d = lg - 1; d >= 0; --d) cur = ((p >> d) & 1) ? right.at(cur) : left.at(cur);

        int copy_cur = d.size();
        d.push_back(x);
        left.push_back(-1);
        right.push_back(-1);
        parent.push_back(-1);

        for (int i = 1; i <= lg; i++) {
            const int par = parent.at(cur);
            const int copy_par = d.size();
            left.push_back(left.at(par) == cur ? copy_cur : left.at(par));
            right.push_back(right.at(par) == cur ? copy_cur : right.at(par));
            d.push_back(op(d.at(left.back()), d.at(right.back())));
            parent.push_back(-1);
            parent.at(copy_cur) = copy_par;

            cur = par;
            copy_cur = copy_par;
        }

        return Root{copy_cur};
    }

    S prod(const Root &root, int l, int r) const {
        assert(0 <= l && l <= r && r <= _n);

        auto rec = [&](auto &&self, int i, int lo, int hi) -> S {
            if (r <= lo or hi <= l) return e();
            if (l <= lo and hi <= r) return d.at(i);

            return op(self(self, left.at(i), lo, (lo + hi) / 2), self(self, right.at(i), (lo + hi) / 2, hi));
        };

        return rec(rec, root.id, 0, size);
    }

    S all_prod(const Root &root) const { return d.at(root.id); }

    Root get_root() const { return {1}; }

// private:
    int _n, size, lg;
    std::vector<S> d;
    std::vector<int> left, right, parent;
};

struct rand_int_ {
    using lint = long long;
    std::mt19937 mt;
    rand_int_() : mt(std::chrono::steady_clock::now().time_since_epoch().count()) {}
    lint operator()(lint x) { return this->operator()(0, x); } // [0, x)
    lint operator()(lint l, lint r) {
        std::uniform_int_distribution<lint> d(l, r - 1);
        return d(mt);
    }
} rnd;



using S = pair<lint, unsigned long long>;
S op(S l, S r) { return l + r; }
S e() { return {0, 0}; }
persistent_segtree<S, op, e> tree(0);

using swag_val = pair<int, persistent_segtree<S, op, e>::Root>;
swag_val val2prod(swag_val x) { return x; }
swag_val swag_op(swag_val l, swag_val r) {
    int i = l.second.id, j = r.second.id;

    if (tree.d.at(i) == tree.d.at(j)) return l;

    for (int d = 0; d < tree.lg; ++d) {
        if (const int il = tree.left.at(i), jl = tree.left.at(j); tree.d.at(il) != tree.d.at(jl)) {
            i = il;
            j = jl;
        } else {
            i = tree.right.at(i);
            j = tree.right.at(j);
        }
    }

    return tree.d.at(i) > tree.d.at(j) ? l : r;
}

vector<int> solve() {
    int N, L, R;
    cin >> N >> L >> R;
    vector<int> X(N);
    cin >> X;
    vector<int> A(N);
    cin >> A;
    REP(i, N) A.at(i) = N - A.at(i);
    dbg(make_tuple(L, R, X, A));

    tree = persistent_segtree<S, op, e>(N);
    vector<unsigned long long> hash(N);
    for (auto &x : hash) x = rnd(0, 1LL << 60);

    auto root0 = tree.get_root();

    swag_queue<swag_val, swag_val, val2prod, swag_op> swag;

    queue<swag_val> roots;
    roots.emplace(0, tree.set(root0, A.at(0), {1, hash.at(A.at(0))}));

    vector<int> prv(N, -1);

    FOR(i, 1, N) {
        while (roots.size() and X.at(roots.front().first) <= X.at(i) - L) {
            swag.push(roots.front());
            roots.pop();
        }
        while (swag.size() and X.at(swag.front().first) < X.at(i) - R) swag.pop();

        if (swag.size()) {
            auto [j, root] = swag.fold_all();
            prv.at(i) = j;
            auto f = tree.prod(root, A.at(i), A.at(i) + 1);
            f.first++;
            f.second += hash.at(A.at(i));
            auto new_root = tree.set(root, A.at(i), f);
            roots.emplace(i, new_root);
        }
    }

    if (prv.back() < 0) return {};

    vector<int> ret;
    for (int cur = N - 1; cur >= 0; cur = prv.at(cur)) ret.push_back(N - A.at(cur));
    sort(ret.rbegin(), ret.rend());
    return ret;
}

int main() {
    int T;
    cin >> T;
    while (T--) {
        auto ret = solve();
        if (ret.empty()) {
            cout << "-1\n";
        } else {
            cout << ret.size() << '\n';
            REP(i, ret.size()) cout << ret.at(i) << (i + 1 == int(ret.size()) ? '\n' : ' ');
        }
    }
}
源文件, 语言: C++17

详细

Test #1:

score: 100
Accepted
time: 2ms
memory: 3444kb

input:

2
5 2 3
1 2 3 4 5
5 2 3 1 4
3 1 2
1 4 7
3 3 3

output:

3
5 4 3
-1

result:

ok 3 lines

Test #2:

score: -100
Wrong Answer
time: 357ms
memory: 3948kb

input:

10000
57 8 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57
11 16 7 7 10 13 9 14 10 1 12 4 8 13 3 20 16 7 16 19 20 8 19 7 16 6 17 13 7 19 17 11 12 17 6 3 7 8 14 2 4 15 5 18 16 7 20 9 1...

output:

7
20 20 19 14 12 11 3
-1
5
6 5 3 2 1
-1
50
20 20 20 20 20 20 20 20 19 19 19 19 19 19 19 19 19 19 19 18 18 18 17 17 17 17 17 17 16 16 16 16 15 15 15 15 15 15 15 14 14 14 13 13 12 12 12 11 8 7
18
20 20 20 19 19 19 19 19 19 18 18 16 16 16 13 12 8 6
-1
110
20 20 20 20 20 20 20 20 20 20 20 20 19 19 19 19...

result:

wrong answer 4th lines differ - expected: '6', found: '5'
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