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QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#100793#4432. Jungle TrailYanagi_Origami#AC ✓369ms70220kbC++203.9kb2023-04-28 09:05:572023-04-28 09:06:00

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-04-28 09:06:00]
  • 评测
  • 测评结果:AC
  • 用时:369ms
  • 内存:70220kb
  • [2023-04-28 09:05:57]
  • 提交

answer

#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstring>
#include <vector>
#include <cstring>
using namespace std;
#define rep(i,a,b) for(int i=a;i<=b;i++)
#define per(i,a,b) for(int i=a;i>=b;i--)
const int N=2005;
char mp[N][N];
int n,m,k,f[N][N][2][2];
vector<char>ans1,ans2,ans3;
void getans(int x,int y,int u,int v){
    if(x==1&&y==1) return ;
    //printf("#%d %d %d %d\n",x,y,u,v);
    if(f[x][y][u][v]==1){
        rep(i,0,1){
            if(f[x][y-1][i][v]){
                getans(x,y-1,i,v);
                ans2.push_back(i?'T':'N');
                ans3.push_back('P');
                break;
            }
        }
    }else{
        rep(i,0,1){
            if(f[x-1][y][u][i]){
                getans(x-1,y,u,i);
                ans1.push_back(i?'T':'N');
                ans3.push_back('D');
                break;
            }
        }
    }
}
void solve(){
    //memset(f,0,sizeof(f));
    scanf("%d%d",&n,&m);
    rep(i,1,n) rep(j,1,m) rep(_1,0,1) rep(_2,0,1) f[i][j][_1][_2]=0;
    ans1.clear(); ans2.clear(); ans3.clear();
    rep(i,1,n){
        scanf("%s",mp[i]+1);
    }
    if(mp[1][1]=='.'){
        f[1][1][0][0] = 1;
        f[1][1][0][1] = 1;
        f[1][1][1][0] = 1;
        f[1][1][1][1] = 1;
    }
    if(mp[1][1]=='O'){
        f[1][1][0][0] = 1;
        f[1][1][1][1] = 1;
    }
    if(mp[1][1]=='@'){
        f[1][1][0][1] = 1;
        f[1][1][1][0] = 1;
    }
    rep(i,1,n){
        rep(j,1,m){
            if(j<m&&mp[i][j+1]!='#'){//1 => j+1 2=>i+1
                if(mp[i][j+1]=='.'){
                    if(f[i][j][0][0]||f[i][j][1][0])
                        f[i][j+1][0][0] = 1,
                        f[i][j+1][1][0] = 1;
                    if(f[i][j][0][1]||f[i][j][1][1])
                        f[i][j+1][0][1] = 1,
                        f[i][j+1][1][1] = 1;
                }else{
                    if(mp[i][j+1]=='O'){
                        if(f[i][j][0][0]||f[i][j][1][0])
                            f[i][j+1][0][0] = 1;
                        if(f[i][j][0][1]||f[i][j][1][1])
                            f[i][j+1][1][1] = 1;
                    }else{
                        if(f[i][j][0][0]||f[i][j][1][0])
                            f[i][j+1][1][0] = 1;
                        if(f[i][j][0][1]||f[i][j][1][1])
                            f[i][j+1][0][1] = 1;
                    }
                }
            }

            if(i<n&&mp[i+1][j]!='#'){
                if(mp[i+1][j]=='.'){
                    if(f[i][j][0][0]||f[i][j][0][1])
                        f[i+1][j][0][0] = 2,
                        f[i+1][j][0][1] = 2;
                    if(f[i][j][1][0]||f[i][j][1][1])
                        f[i+1][j][1][0] = 2,
                        f[i+1][j][1][1] = 2;
                }else{
                    if(mp[i+1][j]=='O'){
                        if(f[i][j][0][0]||f[i][j][0][1])
                            f[i+1][j][0][0] = 2;
                        if(f[i][j][1][0]||f[i][j][1][1])
                            f[i+1][j][1][1] = 2;
                    }else{
                        if(f[i][j][0][0]||f[i][j][0][1])
                            f[i+1][j][0][1] = 2;
                        if(f[i][j][1][0]||f[i][j][1][1])
                            f[i+1][j][1][0] = 2;
                    }
                }
            }

        }
    }
    rep(i,0,1) rep(j,0,1) if(f[n][m][i][j]){
        puts("TAK");
        getans(n,m,i,j);
        ans2.push_back(i?'T':'N');
        ans1.push_back(j?'T':'N');
        for(auto v:ans1) putchar(v); puts("");
        for(auto v:ans2) putchar(v); puts("");
        for(auto v:ans3) putchar(v); puts("");
        return ;
    }
    puts("NIE");
}
int main(){
    int T;
    scanf("%d",&T);
    while(T--) solve();
    return 0;
}

/*
2
4 5
..#..
@@O@@
##@#O
..@.@
4 5
..#..
@@O@@
##@#O
..@.@
*/

详细

Test #1:

score: 100
Accepted
time: 369ms
memory: 70220kb

input:

486
4 5
..#..
@@O@@
##@#O
..@.@
2 2
OO
OO
2 2
@@
@@
2 2
@@
#@
2 2
@O
#@
2 2
@@
OO
2 2
O#
@O
2 2
@#
#@
2 2
@.
.@
2 2
@#
.O
2 2
OO
.O
10 10
@O@O#O@@@#
OO#@#@@#OO
#@#@#O##O@
OO##@@O#@O
O##@@#@O#@
OO@OO@@@O@
@O#@#@O#@O
@OOOOO@##.
O@OOO##O@@
OO@@OOOO#@
10 10
@@#OOO#O@@
#@@OO@@.O@
#.O@@O#@@O
OO@@#O@#O@
.#...

output:

TAK
NNTT
TTNNN
DPPDDPP
TAK
NN
NN
DP
TAK
TT
NN
DP
TAK
TT
NN
PD
TAK
NT
TN
PD
TAK
TN
NN
DP
TAK
TN
TN
DP
NIE
TAK
TT
NN
DP
TAK
TN
NN
DP
TAK
NN
NN
DP
NIE
TAK
TTNNTTTTNT
NNTTNNTTNN
PDDDPPDDDDPPDDPPPP
TAK
NTTTNTNNNN
NTTTNTNTTN
DDDDDPDDDPPPPPDPPP
TAK
TNTNTNNNTN
TTNNNNNTTN
DDDPPDPDDDDDPPPPPP
TAK
TNTNTTTNTN
TT...

result:

ok ac (486 test cases)

Extra Test:

score: 0
Extra Test Passed